Hello everybody i sent some value to php from Jquery $.post method and i want give some data from database
when load data from database is not completed show loading text and when load completed show data(It's contain some tables, div, text and image)
var val = "";
$.post("showData.php",{val: "loadMyTable"},
function(response) {
// if data loaded do something
// if not show loading text
});
Show your loading text in beforeSend and show your data in complete callback:
$.ajax({
type: 'POST',
url: "showData.php",
data: {val: "loadMyTable"},
beforeSend : function() {
$('#loadingText').show();
},
success : function(data) {
$('#loadingText').hide();
$('#myNewContent').html(data);
}
});
I have a YouTube player on my page, the src comes from the session $_SESSION['video']['code'] which contains the YouTube video id.
I need it to change video when the PHP session is updated without reloading the page. Preferably with Jquery, but I'm open to others. My current code is below.
$(document).ready(function(){
refresTa();
});
function refresTa(){
$('.now_playing').load('../beta.php', function(){
setTimeout(refresTa, 1000);
});
}
The problem with it is it keeps refreshing the video, making it unplayable. is there a better way of doing this?
Instead of using .load() on .now_playing, fetch the data from PHP elsewhere, and call refresTa() only when needed. Something like this:
$(document).ready(function(){
myCheck();
});
function myCheck() {
$.ajax({
url: "ajax.php",
dataType: "json"
}).done(function(data) {
var myData = data.myData;
// do something based on data received
// call this function again
setTimeout(function(){
myCheck();
}, 10000); // every 10 seconds
});
}
In ajax.php, you can output the data back to Javascript with json_encode():
$returnArray = array("myData"=>$data);
exit(json_encode($returnArray));
I am trying to load a .php file that comes with a 2Mb image in a specific div.
I can achieve this with ajax but my problem is that I only want the current div html changed to the new one when the image is done loading. My problem right now is that my div becomes empty during the loading process.
function ajaxcallmap(my_url, my_div, my_data) {
$.ajax({
url: my_url,
data: my_data,
type: 'get',
success: function (output) {
var $imgs = $("#worldmap_container").html(output).find("img"), //hide them
imgAmount = $imgs.length,
imgCounter = 0;
$imgs.on("load", function () {
imgCounter++;
if (imgCounter === imgAmount) {
$(my_div).html(output);//show the images when they're loaded
ajaxReady();//Recal jQuery Events
}
});
}
});
}
Use a complete: function instead of a success: function.
UPDATE: Wow that was the fastest response ever and so many answers in minutes of each other. Amazing. Ok here is what I am trying to do. http://edvizenor.com/invoice33/
I want to edit this invoice on the fly but when I hit the BLUE BOX at the top I want to preview or see this content on the next page contained php var echoed out.
This blue box will change later to be a button at the bottom but for testing I am using it.
As you see it calls the ajax script but I need the edited content of the div to be sent a php var to I can echo it on the preview page. If I can put it in a php var I do what I will with it on the next page. Does that make sense? Thanks guys for your quick responses.
OLD POST
Is it possible to get the contents of a div using jQuery and then place them in a PHP var to send via GET OR POST?
I can get the contents of the div with jQuery like this:
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script>
$(document).ready(function()
{
$("#MyButton").click(function()
{
var htmlStr = $("#MyDiv").html();
});
});
</script>
But how do I put the jQuery var in a php var. I need to do this by a BUTTON press too. This is not included in the code above. I need because the div file is changeable and when I hit UPDATE and send via PHP it needs to have the latest content.
According to your situation,
You are trying to send JavaScript variable to PHP.
The only common way to do this is to exchange in JSON format,
for example, suppose we have basic text editor
Jquery:
$($document).ready(function(){
$("#submit-button").click(function(){
$.post('yourphpscript.php', {
//this will be PHP var: //this is JavaScript variable:
'text' : $("#some_text_area").text()
}, function(response){
//To avoid JS Fatal Error:
try {
var result = JSON.parse(response);
//get back from PHP
if ( result.success){ alert('successfully changed') }
} catch(e){
//response isn't JSON
}
});
});
});
PHP code
<?php
/**
*
* So we are processing that variable from JavaScript
*/
if ( isset($_POST['text']) ){
//do smth, like save to database
}
/**
* Well if you want to show "Success message"
* that div or textarea successfully changed
* you can send the result BACK to JavaScript via JSON
*/
$some_array = array();
$some_aray['success'] = true;
die( json_encode($some_array) );
You'll need to use ajax to send the value to your server.
var html = $('#myDiv').html();
$.ajax({
type: 'POST',
url: '/SomeUrl/MyResource.php',
data: JSON.stringify({ text: html }),
success: function(response)
{
alert('Ajax call successful!');
}
});
The thing you need is AJAX (see http://en.wikipedia.org/wiki/Ajax_(programming))
The basic idea is to send a http request with javascript by e.g. calling a php script and wait for the response.
