Displaying image as image gallery using PHP derived from phpmyadmin(MySQL) - php

I am using PHP, HTML, and MySQL to build a website.
So, my goal is to make an image gallery for my webpage which should display only 3 images each row.
But my code seems wrong and I do not know where should I do the correction.
-) Here is my code:
$query = mysql_query("SELECT DISTINCT * FROM products WHERE catID = 11 ORDER BY typeID ASC");
echo "<table>";
while ($row = mysql_fetch_assoc($query))
{
echo "<tr>";
for ($c = 0; $c < 3; $c += 1){
echo "<td>";
echo '<img src="data:image/jpg;base64,'.base64_encode($row['productImg'] ).'" width="300" height="200" alt=""
/>';
echo "<br>";
echo "<b>";
echo $row['productName'];
echo "</b>";
echo "<br>";
// More detail button set up
?>More Detail <i class="fa fa-arrow-circle-o-right"></i> <?php
echo "</td>";
}
echo "</tr>";
}
echo "</table>";
-) Here is the result:
wrong result image
The result turns out not what I expected since on 1 row it displays 3 same images. What I wanted is to display 3 different images on each
row. I do not know where I did wrong.

The result turns out not what I expected since on 1 row it displays 3 same images.
That's because of the for loop, you are looping through the same image three times. Instead use a counter variable $counter to track number of iterations and display three different images per row.
<?php
$query = mysql_query("SELECT DISTINCT * FROM products WHERE catID = 11 ORDER BY typeID ASC");
if(mysql_num_rows($query)){
$counter = 0;
echo "<table><tr>";
while ($row = mysql_fetch_assoc($query)) {
if($counter != 0 && $counter % 3 == 0){
echo "</tr><tr>";
}
echo "<td>";
echo '<img src="data:image/jpg;base64,'.base64_encode($row['productImg'] ).'" width="300" height="200" alt=""/>';
echo "<br>";
echo "<b>";
echo $row['productName'];
echo "</b>";
echo "<br>";
// More detail button set up
?>
More Detail <i class="fa fa-arrow-circle-o-right"></i>
<?php
echo "</td>";
++$counter;
}
echo "</tr></table>";
}
?>
Sidenote: Don't use mysql_* functions, they are deprecated as of PHP 5.5 and are removed altogether in PHP 7.0. Use mysqli or pdo instead. And this is why you shouldn't use mysql_* functions.

Related

Multiple Tables of same Database on the same site

I want to display 9 different tables from my sql database in 9 different html created tables on the website.
In detail: I have 9 tables ("dt_bookmarks_01", "dt_bookmarks_02" etc.) with 4 columns "id" (which is primary and auto increment), icon (for favicon), link (url) and text (for the display text).
I've created 9 different html tables with bootstrap and want to output the content of each table in a different bootstrap table of my site.
My problem is that i have no idea how to get different "foreaches" or counter for each different table.
To automaticaly add new rows to the bootstrap table I use the count and foreach function. problem here is: I dont know how to seperate them from each other. If i have 4 entries in sql table 1 it multiplies the one and only entrie of sql table 2 to match the current count of 4.
I am very new to sql and php so I guess I just miss some fundamental functions or something.
document header:
php
$sql = "
SELECT *
FROM dt_bookmarks_01, dt_bookmarks_02";
$result = mysqli_query($conn, $sql);
while ($row = mysqli_fetch_assoc($result)) {
$rows[] = $row;
}
$conn->close();
and for the html table I use:
php
<tbody>
<!--begin: SQL Selection -->
<?PHP
$count = 0;
foreach($rows as $item){
if (!empty($item['icon'])) {
$icon = '<img src="assets/media/bm-icons/'. $item['icon'] . '">';
}else{
$icon = '<img src="assets/media/bm-icons/default.png">';
}
$count++;
echo "<tr>";
/*echo "<td>" . $count . "</td>";*/
echo "<td> " . $icon . "</td>";
echo "<td> <a href=\"" . $item['link'] . "\"'>" . $item['text'] . "</a> </td>";
echo "<td></i> ";
echo "</i></td>";
echo "</tr>";
}
?>
<!--end: SQL Selection -->
</tbody>
I do not have a database on hand to give you an answer with complete code, but here is the idea:
<?php
for ($i = 1; $i <= 9; $i++)
{
$query = "SELECT index1,index2 FROM dt_bookmarks_0$i";
echo "<h1>This is the content of table $i</h1>";
# RUN THE QUERY HERE !!!
echo "<table>";
# EXTRACT THE RESULTS
foreach $rows as $item
{
echo "<tr><td>$item[index1]</td><td>$item[index2]</td></tr>"
}
echo "</table>";
echo "<br><br>";
}
?>
Loop on your tables.
In each table loop, you output the HTML code to display it's content.
Avoid SELECT *, specify your indexes (research "sql why avoid SELECT *")
So you loop twice. One time to go through the tables, the other to loop on the results.
so here is the new working code.
header:
<?PHP
require_once('/htdocs/_nt/mysql/data.php');
$sql = "
SELECT *
FROM dt_bookmarks";
$result = mysqli_query($conn, $sql);
while ($row = mysqli_fetch_assoc($result)) {
$rows[] = $row;
}
$conn->close();
?>
and for the table output:
<?PHP
$count = 0;
foreach($rows as $item){
if ($item['category'] == talk) {
$count++;
echo "<tr>";
echo "<td> " . $icontalk . "</td>";
echo "<td> <a href=\"" . $item['url'] . "\"'>" . $item['text'] . "</a> </td>";
echo "</tr>";
}else{
echo "";
}
}
?>

