I'm really getting confused with the join on laravel.
I got a users table and got a students_subjects table, in the students_subjects table I got a subject_id column and a user_id column, I'm trying to get the users list by the user_id at the teachers_subjects table with the same subject_id column at the students_subjects.
I've tried :
$user_id = Auth::user()->id;
$results = DB::table('users')
->join('students_subjects', 'students_subjects.subject_id', '=', 'teachers_subjects.subject_id')
->where('students_subjects.user_id', $user_id)
->get();
but I got some errors... would be great if someone can show me the way it should be done so I can understand how to do the joins work at laravel.
structures:
users table :
- id
- name
- last name
students_subjects :
- subject_id
- user_id (users->id)
teachers_subjects :
- subject_id
- teacher_id (users->id)
You need to add a join for both tables:
$user_id = Auth::user()->id;
$results = DB::table('users')
->join('students_subjects', 'users.id', '=', 'students_subjects.user_id')
->join('teachers_subjects', 'students_subjects.subject_id', '=', 'teachers_subjects.subject_id')
->where('students_subjects.user_id', $user_id)
->get();
You may have to tweak this to get exactly what you're looking for.
If you don't know to use laravel eloquent queries then you can execute raw queries using laravel if you are comfortable with it
$cards = DB::select("SELECT * FROM TABLE");
This way you can easily run your queries without any other RND
Related
I have a table (A) that has a One to Many relation with another table (B).
I want to query Table A and eager load Table B with the Table A results - but I also want to sort Table A by a value in Table B.
I have tried using OrderBy in the query and also trying SortBy on the resultant collection but cannot get the Table A data to be sorted by the value found in Table B.
Example of what I have tried:
$query = ModelA::with("ModelB"])->get()->sortByDesc('ModelB.sortValue');
Keep in mind, I am only interested in the LATEST record from Table B. So I need to query Table A and sort by a value in the LATEST records of Table B.
How can I achieve this?
EDIT:
The below (as suggested by #ljubadr) works pretty close, but the issue is that there are many record in Table B which means that it doesn't reliably sort as it doesn't seem to sortby the latest records in Table B. Can I have the join return ONLY the latest record for each ID?
$query = ModelA::select('TableA.*')
->join('TableB', 'TableA.id', '=', 'TableB.col_id')
->groupBy('TableA.id')->orderBy('TableB.sortCol', 'desc')
->with(['x'])
->get();
EDIT 2:
#Neku80 answer has gotten me closest but it seems to not sort the column with the greatest accuracy.. I'm sorting a Decimal column and for the most part it is in order but in some places the items are out of order..
$latestTableB = ModelB::select(['TableA_id', 'sortByColumnName'], DB::raw('MAX(created_at) as created_at'))
->groupBy('TableA_id');
$query = ModelA::select('TableA.*')
->joinSub($latestTableB, 'latest_TableB', function ($join) {
$join->on('TableA.id', '=', 'latest_TableB.TableA_id');
})
->orderBy('latest_TableB.sortByColumnName')
->get();
For example, the ordering is like:
0.0437
0.0389
0.0247 <-- -1
0.025 <-- +1
0.0127
When I delete all rows except for the 'latest' rows, then it orders correctly, so it still must be ordering with old data...
I have found a solution:
ModelA::select('TableA.*', 'TableB.sortByCol as sortByCol')
->leftJoin('TableB', function ($query) {
$query->on('TableB.TableA_id', '=', 'TableA.id')
->whereRaw('TableB.id IN (select MAX(a2.id) from TableB as a2 join TableA as u2 on u2.id = a2.TableA_id group by u2.id)');
})
->orderBy('TableB.sortByCol')
->get();
Another alternative to order is like this:
$users = User::orderBy(
Company::select('name')
->whereColumn('companies.user_id', 'users.id'),
'asc'
)->get();
Here we are ordering in asc order by company name field.
In this article it is explained in detail.
You can simply execute a left join query:
ModelA::query()->leftJoin('model_b_table', 'model_a_table.primary_key', '=', 'model_b_table.foreign_key')->orderBy('model_a_table.target_column')->get();
This should work if you only need TableB's ID and created_at columns:
$latestTableB = ModelB::select('TableA_id', DB::raw('MAX(created_at) as created_at'))
->groupBy('TableA_id');
$query = ModelA::select('TableA.*')
->joinSub($latestTableB, 'latest_TableB', function ($join) {
$join->on('TableA.id', '=', 'latest_TableB.TableA_id');
})
->orderBy('latest_TableB.created_at')
->get();
I'm using luman and Database Query Builder to fetch full user info from database.
First, Please Take a lock at my database structure:
I have a table called users and a series of other tables that are related to user groups (Ex: secretaries, patients, doctors and admins) which stores additional information about the users.
Also To determine user access, I have a level column on user table which can have one of this value as enum: 'admin', 'doctor', 'secretary', 'patient'.
