Cross Join with php codeigniter query - php

Is there away to cross join from php. In example:
Currently I query a database like so:
$company_id = 20;
$templates_data = $this->db->select('template_id')
->from('dr_template_relational')
->where('dr_template_relational.company_id',$company_id)
->get()
->result_array();
What I'm looking to do is something like this:
->from('dr_template_relational')
->cross_join()
There's several responses to this question on SO but post reference a regular sql query like so:
"SELECT * FROM citys LEFT JOIN comments ON comments.city=citys.city WHERE citys.id=$id";
This would be the way to do it in SQL query but the point here is to do it in php and get the data returned with a cross join. I also realize the query can be made with in php to have it select the data and join it with code but my question is related to is there away to simply add ->cross_join() or something like that.

You can run raw query in codeigniter to solve your problem as below:
$sql 'your query here with cross join';
$query = $this->db->query($sql);
return $query->result_array();
Hope it helps you :)

You can use CI join method.
$company_id = 20;
$templates_data = $this->db->select('dr_template_relational.template_id')
->where('dr_template_relational.company_id',$company_id)
->join('table','dr_template_relational.company_id=table.company_id','LEFT')
->get()
->result_array();
where 'LEFT' is the join type

Related

Laravel query with temporary table

How to convert this query to laravel db query.
SELECT * FROM {
Select * from organizers
Order by organizers.rank
} Group by t.department
This is simplified version of query. In real the inner query has more where clause and built using laravel db query.
Edit: I am aware of raw query. But that's not what I am looking for. Inner query is complex and has lots of conditional where clause. I would like to retain the db query object I used there.
You can have 2 different query builders and merge their binding like below :
$innerQuery = DB::table('organizers')->orderBy('organizers.rank');
$mainQuery = DB::table(DB::raw('(' . $innerQuery->toSql() . ') as t'))
->mergeBindings($innerQuery->getQuery())
->groupBy('t.department')
->get();
This will also help you retail the $innerQuery builder instance for your later use as you have mentioned in the question.
I think you will have to execute a raw query.
$result = DB::select("SELECT * FROM (
Select * from organizers
Order by organizers.rank
) Group by t.department");
reference: https://laravel.com/docs/5.7/queries#raw-expressions

How to convert mysql query to codeigniter using query builder?

The following is my mysql query:
select * from db_posts LEFT JOIN db_followers ON db_posts_user_id = db_followers_following AND db_followers_user_id = 276
How can I convert it to codeigniter using query builder?
$this->db->where('db_posts_user_id', 'db_followers_following');
$this->db->where('db_followers_user_id', 276);
$this->db->order_by('db_posts.db_posts_id', 'DESC');
$this->db->join('db_followers', 'db_followers.db_followers_following = db_posts.db_posts_user_id');
$query2 = $this->db->get('db_posts')->result_array();
I get the required result when I use mysql query. But I get a blank array when I use codeigniter queries. What is wrong in my CI Query?
why are you using those where clause? if you are using it as condition for your 'JOIN' process, try it like this:
$this->db->order_by('db_posts.db_posts_id', 'DESC');
$this->db->join('db_followers', 'db_followers.db_followers_following = db_posts.db_posts_user_id and db_followers_user_id = 276', 'left');
$query2 = $this->db->get('db_posts')->result_array();
Points to Note
1)as previous comments said, you should 'Left Join' if you want to get all posts from 'db_posts'.
2) You can add Multiple conditions in ON Clause using and but within ''. all your conditions should be specified before second comma(,) which is before mentioning 'LEFT'.
Hope this will help. Lemme know if this help
Try adding the "Left" option to tell it what kind of join to do:
$this->db->join('db_followers', 'db_followers.db_followers_following = db_posts.db_posts_user_id', 'Left');
Also I'm not sure you need
$this->db->where('db_posts_user_id', 'db_followers_following');
this is already covered by your JOIN statement.
Source:
http://www.bsourcecode.com/codeigniter/codeigniter-join-query/#left-join and https://www.codeigniter.com/userguide3/database/query_builder.html

how to pass variable value to sql query in codeigniter?

