I need help with the below code -
I have 2 tables - A and B
A | B
====================
1 | 1
2 | 2
3 | 3
All i need is the row(1) from table A should be allowed to merge with row(2) and row(3) in tableB, likewise tableA row(2) should be allowed to merge with row(1) and row(3) of tableB and tableA row(3) should be allowed to merge with row(1) and row(2) of tableB.
[this is just an example]
======================
What I have tried:
I tried to use
$array = array('1=>1','2=>2','3=>');
$query ="select A from table where B='".$T."' union all select B from table where A='".$T."'";
$array = array('1=>1','2=>2','3=>');
$query ="select A from table where B='".$T."' union all select B from table where A='".$T."'";
$stid = oci_parse($conn,$query);
$row = oci_execute($stid);
$row = oci_fetch_row($stid);
$oci_free_statement($stid);
I am not able to sure if we need to use slice/intersect/subset.
I have been trying to sort this using OCI_bind_by_array as well but no go, i have spent 3days but unable to find a solution.
Related
Suppose I have a table like:
ID|Word |Reference
1 |Dog |1
1 |Fish |2
1 |Sheep|3
2 |Dog |4
2 |Fish |5
3 |Sheep|6
4 |Dog |7
I want to select all ID's that have the word Dog AND Sheep. So the result should be ID's: 1 and 2. I tried using this query:
SELECT ID FROM `Table` WHERE Word='Dog' OR Word='Fish' GROUP BY ID Having Word='Dog AND Word='Fish'
However, this AND in the Having clause makes me get 0 results. So, am I doing something wrong or is there another way to achieve wat I want based on MySQL query only (to optimize speed, since it has to search through many rows with the same setup as in the example above)
Basically the problem is the AND statement over multiple rows with the same ID.
UPDATE:
I need to get the reference for the ID's that where found. E.g. when the ID 1 and 2 are returned I need to know that ID 1 has reference 1 and 2. ID 2 has reference 3 and 4. Currently, I'm using this query:
SELECT ID FROM `Test` WHERE Word in ('Dog', 'Fish') GROUP BY ID HAVING count(DISTINCT Word) = 2;
Thanks
Here are two solutions that return the correct records, the first as individual records by ID and Reference, and the second with one record per ID and the Words and References as comma separated in columns.
Setup table and populate rows:
DROP TABLE IF EXISTS `list1`;
CREATE table `list1` (
id int(10),
Word varchar(10),
Reference int(10)
);
INSERT INTO `list1` (`ID`, `Word`, `Reference`)
VALUES
(1, 'Dog',1),
(1 ,'Fish',2),
(1 ,'Sheep',3),
(2 ,'Dog',4),
(2 ,'Sheep',5),
(3 ,'Sheep',6),
(4 ,'Dog',7);
Returns one row for each combination of ID and Word
SELECT
t.`ID`,
t.`Word`,
t.`Reference`
FROM `list1` as t
JOIN (
SELECT
t1.`ID` as `ref_id`
FROM `list1` AS t1
WHERE `Word` in ('Sheep','Dog')
GROUP BY t1.`ID`
HAVING count(DISTINCT t1.`Word`) = 2
) AS ts
ON t.`ID` = ts.`ref_id`
WHERE t.`Word` in ('Sheep','Dog')
ORDER BY t.`ID`,t.`Word`;
Results
ID | Word | Reference
1 | Dog | 1
1 | Sheep | 3
2 | Dog | 4
2 | Sheep | 5
Returns one row per ID, with a comma separated list of Words in one column, and a comma separated list of Reference in another.
SELECT
t.`ID`,
GROUP_CONCAT(t.`Word`) AS `Words`,
GROUP_CONCAT(t.`Reference`) AS `References`
FROM `list1` as t
JOIN (
SELECT
t1.`ID` as `ref_id`
FROM `list1` AS t1
WHERE `Word` in ('Sheep','Dog')
GROUP BY t1.`ID`
HAVING count(DISTINCT t1.`Word`) = 2
) AS ts
ON t.`ID` = ts.`ref_id`
WHERE t.`Word` in ('Sheep','Dog')
GROUP BY t.`ID`
ORDER BY t.`ID`,t.`Word`;
Results:
ID | Words | References
1 | Dog,Sheep | 1,3
2 | Dog,Sheep | 4,5
You need to join the table on itself. This way you can pick up where the id's are the same for instances where dog and sheep overlap.
Try this:
declare #t table (id int , Word varchar(10) )
insert into #t (ID, Word) values (1, 'Dog'),
(1 ,'Fish'),
(1 ,'Sheep'),
(2 ,'Dog'),
(2 ,'Sheep'),
(3 ,'Sheep'),
(4 ,'Dog')
select t.ID
from #t as t
join #t as t1 on t1.id = t.id
where t.word = 'Dog' and t1.word = 'Sheep'
Here's one way to do it by joining your table to itself.
