Symfony 4, check if template is already loaded? - php

Question

I have a template home.html.twig loaded and an ajax request as the code below shows. That works just fine.
But if I load my website with the route mywebsite.com/search/foo then I only have searchListing.html.twig displayed without any home.html.twig loaded so the site is broken
So is there a way in the controller, before the return, to check if my template home.html.twig is loaded and if not load it and insert searchListing.html.twig inside a block ?
my html:
<li>foo</li>
here is my ajax:
$(document).ready(function() {
$('.trigger').on('click', function(e) {
e.preventDefault();
const $link = $(e.currentTarget);
$.ajax({
url: $link.attr('href'),
type: 'get'
})
.done(function (data) {
$('#main-content').html(data)
})
});
});
my controller:
class Search extends AbstractController {
/**
* #Route("/search/{var}", name="search")
*/
public function search ($var) {
// CHECK HERE
// if home.html.twig is loaded > load searchListing.html.twig inside a given block
// if home.html.twig is not loaded > load home.html.twig then load searchListing.html.twig inside a given block
return $this->render('searchListing.html.twig',[
'var' => $var,
]);
}
}

Answer 1

If I understand correctly you need:
/**
* #Route("/search/{var}", name="search")
*/
public function search (Request $request, $var) {
// render only search results for ajax request
if ($request->isXmlHttpRequest()) {
return $this->render('searchListing.html.twig',[
'var' => $var,
]);
}
return $this->render('home.html.twig',[
'var' => $var,
]);
}