Inside users table I have a json column named "agencies" that stores data as a simple array like this:
[
"0eb2edf0-50cb-44ff-a0a6-b2a104a9dc12",
"f7c748d4-8718-441e-aa69-91b890ead5ed"
],
the above is valid json. When I try to select all users that contain 0eb2edf0-50cb-44ff-a0a6-b2a104a9dc12 I get null
Is my query correct?
$users = User::whereRaw('JSON_CONTAINS(agencies->"$[*]", "0eb2edf0-50cb-44ff-a0a6-b2a104a9dc12")')->get();
is the below correct way to do write JSON select query conbsidering how I store uuids as an array inside agencies column which is defined as json?
'JSON_CONTAINS(agencies->"$[*]", "0eb2edf0-50cb-44ff-a0a6-b2a104a9dc12"
I got the idea for above select from reading: Making a Laravel 5.4 query on a JSON field containing a JSON array
but the solution in that post is different then what I am trying to do and my modification to it does not give me back any users, but instead I allways get null back.
I believe that's what you want:
$users = User::whereRaw('JSON_CONTAINS(agencies, ?)', ['0eb2edf0-50cb-44ff-a0a6-b2a104a9dc12'])->get();
It will also soon be supported with the query builder. See PR
MySQL expects a JSON string:
$users = User::whereRaw('JSON_CONTAINS(agencies, ?)',
['"0eb2edf0-50cb-44ff-a0a6-b2a104a9dc12"'])->get();
$users = User::whereRaw('JSON_CONTAINS(agencies, ?)',
[json_encode('0eb2edf0-50cb-44ff-a0a6-b2a104a9dc12')])->get();
Related
I am having trouble querying a json column.
Previously my code was
$query->whereIn('user', $users);
Now i have changed the db type to JSON column and am trying to modify the code for the new version.
In RAW MYSQL this works
JSON_CONTAINS(user, '"tom","Bill"')
But when i put it in eloquent / php it keeps failing or returning noting. Here i am passing in an array of Users, previous using an WhereIn which works in raw SQL
$leads->whereRaw("JSON_CONTAINS(user, '"$users"')")
Any idea how to make it work in Laravel so i can pass in an array of strings, query them against the json column which contains an array of strings too.
My Json colum has data like so
["Paul", "Tom", "Bob"]
MySQL expects a JSON string:
$leads->whereRaw('JSON_CONTAINS(user, ?)', [json_encode($users)])
In Laravel 5.6.24 you can use whereJsonContains():
$leads->whereJsonContains('user', $users)
If $users is array of names then you should iterate over it and add orWhereRaw condition, note that orWhereRaw can accept an array of parameter:
$users = ["Tom", "Bob"];
foreach( $users as $user) {
$leads->orWhereRaw("JSON_CONTAINS(user, ?)", [$user]);
}
$leads = $leads->get();
Database table SITE has many columns. One of them is site_id. I need all the site_ids as an array since it has to be fed to a method which accepts only a string array.
What I tried so far is:
$sites = DB::select('select site_id from site_tab');
$sites_arr = $sites->toArray();
But this doesn't produce the result I want. I need $sites_arr to be like ['A','B','C',...]
Please suggest a way to get this done. A solution based on Eloquent is also OK for me.
Thanks
Try this:
DB::table('site_tab')->pluck('site_id')->toArray();
reference pluck
referen toArray
If you open a manual, you will see that
The select method will always return an array of results
So, there's no need to use ->toArray(), as result is already an array.
To get values as array of names you can do:
$site_ids = DB::table('site_tab')->pluck('site_id');
Using ->toArray() here is optional, as you can iterate over $site_ids (which is a Collection) with a foreach too.
Hello I would like to know is it possible to get column value as string. Instead of array in array:
Current query: Number::limit('1000')->get(['number'])->toArray()
The result at the moment is this:
Preferable result:
Before your toArray() call, add pluck('number'):
$result = Number::limit('1000')->get(['number'])->pluck('number')->toArray();
That's it! This will pluck just the number attributes from your result collection, and give you a single-level array.
