i have a small problem. I use two mysql queries for getting data.
First i want to get IDs from groups
$sqlGoups = "SELECT * from `groups` WHERE `Date`='$TodayDate' ";
$result = $conn->query($sqlGoups);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$IDgroups = $row["ID"];
With that, I'll get those IDs, for example 5, 7, 12, 15, 22
I want to put them all in the next mysql query:
$sqlNext = "SELECT * FROM `orders` WHERE ID = '$IDgroups' ORDER BY `ID` ASC ";
$result = $conn->query($sqlNext);
When I do this, I get the result only for the first ID (5). And I want for each
I can not INNER JOIN tables because I use this in next query.
I tried with foreach loop, but no effect.
Try this code
SELECT * FROM `orders`
WHERE ID REGEXP CONCAT('(^|,)(', REPLACE('$IDgroups', ',', '|'), ')(,|$)')
ORDER BY `ID` ASC
Just like #Elanochecer commented the best bet should be a JOIN statement, but if you wish to go through your route, you could use the IN and provide the IDs as comma separated string, your query should look similar to the one below:
...
$sqlNext = "SELECT * FROM orders WHERE ID IN ('$IDgroups') ORDER BY ID ASC ";
...
Also, confirm if $IDgroups is in the format 1,2,3,4
If you provide the schema I could come up with a workable JOIN statement for you, preferably you can create a repo with the schema
Related
I wanted to fetch data from MySQL with PHP when a user inputs something. I have this code.
$query = "SELECT * FROM mealplans WHERE plantitle LIKE '%$inputText%' AND `STATUS` = 1 OR plantitle LIKE '%$inputText%' AND userid = '$userid' GROUP BY plantitle, userid";
$result = mysqli_query($con, $query);
It works fine however, it fetches the oldest or first data from the group. How do I select the newest data?
I've search and found possible solutions by using FROM, JOIN, IN, etc. However, I do not know how to use them since I only know the basics. Hopefully someone could explain one solution for me.
There is a simple solution that you can do.
You can order your data to DESC order. I'm sure that you have an id(primary key) in your table.You just have to order all your datas' to DESC order of ids .So that your last inserted data set will be the one to be fetched since it's on the top.
change your query to: (add your primary key(in the following query i have added it as id) in the ORDER BY syntax)
$query = "SELECT * FROM mealplans WHERE plantitle LIKE '%$inputText%' AND `STATUS` = 1 OR plantitle LIKE '%$inputText%' AND userid = '$userid' GROUP BY plantitle, userid ORDER BY `ID` DESC"
Just add a condition in your query which only retrieves the row having the greatest id.
Find out the id first and then you can use the same query for that id:
SELECT MAX(id) FROM mealplans WHERE plantitle LIKE '%$inputText%' AND `STATUS` = 1 OR plantitle LIKE '%$inputText%' AND userid = '$userid' GROUP BY plantitle, userid
After getting the id and storing it in a variable (say $temp):
SELECT * from mealplans where `id` = $temp
I'm developing a website using HTML, PHP and MySQL to access a database. On one page I present a table with data from that database. This is some of the code I'm using:
$sql1 = "SELECT * FROM MyTable ORDER BY ID ASC";
$rs1 = mysqli_query($link,$sql1);
(...)
while($row1 = mysqli_fetch_assoc($rs1)) {
echo "<tr><td>".$row1['ID']."</td><td>".$row1['Field1']."</td><td></td><td>".$row1['Field2']."</td><td>".$row1['Field3']."</td></tr>\n" ;
}
Notice the empty <td></td>? That's because I want to have there the number of time a given ID appears on two other tables (there are foreign keys involved, obviously). I have sorted out the code I need for that:
$sql2 = "SELECT (SELECT COUNT(*) FROM MyTable2 WHERE ID2=$row1['ID'])+(SELECT COUNT(*) FROM MyTable3 WHERE ID2=$row1['ID']) AS total";
However, I'm struggling with figuring out a way to add this result to the other table. Any help?
try with this.. it inserts the total to an table after selecting the count.
"INSERT INTO total_table (total)
SELECT (SELECT COUNT(*) FROM MyTable2 WHERE ID2=$row1['ID'])+(SELECT COUNT(*) FROM MyTable3 WHERE ID2=$row1['ID']) AS total
WHERE cid = 2"
how would i go about ordering by a value that is not in the table where i am selecting from, in this instance the value $count1 is not in the table search.
count has the same identifying id as that of the thing it is being reffered to in the other table, this is where count1 is grabbed
$q = $db->prepare("SELECT COUNT(rating) FROM ratings WHERE id='$id' AND rating = 'd'");
$q->execute();
$count1 = $q->fetchColumn();
$query = "SELECT * FROM search WHERE title LIKE '$each' ORDER BY '$count1'"
$query = $db->prepare($query);
$query->execute();
that is from ratings, how would i go about ordering the entries like that, so that they are based off the number of count1 and are decided, i might have to implement something like
$query = "SELECT * FROM search WHERE title LIKE '$each' AND id = '$id' ORDER BY '$count1'"
$query = $db->prepare($query);
$query->execute();
Possible Duplicate: Mysql order by specific ID values
Same thing here, you'll just output your $count1as a comma separated string and add it in the SQL query as ORDER BY FIELD(COUNT,___comma_sep_string___)
ratings is a table, not a database. You can join tables or use subqueries to get the desired result, without having to make multiple queries.
