I'm sorry, I know this has been a much debated issue but I can't solve my problem and all the posts are rather old... I've been trying for days but it doesn't work.
The thing is, I just want to execute a python script from a basic php script.
I've tried with the exec() function but have a strange error :
this is what I'm typping in php :
echo exec("C:\Users\paulz\AppData\Local\Programs\Python\Python35-32\python C:\wamp\www\tests\tipe\tipe.py 2>&1")
and I have this :
C:\Users\paulz\AppData\Local\Programs\Python\Python35-32\python.exe: can't find '__main__' module in 'C:\\wamp\\www'
a few details :
- I'm using a windows machine,
- For the 'python.exe' file, I've seen people talking about a "c:\Python26\python.exe" path but I have nothing of this kind...
- I tried to put my file in an other place ( directory ), same error
- I tried to use system(), passthru(), shell_exec(), etc... and didn't work ( I was perhaps using them in the wrong way or with bad arguments )
- I’m using wamp so I’m working in local but I’ll have to work with a real server soon so if it changes something, I’d like to know both ways...
I just want to run this python script via php and get and array in return so if this is not the good way, just show me an other one ;)
Help please :'(
thanks !
Related
Last night I spent 5.5 hours trying make PHP execute and receive the output of Virtualenv’ed Python script. Nothing worked; except for scripts that were not Virtualenv’ed.
What I am trying to do:
I am trying to make PHP call a virtualenv’d install of the Newspaper lib output text when I call it.
What I have now:
PHP: (updated)
<?php
$output = exec('newspaper2/bin/python3 /var/www/html/components/python/test.py 2>&1', $output2);
print_r(error_get_last());
echo $output2;
echo $output;
…this works when using a non-virtualenv script
Python: (updated)
from newspaper import Article
url = 'http://example.com/'
article = Article(url)
article.download()
article.html
article.parse()
article.authors
article.publish_date
string = article.text
print(string)
What the issue is:
I can run the script that PHP is running from the command line and it outputs just fine.
What I have tried:
With PHP, (I have tried all the “exec” calls for PHP) it cannot seem to open the virtual environment and returns nothing.
Before the script I have called “python3” and a few other things to no avail.
Yes, I have chmoded it to be executable…
I feel like this should be so simple.
I have tried suggestions on other posts and all over the web to no avail.
Questions:
Did I set up the virtualenv wrong?
At the top of the Python script, instead of the “#!/usr/bin/env python3” should I call something else?
If so, where do I find it? Should I start from scratch and will that
help?
Thank you for your help;
PS: I am running Ubuntu16, PHP7 and I need to use Python3
In the virtualenv'ed scripts (i.e. installed via the setuptools' entry-points), you should not touch the shebang (#!... first line). It is populated by the virtualenv & setuptools & related tools.
If you specify your own shebang, then it is not virtualenv'ed script. In that case, call python directly:
exec('/path/to/venv/bin/python3 /var/www/html/components/python/testing.py');
Alternatively, you can put the absolute path to the virtualenv's python binary to the py-script, but this does not look a good idea.
Also, remember that virtualenvs are non-relocatable. So they should stay in the path where they were created.
Also note that exec() returns only the last line of the output. You probably want shell_exec() or exec('...', $output) to get the whole output.
Also, it is unclear what happens with your script, and what is being printed on stderr. Try this command to see what is the error:
exec('/path/to/script 2>&1', $output)
#OR:
exec('/path/to/venv/bin/python3 /path/to/script 2>&1', $output)
OK, I finally figured it out and learned a lot in the process. The newspaper lib that I am using by default tries to write to the base of the users home directory. In this case, it was attempting to write to www-data, /var/www.
To fix this:
Go to the settings.py file in the newspaper library.
Edit the variable DATA_DIRECTORY = '.newspaper_scraper' and change it to DATA_DIRECTORY = '.path/to/writable/directory'
Save the file and you should be good to go.
I have no idea why it was not returning the errors that would have explained this sooner.
Hope this helps anyone else.
Thank you so much Sergey Vasilyev for your help. I appreciate it greatly.
I am trying to build a small custom task scheduler. Basically the idea is I have cron run my process script, which looks in the database and finds any scheduled tasks that are ready to run, and runs them. So I think the best way to do this would be to try to launch the tasks "in the background" by way of shell_exec and using > /dev/null, which I understand makes it so the initial script (the process script) doesn't wait for the task scripts to complete.
So first, if there is a better way to achieve this, I'm open to suggestions. Though note I am on php 5.3 so there may be some options in 5.4 and up that I don't have access to :(
However here's the question at hand:
I am testing on WAMP on my windows machine and I am trying to make a call that looks like this:
shell_exec("php $path$base_url$querystring > output_test.txt 2>&1 &");
$path is the full windows path to the script
$base_url is the base url of the script I am calling
$querystring is of course the query string being passed to the task script
I am also outputting to output_test.txt which creates such file in same directory, where I get the following error:
Could not open input file:
C:\xampp\htdocs\email\batch_email_send_u2u.php?dealer=7
Yes I realize the path references an xampp installation, but that is not the issue - all the wamp files are executing from there and everything else has worked like this for years - it was just set up this way to support a legacy setup.
