Codeigniter Complex MySQL Query - php

Question

I got two table which I would like to query from, which the users table and the user_job table
users table structure
user_job table
What I want to achieve is to write a MySQL query in CodeIgniter to display user information from users table if user_status in users table is "Active" And if there is no row in user_job table where user_job_status is equal to "On Probation" or user_job_status is equal to "Active"
In simple English, I want to display a user information if a user not currently on a job.
My current Codeigniter Model code is:
//get all user that are not currently assigned to a position
function get_idle_user(){
$this->db->select('*');
$this->db->from('users');
$this->db->join('user_job', 'user_job.user_id_fk = users.user_id', 'INNER');
$this->db->where('users.user_status','Active');
$this->db->where("(user_job.user_job_status != 'Active' OR user_job.user_job_status != 'On Probation')", NULL, FALSE);
$this->db->group_by('users.user_id');
if($query = $this->db->get()){
return $query;
}else{
return false;
}
}
The problem with this code that it will still display user information if there is a row related to a user and user_job_status does not satisfy the where condition above.
Please Help.

Answer 1

I believe this is what you are after ...
$db->select('user_id_fk,COUNT(*) as `Tally`');
$db->where('user_job_status','On Probabtion');
$db->or_where('user_job_status','Active');
$db->group_by('user_id_fk');
$sub = $db->get_compiled_select('user_job_table');
$db->join("($sub) ujt",'ujt.user_id_fk = users.user_id AND Tally = 0','left');
$db->where('user_status','Active');
// View this query in full
//echo $db->get_compiled_select('users_table');
// Get the data
$data = $db->get('users_table')->result_array();
Note:
You don't need select('*') - it isn't needed
You don't need ->from() - it can be used in the get() element
I have left in the get_compiled_select which will allow you to see the full query and get an idea what its doing. You should comment out the $data line if you uncomment the echo line.
What this query is doing is saying get all users from the job_table which don't have the status Active or On Probation and a list of User ID's. That way you can then get Active users from the users_table and users with a tally of 0.