is it possible to pass the variable value in mysql query in codeigniter ?
I want to select records from database that have id same as my session id.
my code is :
$this->db->select('*'); // <-- There is never any reason to write this line!
$this->db->from('products');
$this->db->where('id_admin = (SELECT id_admin FROM users WHERE id='.$this->session->userdata('user_id').')', NULL, TRUE);
can we concatenate variable values in database queries?
This code not given any error, but not give any result also.
Use join in active records
$this->db->select('p.*');
$this->db->from('products as p');
$this->db->join('users','p.id_admin=users.id');
$this->db->where('users.id',$this->session->userdata('user_id'),false);
$query = $this->db->get();
An Example Reference of how to write the JOIN Query in CI as per the Documentation of the Active Records.
$article_id = $this->input->post('article_id');
$this->db->select('*');
$this->db->from('articles');
$this->db->join('news', 'news.id = articles.id');
$this->db->where('articles.id',$article_id);
$query = $this->db->get();
The above code will produce the query as follows for execution.
SELECT * FROM articles JOIN news ON news.id = articles.id WHERE articles.id='10'
Provided the passed id is 10
In order to view the Result of the executed query you must perform the below code.
print_r($query->result());
Try like this..use joining of two tables.
<?php
$this->db->select('products.*');
$this->db->from('products');
$this->db->join('users','products.id_admin=users.id_admin');
$this->db->where('users.id',$this->session->userdata('user_id'));
$query = $this->db->get();
print_r($query->result_array());//your array of records

How do you make a codeigniter join?

I'm having trouble creating a join in the codeigniter format, i have a MySQL query that returns what i want:
SELECT nwsite.siteid, nwsite.installer_username,
calcdata.esolar, calcdata.time, calcdata.wsolar
FROM nwsite, calcdata
WHERE nwsite.siteid = calcdata.siteid AND time = '2011-10-29 12:45:00';
I've looked at the documentation but i keep getting it wrong.
Thanks
From the CI docs...
$this->db->select('*');
$this->db->from('blogs');
$this->db->join('comments', 'comments.id = blogs.id');
$query = $this->db->get();
// Produces:
// SELECT * FROM blogs
// JOIN comments ON comments.id = blogs.id
So in your case, I would not use the cartisian product in your FROM, I would actually use a join.
$this->db->select("... your fields here...");
$this->db->from("nwsite");
$this->db->join("calcdata", "nwsite.siteid = calcdata.siteid");
$this->db->where("nwsite.time", "2011-10-29 12:45:00");
$query = $this->db->get();
For Future reference, I often utilize
die($this->db->last_query());
to output the actual query that's being generated. It makes it easier to debug and compare to what you are attempting to generate.

how to get data from three tables by a join statement in mysql

In my application i have three tables, reservation, patient and sub_unit, i need to take the patient_id from reservation table and query the patient table for patient data,same time i need to take the sub_unit_id from the reservation table and query the sub_unit name from the sub_unit table... i need to put all this data in to an one array in the sequence like
patient_id, sub_unit_name, patient_name, address and pass it to the Codeigniter table class to draw a table.
How can I query three tables in the same time to query out this data? can you guys help me out?
Using code igniter syntax it can be done as follows -
$this->db->select('r.patient_id, s.sub_unit_name, p.patient_name, p.address');
$this->db->from('reservation r');
$this->db->join('patient p', 'p.id = r.patient_id');
$this->db->join('sub_unit s', 's.id = r.sub_unit_id');
$query = $this->db->get();
You can check your formed query by -
echo $this->db->_compile_select();exit;
Select r.patient_id, s.sub_unit_name, p.patient_name, p.address
from reservation r, sub_unit s, patient p
where r.patient_id = p.patient_id and r.sub_unit_id = s.sub_unit_id
The join syntax is very straightforward in SQL. You are probably looking for something like this:
SELECT reservation.patient_id,
sub_unit.sub_unit_name,
patient.patient_name,
patient.address
FROM reservation
JOIN patient ON (patient.id = reservation.patient_id)
JOIN sub_unit ON (sub_unit.id = reservation.sub_unit_id);
In MySQL, the default join is an Inner Join, which I think is what you're looking for. You may also want to look into Outer Joins which are also very useful.
it worked guys , i did it like this using Codeigniter active records ,hope you guys can use it too
function get_data(){
$sql = 'SELECT * FROM visit,patient,sub_unit WHERE visit.patient_patient_id = patient.patient_id AND visit.sub_unit_sub_unit_id = sub_unit.sub_unit_id';
$this->db->order_by("reference_number", "desc");
$query = $this->db->query($sql);
return $query;
}
thanx for all your support!

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