SELECT t1.id FROM `Table` t1
INNER JOIN `Table` t2 ON t1.id = t2.id
WHERE t1.word='Dog' AND t2.word='Sheep';
The answer for my problem is solved using underneath query:
SELECT ID, GROUP_CONCAT(Reference) as ReferencesGrouped FROM `Test` WHERE Word in ('Dog', 'Fish') GROUP BY ID HAVING count(DISTINCT Word) = 2;
This will return me:
ID|ReferencesGrouped
1 |1,4
2 |4,5
I have these two tables - user_schedules and user_schedule_meta, shown below:
------------------------------------
| id | scheduler_id | status |
------------------------------------
1 3 pending
2 5 active
3 6 active
and
----------------------------------------------
| id | user_schedule_id | meta_key |meta_value
----------------------------------------------
1 3 course-id 135
2 3 session-id 15
3 3 schedule-id 120
I want to write a query to enable me select, for example, from both tables where EVERYONE of the below 5 conditions are met:
user_schedule_id = 3
scheduler_id = 6
session_id = 15
course-id = 135
schedule-id = 120
This is what I have so far, but it is not working:
SELECT user_schedule_meta.`id` FROM user_schedule_meta, user_schedules
WHERE user_schedules.`scheduler_id` = 6
AND user_schedules.id = user_schedule_meta.`user_schedule_id`
AND (
(user_schedule_meta.`meta_key` = 'course-id' AND user_schedule_meta.`meta_value` = 135)
OR (user_schedule_meta.`meta_key` = 'session-id' AND user_schedule_meta.`meta_value` = 15)
OR (user_schedule_meta.`meta_key` = 'daily-schedule-id' AND user_schedule_meta.`meta_value` = 120)
)
GROUP BY user_schedule_meta.`id`
Any suggestions what I am not doing right?
This is a typical key-value store lookup problem. These are trickier than they look in SQL, in that they require multiple JOIN operations.
You need a virtual table with one row per user_schedules.id value, then you can filter it. So
SELECT u.id, u.scheduler_id
FROM user_schedules u
JOIN user_schedule_meta a ON u.id=a.user_schedule_id AND a.meta_key='course-id'
JOIN user_schedule_meta b ON u.id=b.user_schedule_id AND b.meta_key='session-id'
JOIN user_schedule_meta c ON u.id=c.user_schedule_id AND c.meta_key='daily-schedule-id'
WHERE a.meta_value = 135 -- value associated with course-id
AND b.meta_value=15 -- value associated with session-id
AND c.meta_value=120 -- value associated with daily-schedule-id
Notice also that you can list your table with associated attributes like this. This trick of joining the key/value table multiple times is a kind of pivot operation. I use LEFT JOIN because it will allow the result set to show rows where an attribute is missing.
SELECT u.id, u.scheduler_id, u.status,
a.meta_value AS course_id,
b.meta_value AS session_id,
c.meta_value AS daily_schedule_id
FROM user_schedules u
LEFT JOIN user_schedule_meta a ON u.id=a.user_schedule_id AND a.meta_key='course-id'
LEFT JOIN user_schedule_meta b ON u.id=b.user_schedule_id AND b.meta_key='session-id'
LEFT JOIN user_schedule_meta c ON u.id=c.user_schedule_id AND c.meta_key='daily-schedule-id'
try this is code
select * from user_schedule_meta where user_schedule_id=3 and
(meta_key='session-id' AND meta_value=15
or meta_key='daily-schedule-id' AND meta_value=120
or meta_key='course-id' AND meta_value=135
)
I have this query:
SELECT *
FROM `classes`
JOIN `classes_students`
ON `classes`.`id` = `classes_students`.`class`
And I need to add condition for selecting just classes, in which are not currently logged student (user ID is not in classes_students connected with class id) and also count how many students are in that class.
Table structure:
classes: id, name, etc
classes_students: class_id, user_id, etc
Table data:
classes:
1 | test
2 | test2
3 | test3
classes_students:
1 | 1
1 | 2
2 | 3
3 | 4
3 | 5
Expected output if im user with id 1:
classes names (with number of students in):
2 (1 student)
3 (2 students)
All this in one query. It is possible? If yes, how?
Select classid, count(*)
from class
left join student on student.classid = class.classid
group by classid
Glad help for you
Try this query:
$user_id = 1; // current user_id
$query = "SELECT `classes`.`id`, `classes`.`name`, COUNT(*) as students FROM `classes`
JOIN `classes_students`
ON `classes`.`id` = `classes_students`.`class_id`
AND `classes_students`.`user_id` != $user_id
GROUP BY `classes_students`.`class_id`
";
I figured it out! :)
Thank you guys for ur help.
$user_id = 1; // current user_id
$query = "SELECT `classes`.`id`, `classes`.`name`, COUNT(*) as students FROM `classes`
LEFT JOIN `classes_students`
ON `classes`.`id` = `classes_students`.`class_id`
WHERE `classes`.`id` NOT IN (SELECT `class_id` FROM `classes_students` WHERE `user_id`='.$user_id.')
GROUP BY `classes_students`.`class_id`
";
I have three tables where table_2 is the middle(connected) between table_1 and table_3
tables
table_id
...
