how can I format timestamp from MariaDB to universal time with timezone time from SQL
"2018-08-25 00:00:00"
wanted format
"2018-07-24T08:43:32+02:00"
I already tried this but without any result
$value['date'] = "2018-08-25 00:00:00"
gmdate("Y-m-d\Th:i:s\Z", strtotime($value['date']) + date("Z"))
Use date_format function on DateTime object.
$value['date'] = "2018-08-25 00:00:00";
$datetime = new DateTime($value['date']);
$required_format = date_format($datetime, DATE_ATOM);
echo $required_format;
Rextester Demo
Details:
DATE_ATOM - Atom (example: 2013-04-12T15:52:01+00:00)
I have edited Madhur Bhaiya's code :
<?php
$value['date'] = "2018-08-25 00:00:00";
$timestamped = strtotime($value['date']);
$datetime = new DateTime(strtotime($timestamped));
$required_format = date_format($datetime, DATE_ISO8601);
var_dump($required_format); // returns '2018-09-25T13:37:52+0200'
Related
My code is:
$etime = $arr['od'];
$ds = date("Y-m-d H:i:s", strtotime($etime));
$timezone=new DateTimeZone("UTC"); // declare whatever your timezone is
$etimed=new DateTime($ds,$timezone); // resultset datetime
$arr['od'] is 2017-08-20 19:05:59, trying to echo $etimed it breaks my code but I don't know why?
Datetime is an object, it cannot be echoed like that, therefore you need to format the datetime to echo it like the code below:
$etime = $arr['od'];
$ds = date("Y-m-d H:i:s", strtotime($etime));
$timezone=new DateTimeZone("UTC"); // declare whatever your timezone is
$etimed=new DateTime($ds,$timezone); // resultset datetime
echo $etimed->format('Y-m-d H:i:s');
I have a date that I receive in MS format for JSON dates. It looks like this:
/Date(1365004652303)/
I can convert it to a PHP DateTime object by doing this:
$timestamp = round(((int) $originalMSdate) / 1000);
$convertedDate = new DateTime();
$convertedDate->setTimestamp($timestamp);
Ultimately, though, I need it to be a string in ISO 8601 format. I tried then converting it to an ISO date object & then converting that to a string with strval() but strval() doesn't work on date objects.
I've also tried
$dateString = date_format($convertedDate, 'YY-MM-DD H:i:s');
but I need it to also include timezone info, like this: 2015-10-01T21:22:57.057Z
I don't see characters for that in date_format.
How can I achieve this?
EDIT: I should clarify that I'm not printing the resulting string. I need to pass it to a field in a database that accepts a string datatype.
Please try the below code
<?php
// input
$time = microtime(true);
// Determining the microsecond fraction
$microSeconds = sprintf("%06d", ($time - floor($time)) * 1000000);
// Creating DT object
$tz = new DateTimeZone("Etc/UTC");
$dt = new DateTime(date('Y-m-d H:i:s.'. $microSeconds, $time), $tz);
$iso8601Date = sprintf(
"%s%03d%s",
$dt->format("Y-m-d\TH:i:s."),
floor($dt->format("u")/1000),
$dt->format("O")
);
// Formatting according to ISO 8601-extended
var_dump(
$iso8601Date
);
This worked:
$timestamp = round(((int) $originalMSdate) / 1000);
$dateString = date('c', $timestamp);
The format isn't EXACTLY the same. It's in this format:
2016-04-25T14:27:00-05:00 rather than
2016-04-25T14:27:00.057Z
but it's close enough that I can do some manipulation to get what I need.
this one is worked for me. For more please refer this article.
$date = date('Y-m-d H:m:s');
echo date('c', strtotime($date)); // 2020-04-08T16:04:56+05:30
echo date(DateTime::ISO8601, strtotime($date)); // 2020-04-08T16:04:56+0530
echo date(DateTime::ATOM, strtotime($date)); // 2020-04-08T16:04:56+05:30
I'm required to take a date in the format 'Y-z' which is year-doy (e.g, 2013-146) and convert that into a unix time stamp to be store into a database.
The issue i have is that i input 2013-146 and turn it into a DateTime Object. then when i output this date in unix or 'Y-m-d' format i get 2013-5-27 not 2013-5-26 which is the correct day.
You can verify the DOY on this NASA website and this NOAA website.
Summary:
--I have the date: '2013-146'
--Using DateTime::createFromFormat and echoing using 'Y-m-d' and 'Y-z' i get: 2013-5-27 and 2013-146 respectively.
