Get div content with jQuery for PHP - php

UPDATE: Wow that was the fastest response ever and so many answers in minutes of each other. Amazing. Ok here is what I am trying to do. http://edvizenor.com/invoice33/
I want to edit this invoice on the fly but when I hit the BLUE BOX at the top I want to preview or see this content on the next page contained php var echoed out.
This blue box will change later to be a button at the bottom but for testing I am using it.
As you see it calls the ajax script but I need the edited content of the div to be sent a php var to I can echo it on the preview page. If I can put it in a php var I do what I will with it on the next page. Does that make sense? Thanks guys for your quick responses.
OLD POST
Is it possible to get the contents of a div using jQuery and then place them in a PHP var to send via GET OR POST?
I can get the contents of the div with jQuery like this:
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script>
$(document).ready(function()
{
$("#MyButton").click(function()
{
var htmlStr = $("#MyDiv").html();
});
});
</script>
But how do I put the jQuery var in a php var. I need to do this by a BUTTON press too. This is not included in the code above. I need because the div file is changeable and when I hit UPDATE and send via PHP it needs to have the latest content.

According to your situation,
You are trying to send JavaScript variable to PHP.
The only common way to do this is to exchange in JSON format,
for example, suppose we have basic text editor
Jquery:
$($document).ready(function(){
$("#submit-button").click(function(){
$.post('yourphpscript.php', {
//this will be PHP var: //this is JavaScript variable:
'text' : $("#some_text_area").text()
}, function(response){
//To avoid JS Fatal Error:
try {
var result = JSON.parse(response);
//get back from PHP
if ( result.success){ alert('successfully changed') }
} catch(e){
//response isn't JSON
}
});
});
});
PHP code
<?php
/**
*
* So we are processing that variable from JavaScript
*/
if ( isset($_POST['text']) ){
//do smth, like save to database
}
/**
* Well if you want to show "Success message"
* that div or textarea successfully changed
* you can send the result BACK to JavaScript via JSON
*/
$some_array = array();
$some_aray['success'] = true;
die( json_encode($some_array) );

You'll need to use ajax to send the value to your server.
var html = $('#myDiv').html();
$.ajax({
type: 'POST',
url: '/SomeUrl/MyResource.php',
data: JSON.stringify({ text: html }),
success: function(response)
{
alert('Ajax call successful!');
}
});

The thing you need is AJAX (see http://en.wikipedia.org/wiki/Ajax_(programming))
The basic idea is to send a http request with javascript by e.g. calling a php script and wait for the response.
With plain Javascript AJAX requests are a bit unhandy, but since you are already using jQuery you can make use of this library. See http://api.jquery.com/jQuery.ajax/ for a complete overview.
The code on client side would be something like this:
$.ajax({
url:'http://example.com/script.php',
data:'var=' + $('#myDiv').html(),
type:'GET'
success:function(response) {
console.log(response) // Your response
},
error:function(error) {
console.log(error) // No successful request
}
});
In your script.php you could do something like this:
$var = $_GET['var'];
// Do some processing...
echo 'response';
and in your javascript console the string response would occur.
In modern ajax based applications the best practise way to send and receive data is through JSON.
So to handle bigger datasets in your requests and responses you do something like this:
$.ajax({
url:'http://example.com/script.php',
data:{
var:$('#myDiv').html()
},
type:'GET'
success:function(response) {
console.log(response) // Your response
},
error:function(error) {
console.log(error) // No successful request
}
});
And in your PHP code you can use the $someArray = json_decode($_GET['var']) to decode JSONs for PHP (it will return an associative array) and $jsonString = json_encode($someArray) to encode an array to a JSON string which you can return and handle as a regular JSON in your javascript.
I hope that helps you out.

You can use hidden form fields and use jQuery to set the value of the hidden field to that, so when the button is clicked and form submitted, your PHP can pick it up as if it were any other form element (using $_POST). Alternatively, you can use AJAX to make an asynchronous request to your PHP page. This is probably simpler. Here's an example:
$("#myButton").click(function() {
var htmlStr = $('#myDiv').html();
$.post("mypage.php", { inputHTML : htmlStr },
function(data) {
alert("Data returned from mypage.php: " + data);
});
}

Yes, Its possible
<script type="text/javascript">
$(document).ready(function(){
$('#MyButton').click(function(){
$.post('sendinfo.php',
{
data: $('#data').html()
},
function(response){
alert('Successfully');
});
});
});
</script>
<div id="data">Here is some data</div>

Use ajax for sending value to php (server).. here's a good tutorial for ajax with jquery http://www.w3schools.com/jquery/jquery_ajax.asp

you should just use Ajax to send your variable.
$.ajax({
url:'whateverUrl.php',
type:'GET',
data:{
html : htmlStr
}
});

Using AJAX:
$("#MyButton").click(function() {
var htmlStr = $("#MyDiv").html();
$.ajax({
url: "script.php",
type: "POST",
data: {htmlStr : htmlStr},
success: function(returnedData) {
//do something
}
});
});

Something like below should work.
Read more: http://api.jquery.com/jQuery.post/
$("#YourButton").click(function(e){
e.preventDefault();
var htmlStr = $("#YourDiv").html();
$.post(
url: 'YourPHP.php',
data: '{"htmlStr" : "'+htmlStr+'"}',
success: function(){
alert("Success!");
}
);
});

Send the data via XmlHttpRequest ("ajax") to your php page either via POST or GET.

