Prepared statements when working with set operations - php

Question

I've got a simple query that is not so easy to execute in PHP script:
SELECT `title` from `MY_TABLE` WHERE id in (30,32,33,44)
Usually I execute sql queries with prepared statements. I place a bunch of ? and than bind parameters. This time the numbers in parenthesis are an array of data I get from the user.
I tried this, but it does not work:
$ids = [30,32,33,44];
$stmt = $mysqli->prepare("
SELECT `title` from `MY_TABLE` WHERE id in (?)
");
// $stmt->bind_param();
$stmt->bind_param("i",$ids);
$stmt->execute();
$stmt->bind_result($title);
$stmt->store_result();
//fetch
How can I execute a set operation with prepared statements?
UPDATE:
After following your advice I came up with this
$ids = [30,32,33,44];
$questionMarks = rtrim(str_repeat('?,',count($ids)),", ");
$parameters = str_repeat('i',count($ids));
echo $questionMarks."<br>";
echo $parameters."<br>";
$stmt = $mysqli->prepare("
SELECT `title` from `MY_TABLE` WHERE id in (".$questionMarks.")
");
$scene_names = [];
$stmt->bind_param($parameters, $ids); //error here
$stmt->execute();
$stmt->bind_result($title);
$stmt->store_result();
I am still getting an error. This time it says:
Number of elements in type definition string doesn't match number of bind variables
I am not sure why it thinks that the number of elements (what is element in this case?) is wrong.
UPDATE 2:
Instead of:
$stmt->bind_param($parameters, $ids); //error here
I used:
$stmt->bind_param($parameters, ...$ids); //error gone
Taraam. Works fine.

Answer 1

Something like:
$ids = [30,32,33,44];
$types = array();
foreach($ids as $i){
array_push($types,'i');
}
$params = array_merge($ids,$types);
$sqlIN = str_repeat('?,',count($ids));
$sqlIN = rtrim($sqlIN, ',');
//Value of $sqlIN now looks like ?,?,?,?
$sql = "SELECT title from MY_TABLE WHERE id IN ($sqlIN)";
$stmt = $mysqli->prepare($sql);
call_user_func_array(array($stmt, 'bind_param'), $params);
$stmt->execute();
$stmt->bind_result($id);
$stmt->store_result();