Displaying 2 records in a column using php

So I have a code
<?php
$showorder = "SELECT order_number FROM orders WHERE customer_number=522";
$orderesult = mysqli_query($con, $showorder);
$ord = mysqli_fetch_array($orderesult);
?>
in my database customer number 522 has 2 order numbers, when i tried to show the result, it only shows 1.
Here's my other code
echo "<table>";
echo "<th>Order Number</th><th>Order date</th>";
echo "<tr><td>";
echo $ord["order_number"];
echo "</td><td>";
echo $ord["order_date"];
echo "</td></tr>";
You just need to use while() here for getting all records, something like:
while($ord = mysqli_fetch_array($orderesult)){
//echo all value here
}
Also note that, if you want to print $ord["order_date"] than you must need to select column also in your query.
Otherwise, $ord will only contain order_number value.
Your SQL is missing the extra column.
Current SQL:
SELECT order_number FROM orders WHERE customer_number=522
Change to:
SELECT order_number, order_date FROM orders WHERE customer_number=522
Put mysqli_fetch_array($orderesult); in a while loop.
while($ord = mysqli_fetch_array($orderesult)) {
echo $ord["order_number"];
# code
}
Replace your code with the below code and then try again
<?php
$showorder = "SELECT order_number, order_date FROM orders WHERE customer_number=522";
$orderesult = mysqli_query($con, $showorder);
echo "<table>";
echo "<tr>";
echo "<th>Order Number</th><th>Order date</th>";
echo "</tr>";
while($ord = mysqli_fetch_array($orderesult)) {
echo "<tr>";
echo "<td>$ord['order_number']</td>";
echo "<td>$ord['order_date']</td>";
echo "</tr>";
}
echo "</table>";
?>
echo "<table>";
echo "<th>Order Number</th>";
while($ord = mysqli_fetch_array($orderesult)) {
echo "<tr><td>";
echo $ord["order_number"];
echo "</td></tr>";
}
you must use loop to show all result , and you can use echo one time .
while($ord = mysqli_fetch_array($orderesult)) {
echo "<table>
<th>Order Number</th><th>Order date</th>
<tr><td>".
$ord["order_number"]."
</td></tr>";
}

Splitting Long php generated HTML table?

I use a MySql query to select data from my DB and then print it in the form of a HTML Table. It works perfectly, fine but sometimes the table consists of hundreds of rows and the webpage looks incredibly akward. Is there a way to split the table side by side into 2 or 3 halves.
Present Output
Desired output
PHP
<?php
....
echo "<h3>Classes attended :</h3>";
echo "<table class='dates' border='1'>";
foreach ($results as $dates) {
echo "<tr><td width='50%'>";
echo $dates->db_date;
echo "</td>";
echo "<td width='50%'>";
echo $dates->day_name;
echo "</td>";
echo "</tr>";
}
echo "</table>";
?>
What would be the best way to achieve it?
Help would be appreciated.
You can use PHP to determine in your loop if the loop index is divisible by a certain number using something like this:
echo "<h3>Classes attended :</h3>";
echo "<table class='dates' border='1'>";
$rowCount = 1;
$numRows = count($results);
$maxRows = 12;
foreach ($results as $dates) {
echo "<tr><td width='50%'>";
echo $dates->db_date;
echo "</td>";
echo "<td width='50%'>";
echo $dates->day_name;
echo "</td>";
echo "</tr>";
if($rowCount % $maxRows == 0 && $rowCount != $numRows) {
echo "</table><table class='dates' border='1'>";
}
$rowCount ++;
}
echo "</table>";
That's the basics of doing this. Basically in your loop you're testing each index to see if it's divisible by $maxRows, and if so then you're going to close your table and open a new one. You'll have to add the styling to place the tables side by side.
If you wanted to expand upon this concept you can set $maxRows to be an evaluation of $numRows. For instance if you wanted to split the items as close as possible to half in order to show just two tables, you could do... $numRows = count($results); $maxRows = round($numRows / 2);
Inspired by Robert Wade's answer:
<?php
....
echo "<h3>Classes attended :</h3>";
$i=0;
$maxRows=10;
foreach ($results as $dates) {
$a=$i/$maxRows == 0 ? "<table class='dates' border='1'>":"";
$b=$i/$maxRows == 0 ? "</table>":"";
echo $a;
echo "<tr><td width='50%'>";
echo $dates->db_date;
echo "</td>";
echo "<td width='50%'>";
echo $dates->day_name;
echo "</td>";
echo "</tr>";
echo $b;
$i++;
}
?>
At last, add some css style to the tables.
You can also use array_chunk() for splitting your results. Or instead of displaing a lot of tables next to each other you can make pagination and get only some range in your query. For example:
SELECT * FROM `clients` LIMIT 5, 10
Selects 10 rows beggining from row 5. Now, when you change your page, just change limit values.

