Laravel convert resultset to array - php

Database table SITE has many columns. One of them is site_id. I need all the site_ids as an array since it has to be fed to a method which accepts only a string array.
What I tried so far is:
$sites = DB::select('select site_id from site_tab');
$sites_arr = $sites->toArray();
But this doesn't produce the result I want. I need $sites_arr to be like ['A','B','C',...]
Please suggest a way to get this done. A solution based on Eloquent is also OK for me.
Thanks

Try this:
DB::table('site_tab')->pluck('site_id')->toArray();
reference pluck
referen toArray

If you open a manual, you will see that
The select method will always return an array of results
So, there's no need to use ->toArray(), as result is already an array.
To get values as array of names you can do:
$site_ids = DB::table('site_tab')->pluck('site_id');
Using ->toArray() here is optional, as you can iterate over $site_ids (which is a Collection) with a foreach too.

Related

how to compare two plucked results in laravel?

I am having some trouble while trying to compare two plucked collections. Objective is to compare the plucked values and get those values that are not present in both arrays.
I tried the following for this
$users = message::withTrashed()->where([
'sentTo' => $authId,
'isDraft' => 0
])->groupBy('group_message_id')->pluck('group_message_id')->all();
$checkDeleted = inboxDeleted::whereIn('thread_id',$users)
->where('user_id',$authId)
->pluck('thread_id')->all();
From here same values should be eliminated and distinct values should be kept. Is it possible to compare plucked values? If no then how to check the plucked values.
Data should not be fetched from query?
Thanks for suggestions. :)
You can use diff() (Laravel solution):
$diff = $users->diff($checkDeleted);
$diff->all();
From the docs:
The diff method compares the collection against another collection or a plain PHP array based on its values. This method will return the values in the original collection that are not present in the given collection
As I know, pluck returns values of particular column as array instead of collection.
So, you can use array_diff() method like this:
$difference = array_diff($users,$checkDeleted);
This will give you desired result.
You can use
$result=array_diff($a1,$a2);

Laravel get single column result as string

Hello I would like to know is it possible to get column value as string. Instead of array in array:
Current query: Number::limit('1000')->get(['number'])->toArray()
The result at the moment is this:
Preferable result:
Before your toArray() call, add pluck('number'):
$result = Number::limit('1000')->get(['number'])->pluck('number')->toArray();
That's it! This will pluck just the number attributes from your result collection, and give you a single-level array.
The reason this works, is because you are getting a Collection back from get():
All multi-result sets returned by Eloquent are an instance of the Illuminate\Database\Eloquent\Collection object, including results retrieved via the get method or accessed via a relationship.
And the pluck method:
https://laravel.com/docs/5.1/collections#method-pluck
Update
Another, even more succinct method provided by #wunch in the comments:
$result = Number::limit('1000')->lists('number')->toArray();

Using Array in '->where()' for Laravel Query Building

I am trying to get all values of a column, and then use it in another query. I used lists and got the values as an array but, I couldn't find the way to check that variable (array containing each id) in other query
$subscribes = Subscribe::where('from_id', $currentUser)->lists('id')
// dd($subscribes), logs values as array.
$videos = Photo::where('id', $subscribes)->get();
This doesn't work because $subscribes is an array.
Should I use a for loop and send another query for each id? Or is there a practical way that I am missing out? What is the proper way of using it?
Use whereIn method:
$videos = Photo::whereIn('id', $subscribes)->get();
http://laravel.com/docs/5.1/queries (scroll down / search 'whereIn')
Apply whereIn method
if(is_array($subscribes) && count($subscribes) > 0){
$videos = Photo::whereIn('id', $subscribes)->get();
}

Using aliases with eloquent

When I tried using alias using select with eloquent, it has given me weird results
my code:
$caseStudy = CaseStudy::find($id)->select('title_case as title','description_case as description')->get();
It returned collection. My question is to find model and change the column names. How to do it?
The find function can take an array as a second parameter.
In this array you can list the fields you need.
$caseStudy = CaseStudy::find($id, ['title_case as title','description_case as description']);
This way you should be able to access your aliases:
$caseStudy->title
Instead of:
$caseStudy->title_case
try using this
$caseStudy = CaseStudy::select(DB::raw('title_case as title','description_case as description'))->find($id)->get();

how to get the where clause in string format using CakePHP3 ORM?

In CakePHP3, there is a ORM that helps with building queries.
From the documentation, I can see that
$query = $articles->find(); // build a query that has not run yet
$query->where(['id' => 1]); // Return the same query object
So in this case, I want the string
WHERE `articles`.`id` = 1
After much googling, I found out that there is a way to return just the where clause of a query object.
$query->where(['id' => 1])->clause('where'); // Return the where clause in the form of a QueryExpression
More googling leads me to find out how to get the QueryExpression to spit out string representation
$query->where(['id' => 1])->clause('where')->sql($valueBinder); // Return the where clause in string format
Here is my problem. I don't know what the $valueBinder is supposed to look like. I don't know how to initialize it.
I am also happy not to use ValueBinder as long as I can get the where clause in string format using CakePHP 3 ORM and in the right SQL dialect. Please assume I am using MySQL.
Please advise.
EDIT
I tried to use $query->valueBinder() as the $valueBinder.
It is empty and does not contain the associated c:0 to the value 1.
To directly answer your question, you can get the SQL for any clause this way:
$binder = new \Cake\ORM\ValueBinder();
$query->clause('where')->sql($binder);
That will return the SQL with the correct placeholders, not with the values to be used. The values live in the $binder variable and are used for statement objects.
As I can see, you only wanted to preserve the internal structure of the where clause to pass it to another query in a different request. Your solution is fine, but I'd like to add that you can also encode a full conditions tree from an existing query:
$where = serialize($query->clause('where'));
$anotherQuery->where(unserialize($where)); // A query in another request
In any case, you need to be careful with what you are unserializing as taking it directly from user input will certainly lead to security problems.
You can choose to omit this param if you like. Please see http://api.cakephp.org/3.0/class-Cake.Database.Query.html#_sql
In addition, you can use the Query member function traverse($visitor, $parts) to isolate the where clause. $visitor is a function that takes a value and a clause. You define the behavior of $visitor. $parts is an array of clause names. I suggest passing array('where') into this param.
My workaround is that I store the conditions in json string format.
Using the same example, what I do is
$data['conditions'] = json_encode(['Articles.id' => 1]); // encode into JSON string
$this->DynamicRules->patchEntity($dynamicRule, $data); // use in edit action of DynamicRulesController
then when I need to reuse the conditions, I do:
$articlesTable = TableRegistry::get('Articles');
$query = $articlesTable->find(); // new query for Articles
$rule = json_decode($dynamicRule->conditions, true); // get back the conditions in associative array format
$query->where($rule); // re-assign the conditions back
This got me what I ultimately wanted.

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