I made a query that user can see all the post of active users but not of those inactive, but also they should not see the post of users they blocked or blocked them how can I do that?, the block_users table has block_by_userid and blocked_userid column.
I tried INNER JOIN the post table with members table which every inactive users post cannot be seen anymore., How will I combine the block_users table?
$GetPost = "SELECT Post.* FROM Post
INNER JOIN Members ON Post.Poster_user_id = Members.User_id
WHERE Status='active'";
you might try FULL OUTER JOIN
the idea it to get all items in both tables member and block_users and then filter the data using where clause, i am sorry if i miss using the fields name , so please check the tables names, i assume block_users.block_by_userid contained the blocked user id if not use the correct field
$GetPost = "SELECT Post.* FROM Post
INNER JOIN Members ON Post.Poster_user_id = Members.User_id
FULL OUTER JOIN block_users ON Members.User_id = block_users.user_id
WHERE Status='active'
AND
WHERE block_users.block_by_userid != Members.User_id";
Suppose I am doing this for a user xyz whose user_id is 123 then below is a query which will return expected output for user 123.
Query:
SELECT Post.* FROM Post
INNER JOIN Members ON Post.Poster_user_id = Members.User_id
WHERE Status='active' and post.poster_user_id NOT IN(select block_by_userid from block_users where blocked_user_id = 123 UNION select blocked_user_id from block_users where block_by_userid = 123)
Related
I've tried to get data from from one table if id of 2 tables equals to each other. Here is the code which I used:
SELECT id_to
, email_to
, name_to
, status_to
FROM users
LEFT
JOIN friends
ON users.id = friends.id_from
WHERE id_from = ?
I used LEFT JOIN to join two tables but it gets the values from the friends(table) instead of users(table).
I think I've explained my problem clearly.
I guess you must specify it on your query, like this:
SELECT users.id_to, users.email_to, users.name_to, user.status_to FROM users LEFT JOIN friends ON users.id = friends.id_from WHERE id_from = ?
You can do the same if you need to retrieve values from 'friends' table.
If both tables have the same column, then you can specify the table name while selecting columns. so your code will look like:
SELECT users.id_to, users.email_to, users.name_to, user.status_to FROM users LEFT JOIN friends ON users.id = friends.id_from WHERE friends.id_from = ?
table posts
table users
how would i count posts for specific user logged in. for example when user with id 3 is logged in it should show me 4 posts
I already did it for total posts count:
<?php
$post_query1 = "SELECT count(*) AS total FROM posts ";
$post_result1 = mysqli_query($db, $post_query1);
$post1 = mysqli_fetch_array($post_result1);
?>
Try below example :
select count(*) as total from user as u inner join post as p on p.id_user = u.id_user AND u.id_user = 3
If you want to get only the posts count for the particular user, say user with id = 3, your query should be this:
$query = "SELECT count(*) AS total FROM posts WHERE id_users = 3";
But if you want to get both the posts count as well as the user information and other post information, you will have to run a join query on both the users and posts table. Your query would now become:
$query = "SELECT u.*, p.*, count(p.id_posts) FROM users AS u JOIN posts AS p ON u.id_users = p.id_users WHERE p.id_users = 3";
Some Useful Notes
p.* - * is a wildcard character that means get all the columns in the posts table
u.* - * is a wildcard that means get all the columns in the users table
posts as p - AS is for aliasing. So, we are giving posts table a temporary name.