Printing table with div to create delete section

The code I am posting below, iterates through a result set and prints elements (paths to images on database) so that images display in order. Only 3 images per row. I want to be able to have the same concept (i.e. 3 images or cells per row) but I want to have another div underneath it to have the word delete photo.
$n = 3;
echo "<table style='margin-right: 100px;'>";
echo "<tr>";
for($i=1; $i<=count($gallery);$i++){
$temp = array();
$temp = $gallery[$i-1];
echo "<td><div id='gallery_pic'><img id='single_pic' src='". $temp->path . "' /></div></td>";
if($i % $n ==0){
echo "</tr><tr>";
}
}
echo '</tr>';
echo '</table>';
echo "</table>";
The idea is that owner of profile should be able to delete photo by clicking it. I will handle that I am just not sure how to handle printing the table with same order by adding another row per row with delete word.
Simple. Add a new div right after div#gallery_pic and give it a width of 100%, this will force it to be below the image...
echo "<table style='margin-right: 100px;'>";
echo "<tr>";
for($i=1; $i<=count($gallery);$i++){
$temp = array();
$temp = $gallery[$i-1];
echo "<td><div id='gallery_pic'><img id='single_pic' src='". $temp->path . "' /></div><div class='delete_wrap'><a href='?delete_id=" . {image_id} . " style='width:100%'>Delete</a></div></td>";
if($i % $n ==0){
echo "</tr><tr>";
}
}
echo '</tr>';
echo '</table>';
echo "</table>";

SQL Image Database assembling rows into HTML cells and rows

I have a database of images which I want to output as a gallery ...
I want to display each image in its own cell <td>image1</td> and limit the number of cells to 7 per row.
<tr>
<td>image1</td><td>image2</td><td>image3</td><td>image4</td><td>image5</td><td>image6</td><td>image7</td>
</tr>
Then a new row would be created and continue to output all the images.
<tr>
<td>image8</td>
and so on ..
I know how to do a query, but I am lost as to how to assemble the rows into the format I am looking for.
Can anyone please help me it would be greatly appreciated. Thanks.
First run your query, then get the mysql_fetch_assoc in a variable. Then echo your beginning tags for the table and tr. Then create a foreach loop of the query assoc, as another variable such as row, and echo $row['image'] in a td. This will add a new td with the image for every entry in the database. Then echo your closing tags for the tr and table.
$query = mysql_query("SELECT image FROM table_name");
$query_a = mysql_fetch_assoc($query);
echo "<table><tr>"
foreach ($query_a as $row)) {
echo "
<td>" . $row['image'] . "</td>
";
}
echo "</tr></table>";
Not tested, but try something like this
<table>
<?php
// make sure there is at least 1 row first
$cnt = 0;
$while($row = mysql_fetch_assoc($query))
{
if(++$cnt == 1) {
echo '<tr>';
} elseif($cnt % 7 == 0) {
echo '</tr><tr>';
}
// show images in <td>'s
echo "<td>" . $row['image']. "</td>";
}
echo '</tr>';
?>
</table>
Keep it simple:
Query the database to get the desired information, loop through the results, construct a new row come each new loop.
$sql = "Select * from table";
mysql_query($sql) or die(mysql_error());
if(mysql_num_rows !=0)
{
// Found at least one record, create table
echo "<table>";
echo "<tr>";
while($row = mysql_fetch_assoc($sql)
{
$cell_count = 0;
// Create a new row for each record found
echo "<td>" . $row['image_column']. "</td>";
$cell_count++;
if($cell_count == 7)
{
echo "</tr>";
echo "<tr>";
$cell_count = 0;
}
}
// Close the table
echo "</tr>";
echo "</table>";
}

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