...
table_rest
rest_id
table_id
...
rest
rest_id
...
...
And the query to select I use
SELECT m.table_id, table_name
FROM tables m
JOIN table_rest mr
ON m.table_id = mr.table_id
WHERE rest_id = '$rest_id'
What I need now is to join in this query another table reserv
id
...
status
To check if status is 0, 1,or 2 to not show me anything if there is no status this mean there is no record to show me. In other words this is resserved system where I show on screen few tables. If status is 0,1,2 thats mean the table is taken. If nothing is found for status this mean that there is no record for table and can be shown to user.
EDIT: Sample scenario
tables
table_id
1
2
3
4
5
rest
rest_id
1
2
table_rest
table_id | rest_id
1 2
2 2
3 2
4 2
5 2
So the query that is above will generate 5 tables for rest_id=2 and none for rest_id=1
So now I have another table
reserv
id | status
1 0
2 1
3 2
So in this table reserv currently are saved 3 tables. The idea is to show me other two whit id=4 and id=5 because they are not in table reserv and don't have any status.
Hope is a little bit more clear now.
You have to point from table reserv to which table is beign booked, let's call it reserv.table_id
SELECT m.table_id, table_name
FROM tables m
JOIN table_rest mr
ON m.table_id = mr.table_id
left join reserv
on reserv.table_id = m.id
WHERE rest_id = '$rest_id'
and reserv.status is null (*note)
*note use 'is' or 'is not' depending of your needs, as far as I read, first seems that you want !=, later that what you want is =
It's better if you provide sample data or sqlfiddle. Based on what I realize: Is this what you want:
select tables.table_id, rest.rest_id
from tables
left join table_rest on table_rest.table_id = tables.table_id
left join rest on rest.rest_id = table_rest.rest_id
where rest.rest_id = '$rest_id'
and tables.table_id not in (select id from reserv)
i have 3 tables that looks like this:
game_table
+---------+------------+------------+----------------------+----------+
| game_id | game_title | sponser_id | game expiration date | prize_id |
+---------+------------+------------+----------------------+----------+
prize_table
+----------+---------------------------+------------+-------------+--------------------+--------------------------------------------+
| prize_id | prize_image_name | prize_cost | prize_title | remaining_quantity | prize_description |
+----------+---------------------------+------------+-------------+--------------------+--------------------------------------------+
sponser_table
+------------+--------------+
| sponser_id | sponser_name |
+------------+--------------+
how do i build query that select all data from the 3 tables that
meat the statement that go's something like pseudo code:
select all data from game_table and prize_table and sponser_table where game_table.sponser_id = 2 and game_table.prize_id = 2
i tried something like this :
SELECT game_list.*, prize_list.* ,sponser_list.* FROM game_list, prize_list,sponser_list
WHERE game_list.sponser_id=2 And game_list.prize_id = 2 And game_list.game_id=2 ;
but it gave me no good results .
You had a WHERE clause to limit to the correct ids, but you had no join conditions to relate your tables. Instead of the implicit join syntax you attempted (comma-separated table list), use a explicit JOINs with stated relating columns:
SELECT
game_list.*,
prize_list.* ,
sponser_list.*
FROM
game_list
JOIN prize_list ON game_list.prize_id = prize_list.prize_id
JOIN sponser_list ON game_list.sponser_id = sponser_list.sponser_id
WHERE game_list.sponser_id=2 And game_list.prize_id = 2 And game_list.game_id=2 ;
I would recommend against selecting all columns from each table though, since you are duplicating the id columns in at least two places. Instead, be explicit about the columns you want. This will also help you if you later add additional columns to these tables that should not be included in this query.
SELECT
game_id,
game_title,
game_list.sponser_id,
game_expiration_date,
game_list.prize_id,
prize_image_name,
prize_cost,
prize_title,
remaining_quantity,
prize_description,
sponser_name
FROM
game_list
JOIN prize_list ON game_list.prize_id = prize_list.prize_id
JOIN sponser_list ON game_list.sponser_id = sponser_list.sponser_id
WHERE game_list.sponser_id=2 And game_list.prize_id = 2 And game_list.game_id=2 ;
SELECT *
FROM game_table
JOIN prize_table USING (prize_id)
JOIN sponser_table USING (sponser_id)
WHERE sponser_id = 2
AND prize_id = 2
AND game_id = 2
SELECT
game_list.*, prize_list.* ,sponser_list.*
FROM game_list
JOIN prize_list ON game_list.prize_id = prize_list.prize_id
JOIN sponser_list ON game_list.sponser_id = sponser_list.sponser_id
WHERE
game_list.sponser_id=2 And game_list.prize_id = 2 And game_list.game_id=2 ;
From your description it appears that the tables may be related. If they are, you need to use a join, like this:
SELECT *
FROM game_table g
LEFT OUTER JOIN prize_table p ON p.prize_id=g.prize_id
LEFT OUTER JOIN sponser_table s ON s.sponser_id=g.sponser_id
WHERE g.game_id=2