Here are the different types of the JOINs in SQL:
(INNER) JOIN: Returns records that have matching values in both tables
LEFT (OUTER) JOIN: Return all records from the left table, and the matched records from the right table
RIGHT (OUTER) JOIN: Return all records from the right table, and the matched records from the left table
FULL (OUTER) JOIN: Return all records when there is a match in either left or right table
Note: It is necessary that you have to join two/more tables only with the help of foreign key. Without the foreign key is is meaningless to join two or more tables
Reference 1: https://www.w3schools.com/sql/sql_join.asp
Reference 2: https://www.tutorialspoint.com/mysql/mysql-using-joins.htm
As per the Question what you have asked to join the tables
Query:
SELECT * FROM TABLE 1 JOIN TABLE 2 ON TABLE1.id = TABLE2.id WHERE TABLE2.ID=3
Kindly replace TABLE1 & TABLE2 with the Tables that are to be joined and the id with the foreign key what you have specified in the Table.
Hope so this might be helpful for you to write your own code in future. Happy Coding :)
You have only to use a simple join.
SELECT count(*)
FROM USER u,
post p
WHERE p.id_user = u.id_user
AND u.id_user = 3
I have two tables: publick_feed and users
I want to SELECT all from public_feed and also SELECT a three columns from users whose id is the same of user_id in public_feed
and assign the rows returned from public_feed to the column in users table ( correspondent)
I try this:
<?php
$sql = "
SELECT * FROM public_feed
WHERE user_id IN
(SELECT id FROM users) AND
(SELECT Firstname,Lastname,Avatar FROM users WHERE id IN(SELECT user_id FROM public_feed))
";
$query = mysqli_query($dbc_conn,$sql);
if(mysqli_num_rows($query) > 0){
while($row = mysqli_fetch_assoc($query)){
//echo rows with correspondent details from the users table
echo $row['user_id'];
}
}
<?
Please any help will be much appreciated.
Thank you.
Or version with left join in case if there is no user in public_feed, and you still want to fetch user data
SELECT
u.*, f.*
FROM
public_feed f LEFT JOIN
users u ON f.user_id = u.id;
Because author asked for explanation, here it is:
First we are going to use table name alias to make query shorter
public_feed f
and
users u
we are saying that want to refer to tables with an alias. Of course * means that we want to select all columns
SELECT users.*, public_feed.*
is equal to
SELECT u.*, f.*
Of course you can use any other letters as an alias
Next we are saying that public_feed.user_id must be equal to users.id. But when public feed entry does not exists just display columns with null values. This is why we are using LEFT JOIN instead of INNER JOIN. In general JOINS are used to fetch related data from more than one related tables.
ON keyword is saying values from which columns in the tables must be equal to satisfy the request
I think doing a join would be cleaner than using a complicated subquery:
SELECT u.Firstname,
u.Lastname,
u.Avatar,
COALESCE(pf.User_id, 'NA'),
COALESCE(pf.Post, 'NA'),
COALESCE(pf.Date, 'NA')
FROM users u
LEFT JOIN public_feed pf
ON u.Id = pf.User_id
I chose a LEFT JOIN of users against public_feed on the assumption that every feed will have an entry in the users table, but not necessarily vice-versa. For those users who have no feed entries, NA would appear in those columns and that user would appear in only a single record.
i need help getting data from different tables and insert into other different table Here are the Queries
"SELECT commentID, date, comment, subject, parentID, aBUserID FROM comments WHERE status = 'APPROVED'"
"SELECT topicID, subForumID, aBUserID, lastPostID, views, replies, startDate FROM topic WHERE status = 'APPROVED' AND topicID = $parentid";
// $parentID need to be matched from above query parentID,
"SELECT userName FROM users WHERE aBUserID = $cmtaBUserID";
// $cmtaBUserID = aBUserID from first query
"SELECT userName FROM users WHERE aBUserID = $topicaBUserID";
//$topicaBUserID = aBUserID from second query
Last 2 queries are from same table but using different where clause
i used different inner join left join from solutions posted here but non of these worked for me stuck since last 2 weeks please help
PS data from all above Queries will be inserted to a single table i need these to be combined so i can have them all in one place
If you want to perform the operation in same query use 'OR'
"SELECT userName FROM users WHERE aBUserID = $cmtaBUserID OR aBUserID = $topicaBUserID";
Please try this
SELECT userName from users where aBUserID IN(SELECT aBUserID FROM comments WHERE status = 'APPROVED')
Couldn't test it but Maybe this is what you are looking for.
