Converting a complicated query to Laravel's Eloquent - php

I was wondering how I would go about converting this query to Laravel?
SELECT * FROM users INNER JOIN srp_user_statistics ON users.id = srp_user_statistics.user_id ORDER BY srp_user_statistics.payslips_collected DESC LIMIT 2
"users" table is in a modal called Player and the srp_user_statistics table is in a modal called Roleplay which is a relationship of modal Player called "roleplay"
I tried this, but its returning DESC even when selecting ASC:
$players = Player::whereHas('roleplay', function ($query) use($orderType) {
$query->orderBy('payslips_collected', $orderType);
})->get();

using Larvel Query Builder:
$record = DB::table('users')
->innerJoin('srp_user_statistics', 'users.id', '=', 'srp_user_statistics.user_id')
->orderBy('payslips_collected', 'DESC')
->limit(2)
->get();

Related

How to join tables with more than one attribute match?

I am trying to turn my raw sql into laravel query builder and I encounter difficulty on how to join multiple tables using with many attributes match.
In this case, I want to join the table jr_h and jr_d with three attributes match (book,p_seq and staff_code) rather than one (book).
Raw sql:
$sql = "select from_time,to_time,t.staff_code,s.name_t as staff_name,t.book,t.p_code,t.p_seq,p.hrs1,s.img_file,
t.hrs_work,p.sharing_cnt as hrs_work, t.hrs_ot as hrs_ot from jr_d as t
inner join jr_h as p on(t.book=p.book and t.p_seq=p.p_seq and t.staff_code=p.staff_code)
inner join astaff as s on(t.staff_code=s.staff_code) ";
Laravel query builder:
$jr_d = DB::table('jr_d')
->join('jr_h', 'jr_d.book', '=', 'jr_h.book')
->join('astaff', 'jr_d.staff_code', '=', 'astaff.staff_code')
->select('jr_h.*','jr_d.*','astaff.*','astaff.name_t as staff_name')
->where('jr_d.ref_group','=','E')
->get();
and also want to know if there is a way to make the query faster since it has a lot of data in the tables.
Laravel joins with multiple conditions:
$results = DB::table('jr_d')
->select('jr_h.*','jr_d.*','astaff.*','astaff.name_t as staff_name')
->join('jr_h', 'jr_d.book', '=', 'jr_h.book')
->join('jr_h as p', function($query){
$query->on('t.book','=', p.book');
$query->on('t.p_seq','=', 'p.p_seq');
$query->on('t.staff_code', '=', 'p.staff_code');
})
->where('jr_d.ref_group','=','E')
->get();
`
Try this:
// ...
->join('jr_h p', function($join) {
$join->on('t.book', '=', 'p.book');
$join->on('t.p_seq', '=', 'p.p_seq');
// ... more conditions
});
Try this.
$jr_d = DB::table('jr_d')
->join('jr_h', 'jr_d.book', '=', 'jr_h.book')
->join('astaff', 'jr_d.staff_code', '=', 'astaff.staff_code')
->select('*','astaff.name_t as staff_name')
->where('jr_d.ref_group','=','E')
->get();

Laravel eloquent query and join on OR condition

I am trying to do an eloquent query where it joins on a table where column a = x OR column b = x; and I cannot get it to work. So I am hoping that someone can help.
Here is my query:
$candidates = HrCandidate::where('people_id', '<>', 'NULL')
->with('contact')
->join(
'people',
->where('id','people_id')
->orWhere('alternate_id','people_id')
)
->get();
I am trying to join with the people table but where people_id = 1 or the alternate_id column. So I am hoping someone can help with this.
To get started, pass a Closure as the second argument into the join method. The Closure will receive a JoinClause object which allows you to specify constraints on the join clause:
$candidates = HrCandidate::join('people', function ($join) {
$join
->on('people.id', '=', 'candidates.people_id')
->orOn('people.alternate_id', '=', 'candidates.people_id');
})
->where('people_id', '<>', 'NULL')
->get();

select all columns which are not in another table laravel 5.5

I have two tables - the first one is called 'users' and the second one is called 'buy_courses'.
I am trying to select all users those user_name is not in buy_courses. I tried something like -
$users = DB::table('users')
->rightjoin('buy_courses', 'users.user_name', '=', 'buy_courses.user_name')
->get();
It returns all users, whose user_name is in 'buy_courses', when I am using '<>', then I'm getting all users. What should be the right query?
DB::table("users")->select('*')->whereNotIn('user_name',function($query) {
$query->select('user_name')->from('buy_courses');
})->get();
just join actually is inner join in Laravel so actually maybe also you can try:
DB::table('users')
->join('buy_courses', 'users.user_name', '=', 'buy_courses.user_name')
->get();
Try it using Eloquent:
$courseUserNames = BuyCourses::pluck('user_name')->all();
$users = User::whereNotIn('user_name', $courseUserNames)->select(...)->get();
Or if you prefer using DB query:
$courseUserNames = DB::table('buy_courses')->pluck('user_name')->all();
$users = DB::table('users')->whereNotIn('user_name', $courseUserNames)->select(...)->get();
just replace = with != , use function join
$users = DB::table('users')
->join(
'buy_courses',
function ($join)
{$join->on('users.user_name', '!=', 'buy_courses.user_name');}
)
->get();
You can use SQL's 'NOT IN'.
Example:
mysqli_query($con, "SELECT * FROM users WHERE user_name NOT IN (SELECT user_name FROM buy_courses)");

Laravel 5 - compare query from one table to another query

I have two tables: a relationship table and a users table.
Relationship table looks like: 'user_one_id', 'user_two_id', 'status', 'action_user_id'.
Users table looks like: 'id', 'username'.
I would like to query the relationship table first and return an array of all the rows where the 'status' column = 0.
Then I would like to query the users table and return an array of ids and usernames where 'user_one_id' matches 'id'.
My code so far:
public function viewRequests()
{
$currentUser = JWTAuth::parseToken()->authenticate();
$friendRequests = DB::table('relationships')
->where('user_two_id', '=', $currentUser->id)
->where('status', '=', '0')
->get();
$requestWithUsername = DB::table('users')
->where('id', '=', $friendRequests->user_one_id)
->get();
return $requestWithUsername;
}
It's not working and I'm not sure what method is easiest to reach my desired output. How can I change these queries?
EDIT:
After reviewing the response, this is the working code:
$friendRequests = DB::table('users')
->select('users.id','users.username')
->join('relationships', 'relationships.user_one_id','=','users.id')
->where('relationships.status','=',0)
->where('relationships.user_two_id', '=', $currentUser->id)
->get();
Your SQL seems to be this:
SELECT id, username
FROM users
JOIN relationships
ON relationships.user_one_id = id
WHERE relationships.status = 0
Then the Laravel way:
DB::table('users')
->select('id','username')
->join('relationships', 'relationships.user_one_id','=','id')
->where('relationships.status','=',0)
->get();

How to determine columns that will be returned in the result when using `paginate()` method in Laravel?

I have 2 tables: users and articles. To fetch all columns from the articles table and only user_name column from the users table, I use this code:
$articles = Article::join('users', 'articles.user_id', '=', 'users.user_id')
->get(array('articles.*', 'users.user_name'));
and it works fine, but when I use paginate() method like this:
$articles = Article::join('users', 'articles.user_id', '=', 'users.user_id')
->paginate(10);
it fetches all columns from both tables, which I don't want. My question is: How can I select columns that will be returned in the result if I use paginate() method in Laravel framework?
The select function does this.
$articles = Article::join('users', 'articles.user_id', '=', users.user_id')
->select('articles.*', 'users.user_name')
->paginate(10);

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