--This does not agree with the NASA website I listed and is offset by one day can anyone verify that I'm not losing my mind?
Here is the code you can test:
<?php
date_default_timezone_set('America/Chicago');
$year = 2013; //where this outputs a simple year 'CCYY'
$day = 146; //where this provides the day of year
$format = 'Y-z'; //specifying what format i'm creating the datetime with
$date = $year.'-'.$day; //formatting the strings to the above $format
$timezone = new DateTimeZone('America/Chicago'); //specify the timezone
$fileDateStore = DateTime::createFromFormat($format, $date, $timezone);//, $timezone); //create the DateTime object
$fileDateString = date_format($fileDateStore,"Y-m-d"); //format it so strtotime() can read it
$fileDate = strtotime($fileDateString); //finally create the Unix Timestamp for the date.
$newfileDOY = date_format($fileDateStore,"Y-z");
echo 'newfileDOY = '.$newfileDOY.', ';
echo 'date = '.$date.', ';
echo 'fileDateString = '.$fileDateString.', ';
echo 'fileDate = '.$fileDate.PHP_EOL;
?>
The problem is than z format in PHP begins with 0 and not with 1.
Look at: http://www.php.net/manual/en/function.date.php
z: The day of the year (starting from 0)
I have a problem by converting a date in proper format.
I get the time the from Facebook API in this format: 2013-08-23T09:00:00
I then $fbdate = date('2013-08-23T09:00:00');
When I echo $fbdate, it retuns 2013-08-25UTC05:00:00.
Then I tried:
$datum = date("d.m.Y",$fbdate);
$uhrzeit = date("H:i",$fbdate);
To extract the date and the time but it always returns:
01.01.1970 for $datum and 00:33 for $uhrzeit.
You should use strtotime() to parse a date string into a UNIX timestamp:
$fbdate = strtotime('2013-08-23T09:00:00');
$datum = date('d.m.Y', $fbdate);
$uhrzeit = date('H:i', $fbdate);
Try using the DateTime class:
$fbdate = '2013-08-23T09:00:00';
$date = DateTime::createFromFormat('Y-m-d\TH:i:s', $fbdate);
$datum = $date->format('d.m.Y');
$uhrzeit = $date->format('H:i');
echo $datum;
echo $uhrzeit;
$datum = date("d.m.Y",strtotime($fbdate));
$uhrzeit = date("H:i",strtotime($fbdate));
The date function in PHP is meant to convert a microtime into a date, so you need to convert your string dates to microtimes first.
Have you tried this? You should use strtotime() when using the date function.
$datum = date("d.m.Y", strtotime($fbdate));
$uhrzeit = date("H:i", strtotime($fbdate));
Use strtotime()
$a = date("Y-M-d", strtotime($datum));
echo $a.$uhrzeit;
More info http://php.net/manual/en/function.strtotime.php
I'm not a huge fan of using timestamp.
What I did to solve this issue was:
$updatedDate = new DateTime(
preg_replace('/^(.*)\+0000$/', '$1', $fbUser->getProperty("updated_time")),
new DateTimeZone("UTC")
);
It chops the +0000 part and creates the DateTime object with an explicit UTC timezone.
I have a date/time string like this: 180510_112440 in this format ddmmyy_hhmmss
I need a snippet for having a string formatted like this way: 2010-05-18 11:24:40
Thanks for help.
another possible answer is the common use of strptime to parse your date and the mktime function:
<?php
$orig_date = "180510_112440";
// Parse our date in order to retrieve in an array date's day, month, etc.
$parsed_date = strptime($orig_date, "%d%m%y_%H%M%S");
// Make a unix timestamp of this parsed date:
$nice_date = mktime($parsed_date['tm_hour'],
$parsed_date['tm_min'],
$parsed_date['tm_sec'],
$parsed_date['tm_mon'] + 1,
$parsed_date['tm_mday'],
$parsed_date['tm_year'] + 1900);
// Verify the conversion:
echo $orig_date . "\n";
echo date('d/m/y H:i:s', $nice_date);
$inDate = '180510_112440';
$date = strtotime('20'.substr($inDate,4,2).'-'.
substr($inDate,2,2).'-'.
substr($inDate,0,2).' '.
substr($inDate,7,2).':'.
substr($inDate,9,2).':'.
substr($inDate,11,2));
echo date('d-M-Y H:i:s',$date);
Assumes date will always be in exactly the same format, and always 21st century
list($d,$m,$y,$h,$i,$s)=sscanf("180510_112440","%2c%2c%2c_%2c%2c%2c");
echo "20$y-$m-$d $h:$i:$s";