I have a problem by converting a date in proper format.
I get the time the from Facebook API in this format: 2013-08-23T09:00:00
I then $fbdate = date('2013-08-23T09:00:00');
When I echo $fbdate, it retuns 2013-08-25UTC05:00:00.
Then I tried:
$datum = date("d.m.Y",$fbdate);
$uhrzeit = date("H:i",$fbdate);
To extract the date and the time but it always returns:
01.01.1970 for $datum and 00:33 for $uhrzeit.
You should use strtotime() to parse a date string into a UNIX timestamp:
$fbdate = strtotime('2013-08-23T09:00:00');
$datum = date('d.m.Y', $fbdate);
$uhrzeit = date('H:i', $fbdate);
Try using the DateTime class:
$fbdate = '2013-08-23T09:00:00';
$date = DateTime::createFromFormat('Y-m-d\TH:i:s', $fbdate);
$datum = $date->format('d.m.Y');
$uhrzeit = $date->format('H:i');
echo $datum;
echo $uhrzeit;
$datum = date("d.m.Y",strtotime($fbdate));
$uhrzeit = date("H:i",strtotime($fbdate));
The date function in PHP is meant to convert a microtime into a date, so you need to convert your string dates to microtimes first.
Have you tried this? You should use strtotime() when using the date function.
$datum = date("d.m.Y", strtotime($fbdate));
$uhrzeit = date("H:i", strtotime($fbdate));
Use strtotime()
$a = date("Y-M-d", strtotime($datum));
echo $a.$uhrzeit;
More info http://php.net/manual/en/function.strtotime.php
I'm not a huge fan of using timestamp.
What I did to solve this issue was:
$updatedDate = new DateTime(
preg_replace('/^(.*)\+0000$/', '$1', $fbUser->getProperty("updated_time")),
new DateTimeZone("UTC")
);
It chops the +0000 part and creates the DateTime object with an explicit UTC timezone.
Related
I have a date that I receive in MS format for JSON dates. It looks like this:
/Date(1365004652303)/
I can convert it to a PHP DateTime object by doing this:
$timestamp = round(((int) $originalMSdate) / 1000);
$convertedDate = new DateTime();
$convertedDate->setTimestamp($timestamp);
Ultimately, though, I need it to be a string in ISO 8601 format. I tried then converting it to an ISO date object & then converting that to a string with strval() but strval() doesn't work on date objects.
I've also tried
$dateString = date_format($convertedDate, 'YY-MM-DD H:i:s');
but I need it to also include timezone info, like this: 2015-10-01T21:22:57.057Z
I don't see characters for that in date_format.
How can I achieve this?
EDIT: I should clarify that I'm not printing the resulting string. I need to pass it to a field in a database that accepts a string datatype.
Please try the below code
<?php
// input
$time = microtime(true);
// Determining the microsecond fraction
$microSeconds = sprintf("%06d", ($time - floor($time)) * 1000000);
// Creating DT object
$tz = new DateTimeZone("Etc/UTC");
$dt = new DateTime(date('Y-m-d H:i:s.'. $microSeconds, $time), $tz);
$iso8601Date = sprintf(
"%s%03d%s",
$dt->format("Y-m-d\TH:i:s."),
floor($dt->format("u")/1000),
$dt->format("O")
);
// Formatting according to ISO 8601-extended
var_dump(
$iso8601Date
);
This worked:
$timestamp = round(((int) $originalMSdate) / 1000);
$dateString = date('c', $timestamp);
The format isn't EXACTLY the same. It's in this format:
2016-04-25T14:27:00-05:00 rather than
2016-04-25T14:27:00.057Z
but it's close enough that I can do some manipulation to get what I need.
this one is worked for me. For more please refer this article.
$date = date('Y-m-d H:m:s');
echo date('c', strtotime($date)); // 2020-04-08T16:04:56+05:30
echo date(DateTime::ISO8601, strtotime($date)); // 2020-04-08T16:04:56+0530
echo date(DateTime::ATOM, strtotime($date)); // 2020-04-08T16:04:56+05:30
I'm upload the excel data into mysql. in there date save like 16.5.59(dd.mm.yy) formate. I try to change this using this code
$date = '16.5.59';
echo date('d-m-y',strtotime($date));
it always show current time like 04-02-15.