You haven't described how the FOREIGN_KEY is set up in the ratings table, but assuming you have something ratings.search_id, this should work:
SELECT search.*, (SELECT COUNT(rating)
FROM ratings
WHERE ratings.search_id = search.id
AND rating = 'd'
) AS rating_count
FROM search
WHERE title LIKE '$each'
ORDER BY rating_count
I want to echo data from two tables to one variable. Here is the code that I have so far:
$sqlCommand = "SELECT * FROM News ORDER BY id DESC LIMIT 10";
$sqlCommand3 = "SELECT * FROM Users ORDER BY id";
$query = mysql_query($sqlCommand) or die(mysql_error());
$query3 = mysql_query($sqlCommand3) or die(mysql_error());
$count = mysql_num_rows($query);
if($count > 1) {
$News .= "";
// How do I add the query3 here?? along side the already existing one
while($row = mysql_fetch_array($query)) {
// some of the $row here are from query one and some are from query 3
$News .= "<div class=\"news-post\"> <img src=\"".$row['author']."\"><p>".$row['author']."</p> <h2>".$row['title']."</h2></div>";
} // close while
This isn't the right way to go about it, instead try using a SQL join. In this case, you'll want a unique FULL OUTER JOIN.
SELECT * FROM News
FULL OUTER JOIN USERS
ON News.id = Users.id
WHERE News.id IS NULL
OR Users.id IS NULL;
This should give you all rows containing all columns from both tables. Depending on the actual relationship, you may want some different kind of join (refer to previous link)..but this seems like what you were trying to accomplish in your example.
Warning: you are using the mysql_* extension which has been deprecated in PHP 5.5. Please use either mysqli_* or PDO.
Your User table should be linked to the News table by a oneToMany association.
So a user writes a news and a new is written by a user.
And you need to add a join in your SQL query.
$sql = 'SELECT u.username, n.* FROM News n JOIN User u ON n.user_id = u.id';
Then, you while only have to execute one SQL statement and display the result in you HTML.
Have look to this website.
Hey guys, I created a list for fixtures.
$result = mysql_query("SELECT date FROM ".TBL_FIXTURES." WHERE compname = '$comp_name' GROUP BY date");
$i = 1;
$d = "Start";
while ($row = mysql_fetch_assoc($result))
{
$odate = $row['date'];
$date=date("F j Y", $row['date']);
echo "<p>Fixture $i - $d to $date</p>";
}
As you can see from the query, the date is displayed from the fixtures table.
The way my system works is that when a fixture is "played", it is removed from this table. Therefore when the entire round of fixtures are complete, there wont be any dates for that round in this table. They will be in another table.
Is there anyway I can run an other query for dates at the same time, and display only dates from the fixtures table if there isnt a date in the results table?
"SELECT * FROM ".TBL_CONF_RESULTS."
WHERE compid = '$_GET[id]' && type2 = '2' ORDER BY date"
That would be the second query!
EDIT FROM HERE ONWARDS...
Is there anyway I can select the date from two tables and then only use one if there are matches. Then use the rows of dates (GROUPED BY) to populate my query? Is that possible?
It sounds like you want to UNION the two result sets, akin to the following:
SELECT f.date FROM tbl_fixtures f
WHERE f.compname = '$comp_name'
UNION SELECT r.date FROM tbl_conf_results r
WHERE r.compid = '$_GET[id]' AND r.type2 = '2'
GROUP BY date
This should select f.date and add rows from r.date that aren't already in the result set (at least this is the behaviour with T-SQL). Apparently it may not scale well, but there are many blogs on that (search: UNION T-SQL).
From the notes on this page:
//performs the query
$result = mysql_query(...);
$num_rows = mysql_num_rows($result);
//if query result is empty, returns NULL, otherwise,
//returns an array containing the selected fields and their values
if($num_rows == NULL)
{
// Do the other query
}
else
{
// Do your stuff as now
}
WHERE compid = '$_GET[id]' presents an oportunity for SQL Injection.
Are TBL_FIXTURES and TBL_CONF_RESULTS supposed to read $TBL_FIXTURES and $TBL_CONF_RESULTS?
ChrisF has the solution!
One other thing you might think about is whether it is necessary to do a delete and move to another table. A common way to solve this type of challenge is to include a status field for each record, then rather than just querying for "all" you query for all where status = "x". For example, 1 might be "staging", 2 might be "in use", 3 might be "used" or "archived" In your example, rather than deleting the field and "moving" the record to another table (which would also have to happen in the foreach loop, one would assume) you could simply update the status field to the next status.
So, you'd eliminate the need for an additional table, remove one additional database hit per record, and theoretically improve the performance of your application.
Seems like what you want is a UNION query.
$q1 = "SELECT DISTINCT date FROM ".TBL_FIXTURES." WHERE compname = '$comp_name'";
$q2 = "SELECT DISTINCT date FROM ".TBL_CONF_RESULTS.
"WHERE compid = '$_GET[id]' && type2 = '2'";
$q = "($q1) UNION DISTINCT ($q2) ORDER BY date";