It seems to me shell_exec is locating and running php, it's just that it can't open the referenced script. Can't figure out why.
Also I need to eventually get this working on a real linux server so any advice on how to make that happen would be greatly appreciated!
Found a solution! Special thanks to dan08 for getting me set on the right path.
Ultimately I found the answer in this thread: Pass variable to php script running from command line
I ended up using the argv[] array as described in that post and with a little tweak to the script I'm calling it works like a champ now.
I'm trying to execute a php script from a php file, but it seems that i can't get the correct bin path of the php.exe. Its not doing anything as far as i can tell. Lets assume service-oauth.php is a simple echo.
EDIT3:
I fixed it using php-cli instead of php or the php bin path, i must admit that i tried this before but it seems something else was off when i tried this (one of the first things i tried). The answer provided by Keith in Can't execute PHP script using PHP exec , so it ended being a duplicate :S, thanks for the help to those who commented.
EDIT2:
I tried calling the script directly from the server console as #Dagon suggested and it works, both using the php env variable and the php path to the bin, its clear that the path is correct, but something is preveting to get the output or to run the script using the php exec() function
service-oauth.php
<?php echo "Hello there"; ?>
And this is my script:
$basePath = plugin_dir_path( __FILE__ ); # Wordpress function, asume it works.
$fileToExc = $basePath . 'service-oauth.php';
# PHP_BINDIR: /usr/local/bin
# PHP_BINARY: /usr/bin/php
# exec("which php") /usr/bin/php
$phpPath = exec("which php");
$output = exec("$phpPath $fileToExc");
print_r($output);
There are a lot of answers on stackoverflow that recommend any of those 3 options i commenented in the code, but none of them seems to work, not sure if it is the path or something else that is not working. I've tested this script on my localmachine (windows) and it works (even though i had to use a hardcoded path to the bin since i wans't getting the correct path), but i'm testing on my production server (linux) and is not working.
Note: Let me be clear, that this is not a duplicate, i've tried the following answers in these posts and many others, and it didn't work for me:
How to get path of the php binary on server where it is located
Can't execute PHP script using PHP exec
PHP exec to run a file
How to call shell script from another shell script?
Execute a PHP script from another PHP script
I've also tried using .exe at the end of the binary(windows localmachine), using php-cli instead of php, and i've tested the excec function and it works, but not in this case. Also tried with a shebang in the called script.
It's propably something simple that i'm not aware of but i've been spending a lot of hours searching and testing and nothing so far. Any help is appreciated.
EDIT:
Using scandir on the bin folder shows
scandir("/usr/bin/")
Array(
...
[632] => php
[633] => php-cgi
[634] => php-cli
...
)
Tested if in safe mode using ini_get('safe_mode'), but it seems off.
I fixed it using php-cli instead of php or the php bin path, i must admit that i tried this before but it seems something else was off when i tried this (one of the first things i tried). The answer provided by Keith in Can't execute PHP script using PHP exec , so it ended being a duplicate :S, thanks for the help to those who commented. – Zagen
I having a simple problem, I guess.
I am working on an iPhone app which I can send ASIHTTPRequest to my php server (with go daddy). The php script then gets the command and run like:
$this->pdo->beginTransaction();
//do some other simple works
exec ('/usr/local/bin/php -f /path/to/my/script/test.php') ;
$this->pdo->commit();
which is suppose to run another php file within my own server (dedicated)!!! But it does NOT do anything. It does work with curl_exec() though, but I want to use another method which I can put it to work in the background server.
My planning was that I want to send too many APNS (notification) but instead of waiting for the whole list to be done, it is better to get back and let the work done in the background!! How can I do that.
When I got connected using SSH command line. I can easily call "test.php" and it works so fine. But I can not do the same thing from the above php code.
Any help is appreciated.
Use PHP Include? That will run the script.
Put something like this inside an IF Statement.
include 'YourPage.php';
My first thought is that GoDaddy might not allow exec() to be run for security purposes.
I try to crosscompile PHP (trying many versions. now working with 5.3.8) for Android (Android 2.3.3 and Android 4.0.4. Error present in both.). Almost everything is working fine. The most important function for me is executing some shell commands but it does not work! For example this code
<?php
$s = shell_exec("ps");
echo $s;
?>
must output all started processes but in fact displays a blank screen. I try many variants with functions system(), pasthru() and others. All in vain. In php.ini disable_functions empty, safemode off.
In the Internet I found that there is an error with popen() function related to Android OS. But how do I fix this problem?!
I also found this: all exec related PHP functions segfault
This is similar to my case. But for some reasons the author does not write how he corrected the error.
UPDATE: I think I know what is wrong. This link helped me: https://bugs.php.net/bug.php?id=60081 . PHP use for exec commands "/bin/sh" but on Android there is no "/bin/sh". "sh" is located in "/system/bin/sh". I try to copy "/system/bin/sh" -> "/bin/sh" and all work properly. But now there's a new question. How to tell PHP where "sh" is?