I'm using laravel 5.6, and the debugbar allows me to do this:
$IncomingAJAX = json_decode($AJAXrequest, TRUE);
Log::info($AJAXrequest);
which produces this:
[2018-08-05 20:39:11] local.INFO: array (
0 =>
array (
'category' => 'This is Category 1',
'answers' =>
array (
0 =>
array (
'question' => 'This is Question 1',
'score' => 2,
),
1 =>
array (
'question' => 'This is question 2',
'score' => 3,
),
),
),
1 =>
array (
'category' => 'Category #67',
'answers' =>
...
But how do I refer to a specific element? This is driving me mad. I've tried Log::info($AJAXrequest[0].category[0].Answers[0]); and Log::info($IncomingAJAX[0].category[0].Answers[0]); or even just Log::info([0].category[0].Answers[0]) or this one Log::info(AJAXrequest['category']) to no avail.
But this works: Log::info($AJAXrequest[0]['category']);
What I'd really like to do is iterate as follows:
$jsonIterator = new \RecursiveIteratorIterator(
new \RecursiveArrayIterator($AJAXrequest),
\RecursiveIteratorIterator::SELF_FIRST);
foreach ($jsonIterator as $key => $val) {
...}
I'm missing something obvious.
It looks like your syntax is incorrect. you are accessing array elements. The dot (.) syntax is invalid in PHP.
Try
$AJAXRequest[0]["category"]
$AJAXRequest[0]["answers"][0]["question"]
$AJAXRequest[0]["answers"][1]["question"]
$AJAXRequest[1]["category"]
...
You need to look into the structure of your array more.
Also, seems like $AJAXRequest is already an array, so no need for json_decode()
Related
I am building an array (json encoded) and returning it to the caller. My output currently looks like this:
[{"org_id":1,"org_name":"Org 1"},{"org_id":4,"org_name":"Org 4"}]
I want to add a name so that output looks like this:
{
“orgs” : [
{"org_id":1,"org_name":"Org 1"},
{"org_id":4,"org_name":"Org 4"}
]
}
Here is my current code:
// if orgs were found then
if ( is_array($orgs) && !empty($orgs) ) {
$json_orgs = json_encode($user_orgs);
// else return an empty array
} else {
$user_orgs = array();
}
I am fairly new to OO coding, so I have not figured out how to initialize an object so that "orgs" is present. Maybe I don't even need an object. Any help would be greatly appreciated.
Before you json encode the array, just wrap it in another one:
$newArray = ['orgs' => $yourCurrentArray];
Then you json encode the new variable instead.
If you rather not create a new array, you can simply do:
json_encode(['orgs' => $yourCurrentArray]);
This doesn't really have anything to do with OOP since you're just working with arrays. Associative arrays becomes objects when encoded into JSON.
You didn't say exactly how you're generating the JSON at the moment, or from what object/variable in PHP, or with what structure (there is more than one possible way).
But in general, here's how you could do it with an associative array:
$data = array (
'orgs' =>
array (
0 =>
array (
'org_id' => 1,
'org_name' => 'Org 1',
),
1 =>
array (
'org_id' => 4,
'org_name' => 'Org 4',
),
),
)
And then json_encode that to get the JSON.
(Hint: you can simply do the process in reverse to generate this example code from the desired JSON.)
You can achieve this by adding a key, for example:
// variable holding your data
$data;
// return statement in your controller
return ['orgs' => $data];
You just need to decode this with json_decode() and then you get like this
array (
0 =>
array (
'org_id' => 1,
'org_name' => 'Org 1',
),
1 =>
array (
'org_id' => 4,
'org_name' => 'Org 4',
),
)
then you need to add parant array on it
array( "orgs"=> array (
0 =>
array (
'org_id' => 1,
'org_name' => 'Org 1',
),
1 =>
array (
'org_id' => 4,
'org_name' => 'Org 4',
),
)
)
then again encode it and you will get your answer
Short: Is there a way to get a named key/value from SUBARRAY without knowing the main key ?
