I have this piece of code where I query all the rows of data from my database. In my 1st php, I have this link where I will pass the ID from the row into another php page. Here is my code.
<a class="button3" style="float: left;" onclick="return confirm('Are you sure?');" href="adminEditBillboard.php?edit=<?php echo $row['id']; ?>">Edit</a>
My adminEditBillboard.php has this on a input type text.
<input type="text" class="form-control" value="<?php echo $id; ?>" name="owner" placeholder="Enter billboard owner name">
Do I need to add something? like a method post?
This is from my process.php for the edit.
if(isset($_GET['edit'])){
$id = $_GET['edit'];
$result = $mysqli->query("SELECT * FROM billboards WHERE id=$id") or die($mysqli->error);
if(isset($result->num_rows) && $result->num_rows > 0){
$row = $result->fetch_array();
$owner = $row['owner'];
$location = $row['location'];
$email = $row['email'];
$phone = $row['phone'];
$description = $row['description'];
header("location: adminEditBillBoard.php?edit=$id");
}
Your adminEditBillboard.php should pick the id from the HTTP GET parameters as follows
<input type="text" class="form-control" value="<?php echo $_GET['edit']; ?>" name="owner" placeholder="Enter billboard owner name">
Related
I'm trying to call the old values to be edited. What part am I wrong at?
<?php
if (isset($_GET['edit'])) {
$id = $_GET['edit'];
$update = true;
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$BookNo'");
if (mysqli_num_rows($record) == 1 ) {
$n = mysqli_fetch_array($record);
$BookNo = $n['BookNo'];
$ISBN = $n['ISBN'];
$title = $n['title'];
$author = $n['author'];
$publisher = $n['publisher'];
$status = $n['status'];
$cost = $n['cost'];
}
}
?>
<a href="viewBook.php?edit=<?php echo $row['BookNo']; ?>" class="edit_btn" >Edit</a>
</td>
<?php
if (isset($_GET['edit'])) { ?>
<form method="post" action = "viewBook.php">
<input type="hidden" name="BookNo" value="<?php echo $BookNo; ?>">
<input type="text" name="ISBN" value="<?php echo $ISBN; ?>">
<input type="text" name="title" value="<?php echo $title; ?>">
<input type="text" name="author" value="<?php echo $author; ?>">
<input type="text" name="publisher" value="<?php echo $publisher; ?>">
<input type="text" name="status" value="<?php echo $status; ?>">
<input type="text" name="cost" value="<?php echo $cost; ?>">
<?php if ($update == true): ?>
<button class="btn" type="submit" name="update" style="background: #556B2F;" >update</button>
<?php else: ?>
<button class="btn" type="submit" name="save" >Save</button>
<?php endif ?>
<?php } ?>
</form>
So far, what it does is, when the user clicks the edit button, it just shows 6 text fields. I thought by doing what I did, it was supposed to show the details already filled in the textbox.
When you do
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$BookNo'");
$BookNo is not defined.
maybe you wanted to do something like this:
$id = $_GET['edit'];
$update = true;
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$id'");
<form method="post" action = "viewBook.php">
your form method is "post" but you are checking $_GET You must check $_POST
if (isset($_GET['edit']))
you are passing value in $id And using $BookNo which not define.
only 6 input field will be show because first one is using hidden property.
<input type="hidden" name="BookNo" value="<?php echo $BookNo; ?>">
when you click on submit button data will be receive by $_POST
I am creating a simple CRUD application that will be used as a blog. For the edit page, I want to have a dropdown menu with the blog titles of each post. When an option/blog post is selected, I want it to populate the "Title" and "Message" fields, so it can then be edited and saved to the database.
I got it to retrieve the titles of the blog posts, but I am struggling to make it populate the "Title" and "Message" fields so it can be edited when the option is selected.
I have 4 rows in my database: row[0] is the title, row[1] is the message, row[2] is the timestamp and row[3] is the ID.