Related

send data by Jquery ajax to same php

i need help because i'm stuck and don't know what's wrong ,i try to send user clicked button "id" to php to get related data from database in the same page
$(".button_class").on("click", function() {
ToEditId = $(this).attr('id');
console.log(ToEditId ); //to check clicked id is Ok
$.ajax({
type: "POST",
url: same/php/page/path,
data: {
ToEditId: ToEditId
},
success: function(res, data) {
console.log(res, data);
},
error: function(err) {
alert(err);
}
});
});
the ajax print success in console log ,here is php code to get the value if clicked id
<?php
if(isset($_POST['ToEditId'])){
$to_edit_id=$_POST['ToEditId'];
var_dump($to_edit_id);
}
but nothing happen in php file !!
Which is the expected behaviour.
PHP is not dynamic. It doesn't "update".
PHP only runs once. This means that once your page is rendered, you cannot use PHP to change it again. You actually would have to use javascript to change the page, like so;
PHP side:
<?php
if(isset($_POST['ToEditId'])){
echo $_POST['ToEditId'];
$to_edit_id=$_POST['ToEditId'];
var_dump($to_edit_id);
die(); // prevent entire page from re-rendering again.
}
JS side:
$(".button_class").on("click", function() {
ToEditId = $(this).attr('id');
console.log(ToEditId ); //to check clicked id is Ok
$.ajax({
type: "POST",
url: same/php/page/path,
data: {
ToEditId: ToEditId
},
success: function(res, data) {
//Add your PHP file's response to the body through javascript.
$('body').append(res);
},
error: function(err) {
alert(err);
}
});
});
As #IncredibleHat mentioned, you should make sure your page doesn't render any of its usual HTML, so it won't return the entire page back to your ajax call. So put the PHP all the way above your html!

How to pass JS object to PHP function

$('.select_category').change(function(){
if($(this).is(':checked')){
var ID = $(this).val();
$.ajax({
url:'<?php echo site_url($this->config->item('admin_folder').'/catalog/get_all_option');?>',
type:'POST',
data:{category_id:1},
dataType: 'json',
success:function(data){
$('#attribute_form').html('<?php add_attribute_form("'+data+'");?>');
}
});
}
});
on callback function success return the data and pass it to add_attribute_form(data) php function but nothing response.
what is the correct way to pass js object to php function
What you will need to do here is, use Ajax to send data to a separate php page passing it some information, then, based on that information, the php page should return data to the Ajax callback function which will add the returned data to the original page.
Here's a simple example (and a working demo here):
In index.html do this:
<script>
$(document).ready(function(){
$('.select_category').change(function(){
if($(this).is(':checked')){
var ID = $(this).val();
$.ajax({
url:'somepage.php',
type:'POST',
data:{category_id:1},
dataType: 'json', // this setting means you expect the server to return json formatted data
// this is important because if the data you get back is not valid json,
// the success callback below will not be called,
// the error callback will be called instead
success:function(response){
$('#attribute_form').html(response.html);
// if not using json, this would just be $('#attribute_form').html(response);
},
error:function(xhr, status, error){
// handel error
}
});
}
});
});
</script>
<input type="checkbox" class="select_category"> Check this box
<div id="attribute_form"></div>
Then in somepage.php do the following:
<?php
$category_id = isset($_POST['category_id']) ? $_POST['category_id'] : null;
if($category_id == '1'){
echo json_encode(array('html'=>'<h1>This text came from the php page</h1>'));
exit;
// if you are not using dataType:json in your ajax, you can just do:
// echo '<h1>This text came from the php page</h1>';
// exit;
}
?>

How to Dynamically change a YouTube video

I have a YouTube player on my page, the src comes from the session $_SESSION['video']['code'] which contains the YouTube video id.
I need it to change video when the PHP session is updated without reloading the page. Preferably with Jquery, but I'm open to others. My current code is below.
$(document).ready(function(){
refresTa();
});
function refresTa(){
$('.now_playing').load('../beta.php', function(){
setTimeout(refresTa, 1000);
});
}
The problem with it is it keeps refreshing the video, making it unplayable. is there a better way of doing this?
Instead of using .load() on .now_playing, fetch the data from PHP elsewhere, and call refresTa() only when needed. Something like this:
$(document).ready(function(){
myCheck();
});
function myCheck() {
$.ajax({
url: "ajax.php",
dataType: "json"
}).done(function(data) {
var myData = data.myData;
// do something based on data received
// call this function again
setTimeout(function(){
myCheck();
}, 10000); // every 10 seconds
});
}
In ajax.php, you can output the data back to Javascript with json_encode():
$returnArray = array("myData"=>$data);
exit(json_encode($returnArray));

Why does PHP response to AJAX contains <script> aBunchOfJavascriptHere </script>?