Pls change this to dd-mm-yyyy formate.
Thanks in Advance.
Timestamp was limited from 01-01-1970 to 19-01-2038 on some systems (e.g. Windows).
If it not cover the between given range then it will take current date.
$date = '16.5.59';
$date_array = explode(".",$date);
$var_day = $date_array[0];
$var_month = $date_array[1];
> Blockquote
$var_year = $date_array[2];
echo $new_date_format = "$var_day-$var_month-$var_year";
Try to make the date yourself using explode and strtotime:
date_default_timezone_set('America/Los_Angeles');
$date = '16.5.59';
$date_time = strtotime(implode('-', array_reverse(explode('.', $date))))
$date_str = date('d-m-Y', $date_time);
echo $date_str;
Output: 16-5-2059
You ARE required to specify that the year is 1959 instead of 2059 (or are you sure that it's really 2059?)
You can make change from 2059 to 1959 like this:
date_default_timezone_set('America/Los_Angeles');
$date = '16.5.59';
$date_arr = array_reverse(explode('.', $date))
# This line does the job. Make sure all years are between 1900 - 1999.
$date_arr[0] = '19' . $date_arr[0];
$date_time = strtotime(implode('-', $date_arr))
$date_str = date('d-m-Y', $date_time);
echo $date_str;
I hope this answer can help you.
This is by no means the best solution but using php's date_parse_from_format is possible. You could supply a format and use the following
$date = "16.5.59";
$dateObj = date_parse_from_format("j.n.yy", $date)
with the $dateObj you can work what you need such as :
echo $dateObj['year'];
IDE Running Example
Worth noting you require PHP >=v5.3
You can do this if it is for simpler task. It will consume time.
$date = '16.5.59';
$dtSplit=explode(".",$date);
echo "<br>".$dtSplit[0].".".$dtSplit[1].".".$dtSplit[2];
echo "<br>".$dtSplit[0].".".$dtSplit[2].".".$dtSplit[1];
echo "<br>".$dtSplit[1].".".$dtSplit[0].".".$dtSplit[2];
echo "<br>".$dtSplit[1].".".$dtSplit[2].".".$dtSplit[0];
echo "<br>".$dtSplit[2].".".$dtSplit[0].".".$dtSplit[1];
echo "<br>".$dtSplit[2].".".$dtSplit[1].".".$dtSplit[0];
I'm having date 20/12/2001 in this formate . i need to convert in following format 2001/12/20 using php .
$var = explode('/',$date);
$var = array_reverse($var);
$final = implode('/',$var);
Your safest bet
<?php
$input = '20/12/2001';
list($day, $month, $year) = explode('/',$input);
$output= "$year/$month/$day";
echo $output."\n";
Add validation as needed/desired. You input date isn't a known valid date format, so strToTime won't work.
Alternately, you could use mktime to create a date once you had the day, month, and year, and then use date to format it.
If you're getting the date string from somewhere else (as opposed to generating it yourself) and need to reformat it:
$date = '20/12/2001';
preg_replace('!(\d+)/(\d+)/(\d+)!', '$3/$2/$1', $date);
If you need the date for other purposes and are running PHP >= 5.3.0:
$when = DateTime::createFromFormat('d/m/Y', $date);
$when->format('Y/m/d');
// $when can be used for all sorts of things
You will need to manually parse it.
Split/explode text on "/".
Check you have three elements.
Do other basic checks that you have day in [0], month in [1] and year in [2] (that mostly means checking they're numbers and int he correct range)
Put them together again.
$today = date("Y/m/d");
I believe that should work... Someone correct me if I am wrong.
You can use sscanf in order to parse and reorder the parts of the date:
$theDate = '20/12/2001';
$newDate = join(sscanf($theDate, '%3$2s/%2$2s/%1$4s'), '/');
assert($newDate == '2001/12/20');
Or, if you are using PHP 5.3, you can use the DateTime object to do the converting:
$theDate = '20/12/2001';
$date = DateTime::createFromFormat('d/m/Y', $theDate);
$newDate = $date->format('Y/m/d');
assert($newDate == '2001/12/20');
$date = Date::CreateFromFormat('20/12/2001', 'd/m/Y');
$newdate = $date->format('Y/m/d');
I have a date/time string like this: 180510_112440 in this format ddmmyy_hhmmss
I need a snippet for having a string formatted like this way: 2010-05-18 11:24:40
Thanks for help.
another possible answer is the common use of strptime to parse your date and the mktime function:
<?php
$orig_date = "180510_112440";
// Parse our date in order to retrieve in an array date's day, month, etc.
