How to join string after last array value? [duplicate] - php

Question

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How add a link on comma separated multidimensional array
(2 answers)
Closed 7 months ago.
I am trying to generate a string from an array. Need to concatenate the array values with a small string AFTER the value. It doesn't work for the last value.
$data = array (
1 => array (
'symbol' => 'salad'
),
2 => array (
'symbol' => 'wine'
),
3 => array (
'symbol' => 'beer'
)
);
$symbols = array_column($data, 'symbol');
$string_from_array = join($symbols, 'bar');
echo($string_from_array);
// expected output: saladbar, winebar, beerbar
// output: saladbar, winebar, beer

Answer 1

You can achieve it a few different ways. One is actually by using implode(). If there is at least one element, we can just implode by the delimiter "bar, " and append a bar after. We do the check for count() to prevent printing bar if there are no results in the $symbols array.
$symbols = array_column($data, "symbol");
if (count($symbols)) {
echo implode("bar, ", $symbols)."bar";
}
Live demo at https://3v4l.org/ms5Ot

Answer 2

You can also achieve the desired result using array_map(), as follows:
<?php
$data = [
1 => ['symbol' => 'salad'],
2 => ['symbol' => 'wine'],
3 => ['symbol' => 'beer']
];
echo join(", ", array_map(
fn($v) => "{$v}bar",
array_column($data, 'symbol')
)
);
See live code
Array_map() takes every element of the array resulting from array_column() pulling out the values from $data and with an arrow function, appends the string "bar". Then the new array yielded by array_map has the values of its elements joined with ", " to form the expected output which is then displayed.
As a recent comment indicated you could eliminate array_column() and instead write code as follows:
<?php
$data = [
1 => ['symbol' => 'salad'],
2 => ['symbol' => 'wine'],
3 => ['symbol' => 'beer']
];
echo join(", ", array_map(
fn($row) => "{$row['symbol']}bar",
$data
)
);
See live code
Note while this 2nd way, may appear more direct, is it? The fact is that as array_map iterates over $data, the arrow function contains code that requires dereferencing behind the scenes, namely "$row['symbol']".

Answer 3

The join() function is an alias of implode() which
Returns a string containing a string representation of all the array
elements in the same order, with the glue string between each element.
So you need to add the last one by yourself
$data = array (
1 => array (
'symbol' => 'salad'
),
2 => array (
'symbol' => 'wine'
),
3 => array (
'symbol' => 'beer'
)
);
$symbols = array_column($data, 'symbol');
$string_from_array = join($symbols, 'bar');
if(strlen($string_from_array)>0)
$string_from_array .= "bar";
echo($string_from_array);

Answer 4

You can use array_column and implode
$data = array (
1 => array (
'symbol' => 'salad'
),
2 => array (
'symbol' => 'wine'
),
3 => array (
'symbol' => 'beer'
)
);
$res = implode("bar,", array_column($data, 'symbol'))."bar";
Live Demo

Answer 5

Try this:
$symbols = array_column($data, 'symbol');
foreach ($symbols as $symbol) {
$symbol = $symbol."bar";
echo $symbol;
}
btw, you can't expect implode to do what you expect, because it places "bar" between the strings, and there is no between after the last string you get from your array. ;)

Answer 6

Another way could be using a for loop:
$res = "";
$count = count($data);
for($i = 1; $i <= $count; $i++) {
$res .= $data[$i]["symbol"] . "bar" . ($i !== $count ? ", " : "");
}
echo $res; //saladbar, winebar, beerbar
Php demo