Thanks guys. I appreciate it.
<form action="edit.php" id="myform" method="post" autocomplete=off>
<input type="hidden" name="action" value="show">
<p><label>Entry:</label><select name="blog">
<?php
$result = mysqli_query($con, "SELECT * FROM blog");
while ($row = mysqli_fetch_array($result)) {
$chosen = $row['bid'];
}
if (isset($_GET['blog'])) {
$id = $_GET['blog'];
$result = mysqli_query($con, "SELECT * FROM blog WHERE bid='$id'");
$row = mysqli_fetch_array($result);
}
$result = mysqli_query($con, "SELECT * FROM blog");
while ($row = mysqli_fetch_array($result)) {
$id = $row['bid'];
$title = $row['title'];
$selected = '';
if ($id == $chosen) {
$selected = "selected='selected'";
}
echo "<option value='$id' $selected>$title</option>\n";
}
?>
</select></p>
<p><label>Title:</label> <input type="text" id="newtitle" name="newtitle" value="<?php echo $row[0]; ?>"></p>
<p><label>Message:</label> <input type="text" id="newmessage" name="newmessage" value="<?php echo $row[1]; ?>"></p>
<p><input type="hidden" name="id" value="<?php echo $row[3]; ?>"></p>
<br><p><input type="submit" name="submit" value="Submit"></p>
</form>
I have managed to somewhat figure out the answer on my own. It's probably not the most ideal way of doing it, but for anyone else potentially stuck on this - here is my code:
The only issue I'm having now is figuring out how to keep my option selected.
<form action="edit.php" id="myform" method="post" autocomplete=off>
<input type="hidden" name="action" value="show">
<p><label>Entry:</label><select name="blog" onchange="window.location.href = blog.options[selectedIndex].value">
<option selected disabled>Select One</option>
<?php
$result = mysqli_query($con, "SELECT * FROM blog");
while ($row = mysqli_fetch_array($result)) {
$id = $row['bid'];
$title = $row['title'];
echo "<option value='edit.php?edit=$row[bid]'>$title</option>\n";
}
if (isset($_GET['edit'])) {
$id = $_GET['edit'];
$result = mysqli_query($con, "SELECT * FROM blog WHERE bid='$id'");
$row = mysqli_fetch_array($result);
}
?>
</select></p>
<p><label>Title:</label> <input type="text" id="newtitle" name="newtitle" value="<?php echo $row[0]; ?>"></p>
<p><label>Message:</label> <input type="text" id="newmessage" name="newmessage" value="<?php echo $row[1]; ?>"></p>
<p><input type="hidden" name="id" value="<?php echo $row[3]; ?>"></p>
<br><p><input type="submit" name="submit" value="Submit"></p>
</form>
This is advertisement query
INSERT into advertise_management(advertisement_name,adv_code) values('".$adv_name."','".$adv_code."')
post management:
<input type="text" name="post_name" value="<?php if(isset($post_value)){ echo $post_value['post_name'];} else { echo ''; }?>" required="required">
<?php $res= mysql_query("select * from advertise_management ");
while($result= mysql_fetch_array($res)){
$adv=$result['advertisement_name'];
{ ?>
<input type="checkbox" value="<?php echo $adv?>" name="post_adv[]">
<?php } ?>
Post Management insert query :
$post_name = $_POST['post_name'];
$post_adv1 = $_POST['post_adv'];
$post_adv = implode(",", $post_adv1);
$post_id = $_POST['post_id'];
$res = mysql_query("INSERT into post_managment(post_name,post_adv) values('".$post_name."','".$post_adv."')") or die(mysql_error());
Post management edit :
$result = mysql_query("SELECT * FROM post_managment where post_id='$pid'");
$post_value = mysql_fetch_array($result);
><input type="text" name="post_name" value="<?php if(isset($post_value)){ echo $post_value['post_name'];} else { echo ''; }?>" required="required">
<?php $res= mysql_query("select * from advertise_management ");
while($result= mysql_fetch_array($res)){
$adv=$result['advertisement_name'];
{ ?>
<input type="checkbox" value="<?php echo $adv?>" name="post_adv[]">
<?php } ?>
<input type="submit" value="" id="create"><input type="reset" value="" id="cancel">
I want to return the values that is checked and the values that is not checked.