Long:
Ive got a foreach loop that extracts text-files & turns them into individual / single arrays (resetting the array between each file)...
example:
Array
(
[Blah Blah] => Array
(
[number] => 10
[name] => nameBlah
[image] =>
)
)
Array
(
[pinkblue597] => Array
(
[number] => 18
[name] => nameBlah68
[image] =>
)
)
(the 1st part to turn into array is used by multiple parts of a process so I dont want to add unnecessary code)
I want to extract the value of "name" and "number", however I do not know the value / format of the key in advance.. - Example: pinkblue597
If I do print_r, I do see the array as I want...
print_r($found,true)."\n";
but if I do this, $name=$found[0]; I get no results for "$name"...
or
if I do this, $name=$found[0]["name"]; I get no results for "$name"...
I could do this via a foreach loop, but it seems inefficient...
PS there will only be ONE (unknown) key in this array, & a sub-array. The sub array is always the same.
Edited: made the code easier to see (forgot to do this)
If the array formation is going to be the same all the time...
then a (nested) foreach loop will suffice, take the example below,
<?php
$a = [
'somethingUnknown13582563' => [
'name' => 'name',
'number' => 15
],
'somethingUnknown2' => [
'name' => 'another name',
'number' => 24
]
];
foreach ($a as $key => $subArray) {
foreach ($subArray as $subKey => $value) {
echo $subArray[$subKey] . '<br>';
}
}
?>
Output
name
15
another name
24
Or...
You could use array_values,
<?php
$a = [
'somethingUnknown13582563' => [
'name' => 'first name',
'number' => 15
],
'somethingUnknown2' => [
'name' => 'name',
'number' => 24
]
];
$a = array_values($a);
echo $a[0]['name'];
?>
Which would turn the first associative array in to numeric indexes and would like so,
array(
0 => array(
'name' => 'first name',
'number' => 15,
),
1 => array(
'name' => 'name',
'number' => 24,
)
)
I'm not sure why you're creating a nested array in the first place if you only intend to discard it immediately, but since the array only appears to have a single element, and you only care about that element, you can simple use array_pop
$a = [
'somethingUnknown13582563' => [
'name' => 'first name',
'number' => 15
],
];
$data = array_pop($a);
echo $data['name']; // gives you 'first name'
Note that array_pop is destructive. So if you don't want this behavior you could use something like end instead.
$data = end($a); // same effect as array_pop but non-destructive
echo $data['name']; // also gives you 'first name'
With that said, the foreach construct isn't necessarily inefficient. I believe your true concern is around finding a simpler way to dereference the nested array. The easiest way to do that in your case is going to be using something like end($a)['name'] which gives you the kind of straight-forward dereferencing you're looking for.
You can use array_map() to achieve this...
array_map — Applies the callback to the elements of the given arrays. This will loop all the array elements through callback function and you can print each element present in the sub array..
<?php
$myArry = array(
'Blah Blah' => array(
'number' => 10,
'name' => 'Blah Blah 1',
),
'pinkblue597' => array(
'number' => 15,
'name' => 'Blah Blah 2',
)
);
array_map(function($arr){
echo 'Name : '.$arr['name'].'<br>';
echo 'Number : '.$arr['number'].'<br>';
},$myArry);
?>
This will give you :
Name : Blah Blah 1
Number : 10
Name : Blah Blah 2
Number : 15
Quite a difficult to explain, but for example i have an array:
$lol = array(
'key' => 'value',
'key_1' => 'value 1',
'simple_value',
'0' => 'lol',
'key_array' => array(
'key_in_second' => 'value_with_key_in_second',
'value_in_second_array',
)
);
After json_encode it would be
{"key":"value","key_1":"value 1","0":"lol","key_array":{"key_in_second":"value_with_key_in_second","0":"value_in_second_array"}}
So is it possible somehow detect if in php array had the key or note? In my example elements 'simple_value', '0' => 'lol' have same key.
PHP doesn't care if the number 0 is in quotes or not. It is storing it as numeric 0, same as 'value_in_second_array' will be 0, as it was the first element without a key.
Basically,
array('0'=>'lol') is the same as array(0=>'lol') is the same is array('lol');
You'll see simple_value dissappeared, as it was overwritten with lol.