$parsed_date = strptime($orig_date, "%d%m%y_%H%M%S");
// Make a unix timestamp of this parsed date:
$nice_date = mktime($parsed_date['tm_hour'],
$parsed_date['tm_min'],
$parsed_date['tm_sec'],
$parsed_date['tm_mon'] + 1,
$parsed_date['tm_mday'],
$parsed_date['tm_year'] + 1900);
// Verify the conversion:
echo $orig_date . "\n";
echo date('d/m/y H:i:s', $nice_date);
$inDate = '180510_112440';
$date = strtotime('20'.substr($inDate,4,2).'-'.
substr($inDate,2,2).'-'.
substr($inDate,0,2).' '.
substr($inDate,7,2).':'.
substr($inDate,9,2).':'.
substr($inDate,11,2));
echo date('d-M-Y H:i:s',$date);
Assumes date will always be in exactly the same format, and always 21st century
list($d,$m,$y,$h,$i,$s)=sscanf("180510_112440","%2c%2c%2c_%2c%2c%2c");
echo "20$y-$m-$d $h:$i:$s";
How can I convert this string 05/Feb/2010:14:00:01 to unixtime ?
Use the strtotime function:
Example:
$date = "25 december 2009";
$my_date = date('m/d/y', strtotime($date));
echo $my_date;
For PHP 5.3 this should work. You may need to fiddle with passing $dateInfo['is_dst'], wasn't working for me anyhow.
$date = '05/Feb/2010:14:00:01';
$dateInfo = date_parse_from_format('d/M/Y:H:i:s', $date);
$unixTimestamp = mktime(
$dateInfo['hour'], $dateInfo['minute'], $dateInfo['second'],
$dateInfo['month'], $dateInfo['day'], $dateInfo['year'],
$dateInfo['is_dst']
);
Versions prior, this should work.
$date = '05/Feb/2010:14:00:01';
$format = '#^(?P<day>\d{2})/(?P<month>[A-Z][a-z]{2})/(?P<year>\d{4}):(?P<hour>\d{2}):(?P<minute>\d{2}):(?P<second>\d{2})$#';
preg_match($format, $date, $dateInfo);
$unixTimestamp = mktime(
$dateInfo['hour'], $dateInfo['minute'], $dateInfo['second'],
date('n', strtotime($dateInfo['month'])), $dateInfo['day'], $dateInfo['year'],
date('I')
);
You may not like regular expressions. You could annotate it, of course, but not everyone likes that either. So, this is an alternative.
$day = $date[0].$date[1];
$month = date('n', strtotime($date[3].$date[4].$date[5]));
$year = $date[7].$date[8].$date[9].$date[10];
$hour = $date[12].$date[13];
$minute = $date[15].$date[16];
$second = $date[18].$date[19];
Or substr, or explode, whatever you wish to parse that string.
You should look into the strtotime() function.
http://www.php.net/date_parse_from_format
$d="05/Feb/2010:14:00:01";
$dr= date_create_from_format('d/M/Y:H:i:s', $d);
echo $dr->format('Y-m-d H:i:s');
here you get date string, give format specifier in ->format() according to format needed
Simple exploding should do the trick:
$monthNamesToInt = array('Jan'=>1,'Feb'=>2, 'Mar'=>3 /*, [...]*/ );
$datetime = '05/Feb/2010:14:00:01';
list($date,$hour,$minute,$second) = explode(':',$datetime);
list($day,$month,$year) = explode('/',$date);
$unixtime = mktime((int)$hour, (int)$minute, (int)$second, $monthNamesToInt[$month], (int)$day, (int)$year);
If you're up for it, use the DateTime class
Try this:
$new_date=date('d-m-Y', strtotime($date));
If it's a string that you trust meaning that you have checked it before hand then the following would also work.
$date = new DateTime('2015-03-27');