Remove array from multidimentional array using id in php - php

Question

I want to remove array from multidimentional array using base of ID. I tried using foreach loop. But, It is not working.
Any one help me how to remove this?
Thanks.
=> Array :
Array
(
[0] => Array
(
[id] => 11109
[value] => Yes
[field_id] => 234
)
[1] => Array
(
[id] => 11109
[value] => Yes
[field_id] => 237
)
[2] => Array
(
[id] => 11110
[value] => No
[field_id] => 234
)
[3] => Array
(
[id] => 11110
[value] => No
[field_id] => 237
)
[4] => Array
(
[id] => 11111
[value] => No
[field_id] => 237
)
)
From this array, I want to remove array which
field_id is 234 and value is "No" && field_id is 237 and value is
"No".
field_id is 234 and value is "Yes" && field_id is 237 and value is
"Yes".
So, From this array only ID 11111 array is display otherwise all array remove from current array.
Here is my code using I tried to remove array.
foreach ($collection->getData() as $key => $value) {
if(($value['field_id'] == $ids[0] && $value['value'] == "No")){
echo $value['id'];
// exit;
break;
}
echo $value['field_id'];
echo $value['value'];
if(($value['field_id'] == $ids[1] && $value['value'] == "No")){
print_r($collection->getData()[$key]);
unset($collection->getData()[$key]);
unset($collection->getData()[$key-1]);
}
}

Answer 1

You can create a new Multidimensional array , and copy only the values you want to it .
also , when you use break , you get out of the foreach loop completely , i don't think this is the intended behavior , use continue to skip current iteration and test the next element

Answer 2

Is the function getData() returning a copy of the array or a reference? If is is only a copy the unset($collection->getData()[$key]) won't work.
Better you loop over the array as you do, but store all keys you want to delete in side a other array (e.g. $keysToRemove). When the for-each-loop is finished you start to loop the new array $keysToRemove containing all the keys you want to remove and remove then from array.
$keysToRemove = array();
$data = $collection->getData(); // copy or reference?
foreach ($data as $key => $value) {
if(($value['field_id'] == $ids[0] && $value['value'] == "No")){
echo $value['id'].'<br>';
break; // exit the loop? If you want to jump to the next element use "continue"
}
echo $value['field_id'].'<br>';
echo $value['value'].'<br>';
if(($value['field_id'] == $ids[1] && $value['value'] == "No")){
$keysToRemove[$key] = true;
$keysToRemove[$key-1] = true;
}
}
foreach(array_keys($keysToRemove) as $key){
echo '<p>remove key '.$key.' with content <pre>'.print_r($data[$key], true).'</pre></p>';
unset($data[$key]);
}
echo '<p>Result array is<pre>'.print_r($data, true).'</pre></p>';
So you don't manipulate the array your loop use at the moment.

Answer 3

Based on the comment that mentioned its a Magento Collection. I think, You could filter the ids in collection itself so that those are not fetched as part of the collection you want. Like:
$collection = Mage::getModel('your/model')->getCollection();
$collection->addAttributeToFilter('field_id', array('nin' => array(234, 237)));
OR, following if your model is non-eav entity model
$collection = Mage::getModel('your/model')->getCollection();
$collection->addFieldToFilter('field_id', array('nin' => array(234, 237)));

Answer 4

try this code which remove all array value which value is No
$cart = array(
0 => array
(
'id' => 11109,
'value' => 'Yes',
'field_id' => 234
),
1 => array
(
'id' => 11109,
'value' => 'Yes',
'field_id' => 123
),
2 => array
(
'id' => 11110,
'value' => 'No',
'field_id' => 234
),
3 => array
(
'id' => 11110,
'value' => 'No',
'field_id' => 237
),
4 => array
(
'id' => 11111,
'value' => 'No',
'field_id' => 237
),
);
$found = array();
$i = 0;
foreach ($cart as $key => $data) {
if ($data['field_id'] == 234 && $data['value'] == 'No') {
$found[$i]['id'] = $data['id'];
$found[$i]['value'] = $data['value'];
$found[$i]['field_id'] = $data['field_id'];
$i++;
}
}
echo "<pre>";
print_r($found);
then Output Is:
Array
(
[0] => Array
(
[id] => 11111
[value] => No
[field_id] => 234
)
)