With plain Javascript AJAX requests are a bit unhandy, but since you are already using jQuery you can make use of this library. See http://api.jquery.com/jQuery.ajax/ for a complete overview.
The code on client side would be something like this:
$.ajax({
url:'http://example.com/script.php',
data:'var=' + $('#myDiv').html(),
type:'GET'
success:function(response) {
console.log(response) // Your response
},
error:function(error) {
console.log(error) // No successful request
}
});
In your script.php you could do something like this:
$var = $_GET['var'];
// Do some processing...
echo 'response';
and in your javascript console the string response would occur.
In modern ajax based applications the best practise way to send and receive data is through JSON.
So to handle bigger datasets in your requests and responses you do something like this:
$.ajax({
url:'http://example.com/script.php',
data:{
var:$('#myDiv').html()
},
type:'GET'
success:function(response) {
console.log(response) // Your response
},
error:function(error) {
console.log(error) // No successful request
}
});
And in your PHP code you can use the $someArray = json_decode($_GET['var']) to decode JSONs for PHP (it will return an associative array) and $jsonString = json_encode($someArray) to encode an array to a JSON string which you can return and handle as a regular JSON in your javascript.
I hope that helps you out.
You can use hidden form fields and use jQuery to set the value of the hidden field to that, so when the button is clicked and form submitted, your PHP can pick it up as if it were any other form element (using $_POST). Alternatively, you can use AJAX to make an asynchronous request to your PHP page. This is probably simpler. Here's an example:
$("#myButton").click(function() {
var htmlStr = $('#myDiv').html();
$.post("mypage.php", { inputHTML : htmlStr },
function(data) {
alert("Data returned from mypage.php: " + data);
});
}
Yes, Its possible
<script type="text/javascript">
$(document).ready(function(){
$('#MyButton').click(function(){
$.post('sendinfo.php',
{
data: $('#data').html()
},
function(response){
alert('Successfully');
});
});
});
</script>
<div id="data">Here is some data</div>
Use ajax for sending value to php (server).. here's a good tutorial for ajax with jquery http://www.w3schools.com/jquery/jquery_ajax.asp
you should just use Ajax to send your variable.
$.ajax({
url:'whateverUrl.php',
type:'GET',
data:{
html : htmlStr
}
});
Using AJAX:
$("#MyButton").click(function() {
var htmlStr = $("#MyDiv").html();
$.ajax({
url: "script.php",
type: "POST",
data: {htmlStr : htmlStr},
success: function(returnedData) {
//do something
}
});
});
Something like below should work.
Read more: http://api.jquery.com/jQuery.post/
$("#YourButton").click(function(e){
e.preventDefault();
var htmlStr = $("#YourDiv").html();
$.post(
url: 'YourPHP.php',
data: '{"htmlStr" : "'+htmlStr+'"}',
success: function(){
alert("Success!");
}
);
});
Send the data via XmlHttpRequest ("ajax") to your php page either via POST or GET.
this is an ajax method that inserts the data into a db and should supposedly display the new content.
<script type = "text/javascript">
$(document).ready(function() {
$('#submit').live('click', function(eve) {
eve.preventDefault() ;
var form_data = {
title: $('#title').val()
};
$.ajax({
url: "http://localhost/ci/index.php/chat/comment",
type: 'POST',
data: form_data,
success: function(msg) {
alert(msg);
}
});
});
});
</script>
However in my /chat/comment, i am loading the view again, i.e, user submits a comment, load the view again and the comment should be there. My response from server is the view's HTML. However the view comes with all the divs and there are many of them. I need to retrieve only part of the div, say, #commentspace from the ajax on success.
Look at the jQuery $.load() function?
Example
Inside "firstpage.html"
$('#content').load('secondpage.html #content');