SELECT COUNT(*) as count, MONTH(begin_date)
FROM `events`
WHERE (YEAR(begin_date) = YEAR(CURDATE()))
OR (YEAR(begin_date) = YEAR(CURDATE()) + 1)
GROUP BY MONTH(begin_date)
Here is sql query, i want to write it in laravel eloquent.
what i try:
$oncoming_events = DB::table('events')
->select(DB::raw('count(*) as numOfOncomingEvents, MONTH(begin_date)'))
->where('YEAR(begin_date)', '=', 'YEAR(CURDATE())')
->orWhere('YEAR(begin_date)', '=', 'YEAR(CURDATE()) +1')
->groupBy('MONTH(begin_date)')->get();
Error:
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'YEAR(begin_date)' in 'where clause' (SQL: select count(*) as numOfOncomingEvents, MONTH(begin_date) from events where YEAR(begin_date) =
laravel 5.6
btw
sql query works..
You need to use DB::raw() in where to tell the query builder that it is not column name it is data manipulation in query,
$oncoming_events = DB::table('events')->select(DB::raw('count(*) as numOfOncomingEvents, MONTH(begin_date)'))->where(DB::raw('YEAR(begin_date)'), '=', 'YEAR(CURDATE())')->orWhere(DB::raw('YEAR(begin_date)'), '=', 'YEAR(CURDATE()) +1')->groupBy(DB::raw('MONTH(begin_date)'))->get();
Related
I have the problem with pagination in laravel framework.
I built my query in this way:
$auctions = Auction::where('status', '=', 1)
->Where('minQuantity', '>', 0)
->whereRaw('endTime > NOW()');
$auctions->selectRaw('*,' . DB::raw('IF ((SELECT COUNT(*) FROM observed_auctions WHERE observed_auctions.idUser=' . intval($userId) . ' AND observed_auctions.idAuction=auctions.id)>0,\'true\',\'false\') as isObserved'));
Next, I get the result:
$auctions->paginate(15, ['name'], 'page', $currentPage);
It works pretty well until I want to find only observed auctions if I added where clause:
$auctions->where('isObserved', '=', true);
I get error:
Column not found: 1054 Unknown column 'isObserved' in 'where clause' (SQL: select count(*) as aggregate from auctions where status = 1 and minQuantity > 0 and endTime > NOW() and isObserved = 1)
How can I solve this problem?
I am new to laravel and i want to write mysql query in laravel 5.4.
query is like :
note: avoid column names..
SELECT *
FROM (SELECT DISTINCT *
FROM messages
WHERE (from_id=1 OR to_id=1)
ORDER BY created DESC) as m
GROUP BY `from_id`
I tried but gives error.
$messages = DB::table('messagetbl')
->select('*')
->Where(function($query) use ($userid){
$query->distinct()
->where('senderid',$userid)
->orWhere('receiverid',$userid)
->orderBy('datetime','desc');
})
->groupBy('senderid')
->get();
Error:
SQLSTATE[42000]: Syntax error or access violation: 1055
Expression #1 of SELECT list is not in GROUP BY clause and contains
nonaggregated column 'db.messagetbl.id' which is not functionally
dependent on columns in GROUP BY clause; this is incompatible with
sql_mode=only_full_group_by (SQL: select * from messagetbl where
(senderid = 8 or receiverid = 8) group by senderid)
Thanks in advance.
I believe something like this:
DB::table('messages')
->select('*')
->where('form_id', '=', 1)
->orWhere('to_id', '=', 1)
->orderBy('created', 'desc')
->groupBy('form_id')
->distinct()
->get();
Here is my join query
$data['userslist'] = DB::table('users')
->select('users.*','user_roles.role_name')
->join('user_roles','users.user_type=user_roles.role_id')
->where('users.user_type','!=',1)
->get();
But i will get the following error in where clause
check the manual that corresponds to your MariaDB server version for
the right syntax to use near 'where `users`.`user_type` != ?' at
line 1 (SQL: select `users`.*, `user_roles`.`role_name` from `users`
inner join `user_roles` on `users`.`user_type=user_roles`.`role_id`
where users.user_type != 1)
You try to fetch users.user_type where value in not equal to 1. For this, you need to use '<>' in where clause
Now your query is as follow :
$data['userslist'] = DB::table('users')
->select('users.*','user_roles.role_name')
->join('user_roles', 'users.user_type', '=', 'user_roles.role_id')
->where('users.user_type','<>',1)
->get();
I hope you will get your solution.
I have three tables. work_orders, customers, and aircraft. In the work_orders table there are two fields customer_id and aircraft_id. I'm trying to retrieve the customers and aircraft data through the use of join. I am getting an array of errors, but they all seem to be pointed in the same direction and that is that the table cannot be found.
Here is my WorkOrderController index:
public function index(WorkOrder $workorder)
{
$workorder_array = $workorder
->join('work_orders as work', 'work.aircraft_id', '=', 'aircraft.id')
->join('work_orders as workorder', 'workorder.customer_id', '=', 'customers.id')
->select('work_orders.opened_date', 'customers.mobile', 'aircraft.year')
->get();
return view('work-orders.index', compact('workorder_array'));
}
And with this I get the following error:
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'aircraft.id' in 'on clause' (SQL: select work_orders.opened_date from work_orders inner join work_orders as work on aircraft.id = work.aircraft_id inner join work_orders as workorder on workorder.customer_id = customers.id)
I've tried switching work.aircraft_id with aircraft.id, because the Laravel Docs show it in that order, but that doesn't make any difference either. The only way I can get rid of this error is to remove my join statements.
I had the wrong table in the join statement. Here's what I should have had:
public function index(WorkOrder $workorder)
{
$workorder_array = $workorder
->join('aircraft', 'work_orders.aircraft_id', '=', 'aircraft.id')
->join('customers', 'work_orders.customer_id', '=', 'customers.id')
->select('*')
->get();
return view('work-orders.index', compact('workorder_array'));
}
I'm trying to build in search functionality in my application (Laravel 5.1), but my join doesn't seem to do anything to the resulting query. What am I doing wrong?
Code:
$query = InvoiceHeader::where('customer_code_id', '=', Auth::user()->customer_code_id);
$query->join('invoice_types', 'invoice_headers.invoice_type_id', '=', 'invoice_types.id')
->where('invoice_types.name', '<>', array_search('Faktura', InvoiceHeader::INVOICE_TYPES));
$invoices = $query->paginate(15);
Resulting query:
select count(*) as aggregate from invoice_headers where customer_code_id = 1 and (invoice_types.name <> 380)
Resulting response:
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'invoice_types.name' in 'where clause'
This is the query I was hoping to see:
select count(*) as aggregate
from invoice_headers
inner join invoice_types
on invoice_headers.invoice_type_id = invoice_types.id
where customer_code_id = 1
and (invoice_types.name <> 380)
$query = InvoiceHeader::where('customer_code_id', '=', Auth::user()->customer_code_id);
you need to store the query in a variable.
$query = $query->join('invoice_types', 'invoice_headers.invoice_type_id', '=', 'invoice_types.id')
->where('invoice_types.name', '<>', array_search('Faktura', InvoiceHeader::INVOICE_TYPES));
$invoices = $query->paginate(15);
You need to add JOIN with invoice_types table if you want to filter on invoice_types.name.