SELECT c.commentID, c.date, c.comment, c.subject, c.parentID, c.aBUserID,
t.topicID, t.subForumID, t.aBUserID, t.lastPostID, t.views, t.replies, t.startDate,
u.userName
FROM
comments c
left outer join topic t on t.topicID = c.parentID
left outer join users u on u.aBUserID = c.aBUserID and u.aBUserID = t.aBUserID
WHERE
c.status = 'APPROVED' and t.status = 'APPROVED';
try this:
SELECT
comment.[commentID],
comment.[date],
comment.[comment],
comment.[subject],
comment.[parentID],
comment.[aBUserID],
commentuser.[userName],
topic.[topicID],
topic.[subForumID],
topic.[aBUserID],
topic.[lastPostID],
topic.[views],
topic.[replies],
topic.[startDate],
topic.[userName]
FROM comments comment
LEFT OUTER JOIN users commentuser
ON commentuser.aBUserID = comment.[aBUserID]
LEFT OUTER JOIN
(
SELECT
t.[topicID],
t.[subForumID],
t.[aBUserID],
t.[lastPostID],
t.[views],
t.[replies],
t.[startDate],
u2.[userName] --user from users table joined to topics table
FROM topic t
LEFT OUTER JOIN users u
ON u.aBUserID = t.[aBUserID]
WHERE t.[status] = 'APPROVED'
) topic
ON topic.topicID = comment.parentID
WHERE comment.[status] = 'APPROVED'
Hi all!
I'm scripting a guestbook (personalized for each user). I have one table for users and a different one for the guestbook. Now, the way I'm currently displaying the name of the author of a post is not optimal. I simply have a row in the DB for "fromname" i.e the authors name.
I would like to select the authors name based on the authors ID and matching that to their name in the "users" table.
So... This is my mysql query right now:
$sql = " SELECT
pid,toid,fromid,message,fromname,name,pdate,flag
FROM gbook INNER JOIN users
ON id='{$_GET['id']}'
WHERE toid='{$_GET['id']}'
ORDER BY pdate DESC";
I guess I need to like... Select the name on a different condition but in the same query. But I don't know how.
I hope you understand my problem.
Help will be greatly appreciated!
/Jafool
Assuming your users table has a column called username, the following should do what you want:
SELECT
pid,
toid,
fromid,
message,
u.username,
name,
pdate,
flag
FROM gbook INNER JOIN users u
ON id='{$_GET['id']}'
WHERE toid='{$_GET['id']}'
ORDER BY pdate DESC"
All I did was alias the user table (as u), and refered to u.username instead of the fromname you had before.
From what I am seeing it looks like you need to link to the users table twice since you have a fromid and a toid. If you have a users table, why would you have a fromname field in the gbook table? Anyway if my assumption is correct then you may be interested in the following query:
SELECT g.*, u1.username AS ToUser, u2.username AS FromUser
FROM gbook AS g
INNER JOIN users AS u1 ON u1.id = g.toid
INNER JOIN users AS u2 ON u2.id = g.fromid
WHERE g.toid = '{$_GET['id']}'
ORDER BY g.pdate DESC
Hard coding the name in the guestbook table is indeed dirty. Assuming your table structure is something like this:
users( id, name )
gbook( pid, toid, fromid, message, fromname, name, pdate, flag )
your query is already almost ok. Just change it as follows to select all columns of both tables:
$sql = " SELECT *
FROM gbook g INNER JOIN users u
ON u.id=g.fromid
WHERE toid='{$_GET['id']}'
ORDER BY pdate DESC";
Then you can display the name with something like
$result = mysql_query($sql);
while( $val = mysql_fetch_array($result) )
{
$username = $val["u.name"];
}