The reason this works, is because you are getting a Collection back from get():
All multi-result sets returned by Eloquent are an instance of the Illuminate\Database\Eloquent\Collection object, including results retrieved via the get method or accessed via a relationship.
And the pluck method:
https://laravel.com/docs/5.1/collections#method-pluck
Update
Another, even more succinct method provided by #wunch in the comments:
$result = Number::limit('1000')->lists('number')->toArray();
In CakePHP3, there is a ORM that helps with building queries.
From the documentation, I can see that
$query = $articles->find(); // build a query that has not run yet
$query->where(['id' => 1]); // Return the same query object
So in this case, I want the string
WHERE `articles`.`id` = 1
After much googling, I found out that there is a way to return just the where clause of a query object.
$query->where(['id' => 1])->clause('where'); // Return the where clause in the form of a QueryExpression
More googling leads me to find out how to get the QueryExpression to spit out string representation
$query->where(['id' => 1])->clause('where')->sql($valueBinder); // Return the where clause in string format
Here is my problem. I don't know what the $valueBinder is supposed to look like. I don't know how to initialize it.
I am also happy not to use ValueBinder as long as I can get the where clause in string format using CakePHP 3 ORM and in the right SQL dialect. Please assume I am using MySQL.
Please advise.
EDIT
I tried to use $query->valueBinder() as the $valueBinder.
It is empty and does not contain the associated c:0 to the value 1.
To directly answer your question, you can get the SQL for any clause this way:
$binder = new \Cake\ORM\ValueBinder();
$query->clause('where')->sql($binder);
That will return the SQL with the correct placeholders, not with the values to be used. The values live in the $binder variable and are used for statement objects.
As I can see, you only wanted to preserve the internal structure of the where clause to pass it to another query in a different request. Your solution is fine, but I'd like to add that you can also encode a full conditions tree from an existing query:
$where = serialize($query->clause('where'));
$anotherQuery->where(unserialize($where)); // A query in another request
In any case, you need to be careful with what you are unserializing as taking it directly from user input will certainly lead to security problems.
You can choose to omit this param if you like. Please see http://api.cakephp.org/3.0/class-Cake.Database.Query.html#_sql
In addition, you can use the Query member function traverse($visitor, $parts) to isolate the where clause. $visitor is a function that takes a value and a clause. You define the behavior of $visitor. $parts is an array of clause names. I suggest passing array('where') into this param.
My workaround is that I store the conditions in json string format.
Using the same example, what I do is
$data['conditions'] = json_encode(['Articles.id' => 1]); // encode into JSON string
$this->DynamicRules->patchEntity($dynamicRule, $data); // use in edit action of DynamicRulesController
then when I need to reuse the conditions, I do:
$articlesTable = TableRegistry::get('Articles');
$query = $articlesTable->find(); // new query for Articles
$rule = json_decode($dynamicRule->conditions, true); // get back the conditions in associative array format
$query->where($rule); // re-assign the conditions back
This got me what I ultimately wanted.
I have this query:
static function findIdOnName($pageName){
return Fanpages::select('id')
->where('url', '=', $pageName)
->get();
}
Response: (when done print_r)
[{"id":17}]
I just want the INT (in this case 17) I searched the interwebs for it, but I can't find anthing about it. Randomly tried adding ->toString() etc to the query, but so far, no good.
Your code returns a Collection with a single Model (or multiple models if there are more matching the where clause), while the method you need is pluck:
return Fanpages::where('url', '=', $pageName)->pluck('id');
// returns INT 17
as it returns value for column id of the first row matching WHERE clause.
If you do not return a view with data, then Laravel will automatically convert your data into json. In order to accomplish what you want you can simply do something like
$data = Fanpages::select('id')->where('url', '=', $pageName)->get();
die($data->id);
However, exiting the application like this isn't recommended. You should either keep the json response and work with that, or send the data to a basic blade template.