So, I want to get this information using one query by join and select.
My training code is something like this:
$userInfo = User::where("userID", $userID)
->limit(1)
->join('[GROUP_TABLE_NAME]', function ($join) {
$join->on('user.userID', '=', '[GROUP_TABLE_NAME]' .'.'.
'[GROUP_NAME]' . 'ID');
})
->get();
The GROUP_NAME comes from level column on user table and the GROUP_TABLE_NAME can be built based on the GROUP_NAME value(Ex: ['secretary' => 'secretaries' , 'patient' => 'patients' , ...]).
Any idea to handle the join structure using laravel query builder?
First you should be aware of the fact that this code architecture is not convenient and not easy to understand for other developers.
SQL
You can achieve your goal by using union and join.
Just convert this query for laravel builder or use it directly with DB::statement: select users.*, infos.info from users left join (( select secretaries.* from secretaries ) UNION (select doctors.* from doctors)) infos ON users.id = infos.user_id where users.id=?.
But
The easiest way to do it is to fetch info in two queries, both indexed and fast: user from users by primary key and then info by indexed field user_id in it. Create Doctorinfo, Admininfo models and correspondent migrations. So user class can be smth like this:
public function getInfo() {
switch($this->level) {
'doctor':
return $this->doctorinfo;
...
}
}
private function doctorinfo() {
$this->hasOne('App\Doctorinfo');
}
Builder
You can use left join to join all sub tables as well. The following builder selects info column.
User::where("userID", $userID)->limit(1)
->leftJoin('patients', 'users.id', '=', 'patients.user_id')
->leftJoin('doctors', 'users.id', '=', 'doctors.user_id')
->leftJoin('admins', 'users.id', '=', 'admins.user_id')
->select('users.*', DB::raw('IF(users.level="admin", admins.info, (IF users.level="doctors", doctors.info, patients.info))'))
I was wondering how I would go about converting this query to Laravel?
SELECT * FROM users INNER JOIN srp_user_statistics ON users.id = srp_user_statistics.user_id ORDER BY srp_user_statistics.payslips_collected DESC LIMIT 2
"users" table is in a modal called Player and the srp_user_statistics table is in a modal called Roleplay which is a relationship of modal Player called "roleplay"
I tried this, but its returning DESC even when selecting ASC:
$players = Player::whereHas('roleplay', function ($query) use($orderType) {
$query->orderBy('payslips_collected', $orderType);
})->get();
using Larvel Query Builder:
$record = DB::table('users')
->innerJoin('srp_user_statistics', 'users.id', '=', 'srp_user_statistics.user_id')
->orderBy('payslips_collected', 'DESC')
->limit(2)
->get();
I have to select data from two tables for APIs.
There are two tables garage_services, and garages. I receive garage_sevices id.
Garage_services table is like this
id | garage_id | service _id
Now from this table I select row based on service_id from here I have to select garage_id and get details about garage from garage table
$garages = $this->db
->select('*')
->from('garage_services')
->join('garage', 'garage_services.id=garage.id')
->where($where)
->get();
Above is the query I came up with, I don't know if its correct. as I am not sure about $where as well.
Please help me with this
Here I have written the query for your solution.
$garages = $this->db->from('garage_services as gs, garages as g')
->where('g.id', $garage_service_id, FALSE)
->get();
Here $garage_service_id is the variable that passed in function argument as you have written you in your question.
Try this
->select('*')
->from('garage_services as t1')
->join('garage as t2', 't1.garage_id = t2.id')
->where('t1.id', $service _id)
->get();
As per the detail is given in the question your query look correct and for the where condition:
$this->db->select('*');
$this->db->from('table1');
$this->db->join('table2', 'table1.col1 = table2.col1');
$this->db->where('table1.col1', 2);
$query = $this->db->get();
I have a query that will get the data from a joined tables. I successfully fetched the data from the 2 tables but for a long time, I did not notice that only one primary id of a certain table has been returned. I made adjustments but still never figure it out. What would I do? Please help. Thanks a lot guys. Here is my code.
$purchase = Purchase::where('purchases.purchase_order_id', $id)
->join('products', 'purchases.product_id', '=', 'products.id')
->select('purchases.*', 'products.*')
->get();
It only returns the primary id of a product, primary id of the table purchases is not included. What is the problem of the query above?
You can use select as:
->select('purchases.*', 'purchases.id as purchase_id', 'products.*', 'products.id as product_id')
This query returns the IDs of Survey Table as surveys_id as well as IDs of industries table along with all other data:
surveydata = Survey::select(
'surveys.*',
'surveys.id as surveys_id',
'industries.*',
'industries.id as industries_id'
)->where('surveys.active_status', '=','1')
-> join (
'industries',
'industries.id',
'=',
'surveys.survey_industry_id'
)->orderBy('surveys.id','desc')
->paginate(12);