I have two tables: publick_feed and users
I want to SELECT all from public_feed and also SELECT a three columns from users whose id is the same of user_id in public_feed
and assign the rows returned from public_feed to the column in users table ( correspondent)
I try this:
<?php
$sql = "
SELECT * FROM public_feed
WHERE user_id IN
(SELECT id FROM users) AND
(SELECT Firstname,Lastname,Avatar FROM users WHERE id IN(SELECT user_id FROM public_feed))
";
$query = mysqli_query($dbc_conn,$sql);
if(mysqli_num_rows($query) > 0){
while($row = mysqli_fetch_assoc($query)){
//echo rows with correspondent details from the users table
echo $row['user_id'];
}
}
<?
Please any help will be much appreciated.
Thank you.
Or version with left join in case if there is no user in public_feed, and you still want to fetch user data
SELECT
u.*, f.*
FROM
public_feed f LEFT JOIN
users u ON f.user_id = u.id;
Because author asked for explanation, here it is:
First we are going to use table name alias to make query shorter
public_feed f
and
users u
we are saying that want to refer to tables with an alias. Of course * means that we want to select all columns
SELECT users.*, public_feed.*
is equal to
SELECT u.*, f.*
Of course you can use any other letters as an alias
Next we are saying that public_feed.user_id must be equal to users.id. But when public feed entry does not exists just display columns with null values. This is why we are using LEFT JOIN instead of INNER JOIN. In general JOINS are used to fetch related data from more than one related tables.
ON keyword is saying values from which columns in the tables must be equal to satisfy the request
I think doing a join would be cleaner than using a complicated subquery:
SELECT u.Firstname,
u.Lastname,
u.Avatar,
COALESCE(pf.User_id, 'NA'),
COALESCE(pf.Post, 'NA'),
COALESCE(pf.Date, 'NA')
FROM users u
LEFT JOIN public_feed pf
ON u.Id = pf.User_id
I chose a LEFT JOIN of users against public_feed on the assumption that every feed will have an entry in the users table, but not necessarily vice-versa. For those users who have no feed entries, NA would appear in those columns and that user would appear in only a single record.
Related
table posts
table users
how would i count posts for specific user logged in. for example when user with id 3 is logged in it should show me 4 posts
I already did it for total posts count:
<?php
$post_query1 = "SELECT count(*) AS total FROM posts ";
$post_result1 = mysqli_query($db, $post_query1);
$post1 = mysqli_fetch_array($post_result1);
?>
Try below example :
select count(*) as total from user as u inner join post as p on p.id_user = u.id_user AND u.id_user = 3
If you want to get only the posts count for the particular user, say user with id = 3, your query should be this:
$query = "SELECT count(*) AS total FROM posts WHERE id_users = 3";
But if you want to get both the posts count as well as the user information and other post information, you will have to run a join query on both the users and posts table. Your query would now become:
$query = "SELECT u.*, p.*, count(p.id_posts) FROM users AS u JOIN posts AS p ON u.id_users = p.id_users WHERE p.id_users = 3";
Some Useful Notes
p.* - * is a wildcard character that means get all the columns in the posts table
u.* - * is a wildcard that means get all the columns in the users table
posts as p - AS is for aliasing. So, we are giving posts table a temporary name.
Here are the different types of the JOINs in SQL:
(INNER) JOIN: Returns records that have matching values in both tables
LEFT (OUTER) JOIN: Return all records from the left table, and the matched records from the right table
RIGHT (OUTER) JOIN: Return all records from the right table, and the matched records from the left table
FULL (OUTER) JOIN: Return all records when there is a match in either left or right table
Note: It is necessary that you have to join two/more tables only with the help of foreign key. Without the foreign key is is meaningless to join two or more tables
Reference 1: https://www.w3schools.com/sql/sql_join.asp
Reference 2: https://www.tutorialspoint.com/mysql/mysql-using-joins.htm
As per the Question what you have asked to join the tables
Query:
SELECT * FROM TABLE 1 JOIN TABLE 2 ON TABLE1.id = TABLE2.id WHERE TABLE2.ID=3
Kindly replace TABLE1 & TABLE2 with the Tables that are to be joined and the id with the foreign key what you have specified in the Table.
Hope so this might be helpful for you to write your own code in future. Happy Coding :)
You have only to use a simple join.
SELECT count(*)
FROM USER u,
post p
WHERE p.id_user = u.id_user
AND u.id_user = 3
I have a table with two columns.
created_by | assigned_to
One is the person who create a "to do card", the other column is the person who is assigned to do it.
The columns are filled with id, for example; (1,2,3).
My question is how can i replace this id with the names that are saved in another table.
by far this is what i got.
SELECT tickets.*, users.Name, users.LastName
FROM tickets
LEFT JOIN users ON tickets.assigned_to = users.uid
AND tickets.id_usuario = users.uid
but when i try to print the name of the persona
Created by: <?= query['Name']; ?>
Assigned to: <?= query['Name']; ?>
but i got the same name in both columns.
Your current query only joins to users when the creator and assigned-to user ID are the same.
You'll need to join to your users table twice to retrieve the separate records. You do this by adding more joins...
