Multiple Tables of same Database on the same site - php

Question

I want to display 9 different tables from my sql database in 9 different html created tables on the website.
In detail: I have 9 tables ("dt_bookmarks_01", "dt_bookmarks_02" etc.) with 4 columns "id" (which is primary and auto increment), icon (for favicon), link (url) and text (for the display text).
I've created 9 different html tables with bootstrap and want to output the content of each table in a different bootstrap table of my site.
My problem is that i have no idea how to get different "foreaches" or counter for each different table.
To automaticaly add new rows to the bootstrap table I use the count and foreach function. problem here is: I dont know how to seperate them from each other. If i have 4 entries in sql table 1 it multiplies the one and only entrie of sql table 2 to match the current count of 4.
I am very new to sql and php so I guess I just miss some fundamental functions or something.
document header:
php
$sql = "
SELECT *
FROM dt_bookmarks_01, dt_bookmarks_02";
$result = mysqli_query($conn, $sql);
while ($row = mysqli_fetch_assoc($result)) {
$rows[] = $row;
}
$conn->close();
and for the html table I use:
php
<tbody>
<!--begin: SQL Selection -->
<?PHP
$count = 0;
foreach($rows as $item){
if (!empty($item['icon'])) {
$icon = '<img src="assets/media/bm-icons/'. $item['icon'] . '">';
}else{
$icon = '<img src="assets/media/bm-icons/default.png">';
}
$count++;
echo "<tr>";
/*echo "<td>" . $count . "</td>";*/
echo "<td> " . $icon . "</td>";
echo "<td> <a href=\"" . $item['link'] . "\"'>" . $item['text'] . "</a> </td>";
echo "<td></i> ";
echo "</i></td>";
echo "</tr>";
}
?>
<!--end: SQL Selection -->
</tbody>

Answer 1

I do not have a database on hand to give you an answer with complete code, but here is the idea:
<?php
for ($i = 1; $i <= 9; $i++)
{
$query = "SELECT index1,index2 FROM dt_bookmarks_0$i";
echo "<h1>This is the content of table $i</h1>";
# RUN THE QUERY HERE !!!
echo "<table>";
# EXTRACT THE RESULTS
foreach $rows as $item
{
echo "<tr><td>$item[index1]</td><td>$item[index2]</td></tr>"
}
echo "</table>";
echo "<br><br>";
}
?>
Loop on your tables.
In each table loop, you output the HTML code to display it's content.
Avoid SELECT *, specify your indexes (research "sql why avoid SELECT *")
So you loop twice. One time to go through the tables, the other to loop on the results.

Answer 2

so here is the new working code.
header:
<?PHP
require_once('/htdocs/_nt/mysql/data.php');
$sql = "
SELECT *
FROM dt_bookmarks";
$result = mysqli_query($conn, $sql);
while ($row = mysqli_fetch_assoc($result)) {
$rows[] = $row;
}
$conn->close();
?>
and for the table output:
<?PHP
$count = 0;
foreach($rows as $item){
if ($item['category'] == talk) {
$count++;
echo "<tr>";
echo "<td> " . $icontalk . "</td>";
echo "<td> <a href=\"" . $item['url'] . "\"'>" . $item['text'] . "</a> </td>";
echo "</tr>";
}else{
echo "";
}
}
?>