The browser normally won't send anything for checkboxes that aren't checked. You can work around this by also rendering a hidden input () with the same name and a different value. Make sure it's output right before the checkbox.
My question deals with my next/previous buttons. I can get my update/delete buttons to work, but I'm so ready to tear out my hair when dealing with the next/previous buttons. Any help would be spectacular! Here's my code. Also, I'm pretty new to PHP so if this is bad coding, please let me know and point me in the right direction so I can fix my mistakes. Thanks!!!
session_start();
include "connectionfile.php";
if (isset($_POST['fname']) &&
isset($_POST['lname']) &&
isset($_POST['email']) &&
isset($_POST['login']) &&
isset($_POST['password']) &&
isset($_POST['super']) &&
isset($_POST['foldername']))
{
$id = get_post('id');
$fname = get_post('fname');
$lname = get_post('lname');
$email = get_post('email');
$login = get_post('login');
$password = hash('sha256', get_post('password'));
$super = get_post('super');
$foldername = get_post('foldername');
if ($_POST['submit']==0){
$query = mysql_query("SELECT * FROM `Logins` WHERE ID < '".$id."' ORDER BY ID DESC LIMIT 1;");
while($row = mysql_fetch_array($query)){
$id = $row['ID'];
$fname = $row['fname'];
$lname = $row['lname'];
$email = $row['email'];
$login = $row['login'];
$password = $row['password'];
$super = $row['super'];
$foldername = $row['foldername'];
}
}else if ($_POST['submit']==1){
$query = "UPDATE Logins SET fname = '$fname', lname='$lname', email='$email".'#carouselclinical.com'."', login='$login', password='$password', super='$super', foldername='$foldername'";
$query .= "WHERE ID = '$id';";
if (!mysql_query($query, $connect))
echo "INSERT failed: $query<br />" .
mysql_error() . "<br /><br />";
}else if($_POST['submit']==2){
$delete_query = "DELETE FROM Logins WHERE ID = '".$id."';";
mysql_query($delete_query);
$rc = mysql_affected_rows();
echo "Rows Affected " . $rc;
}
if ($_POST['submit']==3){
$query = mysql_query("SELECT * FROM `Logins` WHERE ID= '". $id ."' ORDER BY ID ASC LIMIT 1;");
while($row = mysql_fetch_array($query)){
$id = $row['ID'];
$fname = $row['fname'];
$lname = $row['lname'];
$email = $row['email'];
$login = $row['login'];
$password = $row['password'];
$super = $row['super'];
$foldername = $row['foldername'];
}
}
}
mysql_close($connect);
function get_post($var)
{
return mysql_real_escape_string($_POST[$var]);
}
?>
<form action="" method="post"><pre>
id <input type="text" readonly="readonly" name="id" value="<?php echo "$id"; ?>" />
First Name <input type="text" name="fname" value="<?php echo "$fname"; ?>" />
Last Name <input type="text" name="lname" value="<?php echo "$lname"; ?>" />
Email <input type="text" name="email" value="<?php echo "$email"; ?>" /> There's no need to put #carouselclinical.com.