SELECT
c_users.Name as created_by_name,
c_users.LastName as created_by_last_name,
a_users.Name as assigned_to_name,
a_users.LastName as assigned_to_last_name
FROM tickets t
INNER JOIN users c_users
ON t.created_by = c_users.uid
-- or t.id_usuario = c_users.uid, it is not clear from your question
INNER JOIN users a_users
ON t.assigned_to = a_users.uid
I've used INNER JOIN instead of LEFT JOIN as it doesn't seem feasible that you'd have broken relationships between the two tables.
I need to display details from 2 different tables
Table 1- user table
Table 2-bicycle table
I can show a list of users and bicycle.
But can't show a list that show which bicycle belongs to who.
Bicycle table,
user table
You need to use a LEFT JOIN. The query below will connect your user table to your bicycle table based on the userIDand return all of the bicycle and user fields
SELECT b.*, u.*
FROM registered_users u
LEFT JOIN registered_bicycle b ON (u.userID = b.userID)
If you want specific bicycle fields just prefix them with b. Example:
SELECT b.brand, b.model, b.color...
Click on SQL tab and type this:
SELECT * FROM `registered_bicycle` JOIN `registered_users` ON `registered_users`.`userID` = `registered_bicycle`.`userID`
and run it
You have to make a foreign key from user_table to bicycle_table like this.
user_table has user_id = user_1,name=John Richard
bicycle_table has user_id = user_1,description = Bicycle1
to fetch the data:
select a.user_id, a.name,b.description from
(select user_id, name from user_table) as a
left join
(select user_id,description from bicycle_table) as b
on a.user_id = b.user_id
I'm building a forum, and I have a problem with a SQL select with many joins. I want to show two images of different users in the same row.
The first image of the user is who wrote the topic, and the second image is of the user who last replied.
The query I build:
SELECT
posts.*, users.photo, users.displayname FROM posts
JOIN users ON(posts.useraid = users.id)
JOIN users ON(posts.lastreply = user.id)
WHERE forumid='$forumid' and type='post' ORDER BY `timee` DESC
posts.lastreply = the ID of the last reply user.
You have to specify an alias for each table using the AS keyword:
SELECT posts.*,
u1.photo AS creatorPhoto, u1.displayname AS creatorName,
u2.photo AS replierPhoto, u2.displayname AS replierName
FROM posts
JOIN users AS u1 ON(posts.useraid = u1.id)
JOIN users AS u2 ON(posts.lastreply = u2.id)
WHERE forumid= #forumid and type='post'
ORDER BY `timee` DESC
Notice how I call each instance of the users table by a different name - u1 and u2. Also notice how I have specified a column alias to distinguish between the two columns of the same name (e.g. creatorPhoto and replierPhoto). This way you can use the name as an index into a PHP associative array a la $post['creatorPhoto'].
Yes, I've silently changed your inline variable to a parameter. Take it as a hint. :-D
In addition to the lack of aliases in the from clause you may also have a problem with the where and order by clause. You need to use aliases for the columns there.
I don't know where they come from, but something like:
WHERE posts.forumid='$forumid' and posts.type='post'
ORDER BY posts.`timee` DESC
Assuming all come from posts.
you need an alias for this to work
SELECT
posts.*, u1.photo, u1.displayname, u2.photo, u2.displayname FROM posts
JOIN users u1 ON posts.useraid = u1.id
JOIN users u2 ON posts.lastreply = u2.id
WHERE forumid='$forumid' and type='post' ORDER BY `timee` DESC
SELECT posts.*, author.photo as author_photo, author.displayname as author+name,
replier.photo as replier_photo, replier.displayname as replier_name
FROM posts
JOIN users author ON(posts.useraid = users.id)
JOIN users replier ON(posts.lastreply = user.id)
WHERE forumid='$forumid' and type='post' ORDER BY `timee` DESC
so I'm having trouble selecting a field only if another fields value is not equal to 0.
So, here's what's going on.
I have 3 tables, they are - users, schools, campuses
And basically, I need to select a single users data from these 3 tables. I'd like to only select the campus_name field from campuses if the users.campus_id field is not 0.
So, something pseudo coded like this might give you a better idea..
The query is being passed in a $id variable, that has some user's id.
SELECT users.*, schools.*, (if(users.campus_id != 0) then campuses.campus_name)
FROM users, schools, campuses
WHERE users.id = '$id' (if(users.campus_id != 0) then AND campuses.id = users.campus_id)
SELECT *
FROM schools,
users LEFT OUTER JOIN campuses
ON users.campus_id != 0
AND users.campus_id = campuses.id
WHERE users.school_id = schools.id
So you are joining three tables together, you always expect a user to have a school, but they may not have a campus, and if this is the case, obviously nothing should be displayed.
The best you can do is acheive this with a LEFT JOIN on campuses.
An example based on your pseudo code below:
SELECT u.*, s.*, c.campus_name
FROM users u
INNER JOIN schools s ON u.school_id = s.school_id
LEFT JOIN campuses c ON u.campus_id = c.campus_id
WHERE u.user_id = $userId
If I understood you correctly, you want ALL the information displayed, but to display campus name ONLY if it exists? If so, I believe the following statement should do the trick:
SELECT `u`.* `s`.* if(`c`.`campus_name` != 0, `c`.`campus_name`, "") as `campus`
FROM `users` as `u`
INNER JOIN `schools` as `s` ON `u`.`school_id` = `s`.`school_id`
LEFT JOIN `campuses` as `c` ON `u`.`campus_id` = `c`.`campus_id`
WHERE `u`.`user_id` = $user_id;
Untested, written from the top of my head, could be errors in there