Get Array value based on object ids with php - php

Question

I have this Array but i don't know how to get the [discount_amount] based on the [object_ids].
For example i would like to get the 93 value if my [object_ids] contain 81.
Array
(
[0] => Array
(
[id] => rule_5b0d40cd1408a
[membership_plan_id] => 106
[active] => yes
[rule_type] => purchasing_discount
[content_type] => post_type
[content_type_name] => product
[object_ids] => Array
(
[0] => 81
)
[discount_type] => amount
[discount_amount] => 93
[access_type] =>
[access_schedule] => immediate
[access_schedule_exclude_trial] =>
)
[1] => Array
(
[id] => rule_5b0d4e0f3b0b4
[membership_plan_id] => 106
[active] => yes
[rule_type] => purchasing_discount
[content_type] => post_type
[content_type_name] => product
[object_ids] => Array
(
[0] => 110
)
[discount_type] => amount
[discount_amount] => 50
[access_type] =>
[access_schedule] => immediate
[access_schedule_exclude_trial] =>
)
)

Answer 1

You could use a foreach and use in_array to check if the array object_ids contains 81.
foreach ($arrays as $array) {
if (in_array(81, $array["object_ids"])) {
echo $array["discount_amount"];
}
}
Demo

Answer 2

Try with this code .
Assuming $dataArray is the array you have printed.
foreach ($dataArray as $key => $value){
if($value['object_ids'][0] == 83){
$discount_amount = $value['discount_amount'];
}
}
echo $discount_amount

Answer 3

The way I mostly do this is as followed:
# Save retrieved data in array if you want to.
$test = array();
foreach($array as $line){
# Count the row where discount_amount is found.
$test[] = $line['9'];
echo "Result: ".$line['9']. "<br \>\n";
# OR another method is
$test[] = $line['discount_amount'];
echo "Result: ".$line['discount_amount']. "<br \>\n";
}