How to get ID from different controllers Yii2? - php

Question

In the ActiveForm I have model button with Pjax render field after form from the modal button will created. Added a picture for an example. How can I get newly created id (not select added to the database, need to get the id that comes from this form).
I think I need to set get to button, than with ajax catch this and transfer to my Pjax rendered cell
I tried variations, but unsuccessfully, I cann't fully understand how to implement it. Can anyone help with the solution ?
//TwoController
public function actionCreate()
{
$model = new Formtwo();
if ($model->load(Yii::$app->request->post())) {
if ($model->save()) {
echo 1;
//maybe here I must to do query ?
} else {
echo 0;
}
} else {
return $this->renderAjax('create', [
'model' => $model,
]);
}
}
Index GridView

Answer 1

I hope I understood correct; you wish that when a user creates an instance of Form2, it is transferred then to create an instance of Form1, and the id of newly created record for Form2, is put in the Form1 _form.
If I did not understand correctly, please explain better :)
In TwoController create action, after creation, you would call the create action of OneContrller:
if ($model->save()) {
return \Yii::$app->runAction('/controller/action-name', ['form2_id'=>$model->id]);
}
On OneController actionCreate add parameter with default value:
public function actionCreate($form2_id=null) {
and make sure it is passed to the view (don't forget to make sure you pass it on create.php as well to the _form.

Answer 2

//TwoController
public function actionCreate()
{
$model = new Formtwo();
if ($model->load(Yii::$app->request->post())) {
if ($model->save()) {
echo $model->id;
//maybe here I must to do query ?
} else {
echo 0;
}
} else {
return $this->renderAjax('create', [
'model' => $model,
]);
}
}
You don't need query. Just use $model->id. It has value after save().
Update
It doesn't matter in which controller you are. You get the id of the model saved after save(). Then you can use id attribute. So, you can open modal form with ajax load. On form2 you register script to ajax post form. Something like this:
$("#form :submit").click(function (e) {
e.preventDefault();
$.ajax({
method: "POST",
url: $("#form").attr("action"),
data: $("#form").serialize(),
success: function (response) {
$("#modalid").modal("hide")
$.pjax.reload({
container: "#grid"
});
$('#Form2_id').val(response); //here you get the id
},
})
return false;
});