I'm trying to figure this out from 2 hours with no luck, maybe it's not that technical but I need help!
I've an AJAX script that needs to send a GET request to a php script that's on the same page.
The PHP script terminates like this
if ($success) {
print( $state );
}?>
The Javascript is rightly under the php termination and is this.
<script>
$('table button').click( function() {
var button = $(this);
/* if button inside the table is clicked */
var username = button.parent().parent().children('td').html();
var state = button.html();
/* send GET request */
$.ajax({
type: "GET",
url: 'index.php',
data: 'username='+username+'&state='+state,
success: function(response) {
alert(response);
}
});
});
</script>
What I don't understand is why I get the alert containing this text
inside // this is the state, so it's good
<script> // this is the script, not good
$('table button').click( function() {
var button = $(this);
/* if button inside the table is clicked */
var username = button.parent().parent().children('td').html();
var state = button.html();
/* send GET request */
$.ajax({
type: "GET",
url: 'index.php',
data: 'username='+username+'&state='+state,
success: function(response) {
alert(response);
}
});
});
</script>
I've to manipulate the HTML on success by I'm not able to do that because of the messy response that I get from my php code. I'm not sure if I've to post other code. If you need to know more just ask, I'll reply as soon as possible.
Any characters outside <?php ?> tags are sent back in the response. That's how you get that <script> tag in the first place when you access index.php from the browser.
echo and print are obviously going to also send data.
So I guess you should have that if($success) at the begining of index.php and exit; inside it, after print.
Characters outside <?php ?> tags are sent as part of the response for historical and practical reasons.
In our days having PHP code mixed with HTML is a bad practice (as some people already pointed out in the comments bellow). You either use a templating engine (most people know about Smarty) or use PHP itself as a templating engine.
But "back in the day" PHP started out as just a simple templating engine (no classes, external modules, namespaces, autoloaders, etc.), so mixing HTML with PHP was basically the purpose of this language.
As I said, today we still use PHP as a templating language so mixing PHP (control structures, loops) and HTML works.
A quick, but not recommended fix is to avoid the javascript content on an ajax request
Just demonstrating, how it could be,
if($success) {
print( $state );
}
if(!isset($_GET['ajax_call']))
{ ?>
<script>
$('table button').click( function() {
var button = $(this);
/* if button inside the table is clicked */
var username = button.parent().parent().children('td').html();
var state = button.html();
/* send GET request */
$.ajax({
type: "GET",
url: 'index.php?ajax_call=1',
data: 'username='+username+'&state='+state,
success: function(response) {
alert(response);
}
});
});
</script>
<?php
}?>
.....
and you should note that the new ajax call has an additional variable, ajax_call,
This is a quick fix, for you to move on, but i suggest you to use an MVC framework.

My ajax/jquery script to send $_GET to php isn't working? (Wordpress)

This is the code that I'm using to send a variable (via GET) to another php file:
(basically, I click on a button, and then js gets the id and sends the id via ajax to the php file.
$(document).ready(function() {
$(".doClick").click(function() {
var category=$(this).attr('id');
$.ajax({
url:'aFile.php',
type:'GET',
data: $category,
success: function(data){
alert("It worked?"); // this is the response
}
});
alert($(this).attr("id"));
});
});
This is the code in my aFile.php:
The php file gets the info via $_GET[] and then assigns it to a variable and uses that variable in a function call.
<head>
<script type="text/javascript">
$(document).ready(function() {
function JS() {
//code
});
</script>
</head>
<body onload="JS()">
<?php
$category = $_GET['category'];
if (function_exists('inventory_insert')) {
echo inventory_insert('{category_name = '.$category.'}');
} else echo('warning');
?>
It's supposed to give me a response back on my main page, but nothing seems to be happening. I don't even get the alert I posted after the ajax script.
your variable is category but you're sending data: $category
You must send key/value pair to server
to receive $_GET['category'] your data sent in ajax needs to be either:
data: 'category='+category
Or
data: {category: category}
You have assigned id into category in jquery. so correct in data params.
data: {category : category},
Send it in this way to server or php file.
$(document).ready(function() {
$(".doClick").click(function() {
var category=$(this).attr('id');
$.ajax({
url:'aFile.php',
type:'GET',
data: {category : category},
success: function(data){
alert("It worked?"); // this is the response
}
});
alert($(this).attr("id"));
});
});

Categories