The JSON accurately reflects the php. For example, if you had this code:
<?php
$lol = array(
'key' => 'value',
'key_1' => 'value 1',
'simple_value',
'0' => 'lol',
'key_array' => array(
'key_in_second' => 'value_with_key_in_second',
'value_in_second_array',
)
);
print_r($lol);
The output would be:
Array
(
[key] => value
[key_1] => value 1
[0] => lol
[key_array] => Array
(
[key_in_second] => value_with_key_in_second
[0] => value_in_second_array
)
)
What happened here is that as simple_value didn't have a key, it was assigned a key of 0, but was then overwritten with lol which came next. You can also see how the value_in_second_array was automatically assigned a key of 0.
So, nothing to do with json_encode, you just never had the data in PHP.
This question is based on my other question here about a suitable array processing algorithm.
In my case, I want to flatten a multidimensional array, but I need to store the full key to that element for reuse later.
For example :
array(
0 => array(
'label' => 'Item1',
'link' => 'http://google.com',
'children' => null
)
1 => array(
'label' => 'Item2',
'link' => 'http://google.com',
'children' => array( 3 => array(
'label' => 'SubmenuItem1',
'link' => 'http://www.yahoo.com',
'children' => null
)
)
)
2 => array(
'label' => 'Item3',
'link' => 'http://google.com',
'children' => null
)
)
Should be flattened into something like the following table
Key Link
===================================
[0] http://google.com
[1] http://google.com
[2] http://google.com
[1][3] http://yahoo.com
The problem is that I while I can easily store the location of an element in a multidimensional array, I am finding it to be quite hard to retrieve that element later. For example, if I store my key as $key = "[1][3]", I can not access it using $myarray[$key]. Is there anyway to do this?
Solution using recursion:
//Array parts should be an array containing the keys, for example, to address
//SubmenuItem1, I had 1.3 when the array was flattened. This was then exploded() to the array [1, 3]
$this->recurseIntoArray($myArray, $arrayParts);
private function recurseIntoArray(&$array, $arrayParts){
$current = $arrayParts[0];
$array[$current]['blah'] = 'blah'; //If you want to update everyone in the chain on the way down, do it here
array_shift($arrayParts);
if (!empty($arrayParts)){
$this->recurseIntoArray($array[$current]['children'], $arrayParts);
}else{
//If you want to update only the last one in the chain, do it here.
}
}
I've been playing around with Mongo for about a week now and I still can't work out how to modify nested arrays in Mongo with php.
So here is a sample document...
array (
'_id' => new MongoId("4cb30f560107ae9813000000"),
'email' => 'mo#maurice-campobasso.com',
'firstname' => 'Maurice',
'lastname' => 'Campobasso',
'password' => 'GOD',
'productions' =>
array (
0 =>
array (
'title' => 'a',
'date' => '1286811330.899',
),
1 =>
array (
'title' => 'b',
'date' => '1286811341.183',
),
2 =>
array (
'title' => 'c',
'date' => '1286811350.267',
),
3 =>
array (
'title' => 'd',
'date' => '1286811356.05',
),
),
)
What I wan't to do is delete an array inside the productions array, but I can't work out how. I've been playing with 'update('$pull' => ...etc)' but I haven't been able to make it work.
OK, there are a few ways to do this. In your case, I would do something like
mymongoobject.update( $unset : { "productions.2" : 1 } }
That's basically saying to unset the ".2" element of productions. Some docs here.
Now $pull should also work, but it's a little tougher because "productions" is actually an array of arrays (or objects with sub-objects). So you'd have to match arrays exactly:
mymongoobject.update( $pull : { "productions" : {'title':'d', 'date':'1286811356.05'} }
In the case above, the unset is probably the easiest option (though it will leave a "hole" in the array)
That is actually very easy, unlike traditional sql stuff you just modify the whole data and pass it back.
$cursor = $mongo->yourDB->yourCollection->findOne("_id",4cb30f560107ae9813000000);
//let's remove last item on productions
array_splice($cursor["productions"],2);
//and update the mongo document
echo $mongo->yourDB->yourCollection->update($cursor);
//it echoes 1 if successful
hope it helps.