Login <input type="text" name="login" value="<?php echo "$login"; ?>"/>
Password <input type="text" name="password" value="<?php echo "$password"; ?>"/>
Super? <input type="text" name="super" value="<?php echo "$super"; ?>" />
foldername <input type="text" name="foldername" value="<?php echo "$foldername"; ?>" />
<button name="submit" value="0">Previous</button>
<button name="submit" value="1">UPDATE</button>
<button name="submit" value="2">Delete</button>
<button name="submit" value="3">Next</button>
</pre>
Home <br />
Log out
</form>
Try adding an else right above mysql_close($connect);. My guess is that on the initial page load you are not posting any values, so no action is taken. This will create a default ID if none is defined in your top if.
else{
$query = mysql_query("SELECT * FROM `Logins` ORDER BY ID ASC LIMIT 1;");
while($row = mysql_fetch_array($query)){
$id = $row['ID'];
$fname = $row['fname'];
$lname = $row['lname'];
$email = $row['email'];
$login = $row['login'];
$password = $row['password'];
$super = $row['super'];
$foldername = $row['foldername'];
}
Also, on your if ($_POST['submit']==3), you need to change the = to > in your $query so you can get the next record. Currently you would be selecting the same ID, not the next higher.
$query = mysql_query("SELECT * FROM `Logins` WHERE ID > '". $id ."' ORDER BY ID ASC LIMIT 1;");
Finally, when doing Previous/Next you also need to take into consideration how you will deal with Previous when you are on the first ID, and Next when you are on the last id, as you will return an empty result set from MySQL.
I don't know to do the script, when click link, it will send data to form. What im trying to do is . When user click link data will appear at the form. below is my link. generated from database.
<div id="menu_bar" region="west" split="true" title="Pages listing" style="width:200px;padding:10px;">
<?php
$parent = mysql_query("select * from pages where parent = 0");
echo "<ul id='sitemap'>";
while($row = mysql_fetch_array($parent)){
$parent_id = $row['id'];
$parent_name = $row['name'];
echo "<li><a href='#' onclick='editPage()'>$parent_name ($parent_id)</a>";
echo "<ul>";
$child = mysql_query("select * from pages where parent = '$parent_id'");
while($row = mysql_fetch_array($child)){
$child_id = $row['id'];
$child_name = $row['name'];
echo "<li><a href='list2.php?id=$child_id' onclick='editPage()'>$child_name ($child_id)</a></li>";
}
echo "</ul>";
}
echo "</li>";
echo "</ul>";
?>
</div>
And the form.
Basic Information
Name:
Parent:
Order:
Body:
Special:
Please help me, im still in programming field. im using PHP, JSON,JQUERY, EASY-UI.
Thanks
If you want to edit page detail in new page then no need to call onclick='editPage()' instead of that pass the page url in href.
<?php
$parent = mysql_query("select * from pages where parent = 0");
echo "<ul id='sitemap'>";
while($row = mysql_fetch_array($parent)){
$parent_id = $row['id'];
$parent_name = $row['name'];
echo "<li><a href='edit_page.php?id=".$row['id']."' >$parent_name ($parent_id)</a>";
echo "<ul>";
$child = mysql_query("select * from pages where parent = '$parent_id'");
while($row = mysql_fetch_array($child)){
$child_id = $row['id'];
$child_name = $row['name'];
echo "<li><a href='edit_page.php?id=".$row['id']."' >$child_name ($child_id)</a></li>";
}
echo "</ul>";
}
echo "</li>";
echo "</ul>";
?>
edit page code should be like this
<?php
$id = $_REQUEST['id'];
//use ur table name here
//I am considering that ur table contain all the required information
$result = mysql_query("select * from table where id='".$id."'");
$row = mysql_fetch_assoc($result);
?>
<form>
Name <input type="text" name="name" id="name" value="<?php echo $row['name']; ?>" />
Parent <input type="text" name="name" id="name" value="<?php echo $row['parent']; ?>" />
Order <input type="text" name="name" id="name" value="<?php echo $row['order']; ?>" />
Body <input type="text" name="name" id="name" value="<?php echo $row['body_text']; ?>" />
Special <input type="text" name="name" id="name" value="<?php echo $row['special']; ?>" />
</form>
hope this will help you.