PHP remove array in array by using another array - php

Question

I have 2 arrays. The first is my array and the second is the API response :
$array1 = [
["id" => 45, "name" => "toto"],
["id" => 50, "name" => "tata"],
["id" => 31, "name" => "titi"],
["id" => 82, "name" => "tutu"],
["id" => 12, "name" => "tototo"]
];
$array2 = [
"45" => ["status" => false],
"50" => ["status" => true],
"31" => ["status" => true],
"82" => ["status" => false],
"12" => ["status" => true]
];
I'd like to remove in array1 all id in array2 who have a status false, or keep all id with status true
In this example I need to get :
$array1 = [
["id" => 50, "name" => "tata"],
["id" => 31, "name" => "titi"],
["id" => 12, "name" => "tototo"]
];
Because id 45 and 82 are false in the second array, then I remove them from the first array.
How I can do that without using multiple loops ? There is a solution if we play with php functions like array_diff or something like this ?

Answer 1

You can use array_filter to filter the $array1. Return true if id exist and status is true.
$array1 = ...
$array2 = ...
$result = array_filter($array1, function( $o ) use( $array2 ) {
return isset( $array2[ $o["id"] ] ) && $array2[ $o["id"] ]["status"];
});
This will result to:
Array
(
[1] => Array
(
[id] => 50
[name] => tata
)
[2] => Array
(
[id] => 31
[name] => titi
)
[4] => Array
(
[id] => 12
[name] => tototo
)
)

Answer 2

The most readable solution is often better than using fancy array_* functions, i.e. in this case a simple foreach loop is sufficient:
https://3v4l.org/5eNEf
<?php
$array1 = [
["id" => 45, "name" => "toto"],
["id" => 50, "name" => "tata"],
["id" => 31, "name" => "titi"],
["id" => 82, "name" => "tutu"],
["id" => 12, "name" => "tototo"]
];
$array2 = [
"45" => ["status" => false],
"50" => ["status" => true],
"31" => ["status" => true],
"82" => ["status" => false],
"12" => ["status" => true]
];
$result = [];
foreach($array1 as $arrayEl) {
$id = $arrayEl['id'];
if($array2[$id]['status'] === true) {
$result[] = $arrayEl;
}
}
var_dump($result);
Note: We are not modifying the original content but create a new result array. You might want to add additional isset checks depending on what keys your array contains/might not contain.

Answer 3

Please try this code.
<?php
$array1 = [
["id" => 45, "name" => "toto"],
["id" => 50, "name" => "tata"],
["id" => 31, "name" => "titi"],
["id" => 82, "name" => "tutu"],
["id" => 12, "name" => "tototo"]
];
$array2 = [
"45" => ["status" => false],
"50" => ["status" => true],
"31" => ["status" => true],
"82" => ["status" => false],
"12" => ["status" => true]
];
foreach($array1 AS $key => $value){
if(!$array2[$value['id']]['status']){
unset($array1[$key]);
}
}
echo "<pre>";
print_r($array1);
?>
Find the key from first array and unset it using the true or false value.
Output:
Array
(
[1] => Array
(
[id] => 50
[name] => tata
)
[2] => Array
(
[id] => 31
[name] => titi
)
[4] => Array
(
[id] => 12
[name] => tototo
)
)

Answer 4

You can use array_walk
$res=[];
array_walk($array1, function(&$v,$k) use (&$res,$array2){
($array2[$v['id']]['status'] == 1) ? ($res[] = $v): '';
});
Live Demo

Answer 5

Here is one more solution for the same,
array_walk($array1, function(&$item,$key) use(&$array1, $array2){
if(!$array2[$item['id']]['status']) // checking status if false
unset($array1[array_search($item['id'], array_column($array1,'id'))]); // then unset
});
print_r($array1);
array_walk — Apply a user supplied function to every member of an array
array_search — Searches the array for a given value and returns the first corresponding key if successful
array_column — Return the values from a single column in the input array
Working demo.

Answer 6

This is probably the least readable solution :-)
Array_intersect and array_column can also get the job done.
I make both arrays associative on id then use array_intersect_key to get the true values.
// Make $array1 associative.
$array1 = array_column($array1, null, "id");
// Find all true values in $array1 from $array2
$result = array_intersect_key($array1, array_intersect(array_combine(array_keys($array2), array_column($array2, "status")), [true]));
https://3v4l.org/QVoI5

Answer 7

$array1 = [
["id" => 45, "name" => "toto"],
["id" => 50, "name" => "tata"],
["id" => 31, "name" => "titi"],
["id" => 82, "name" => "tutu"],
["id" => 12, "name" => "tototo"]
];
$array2 = [
"45" => ["status" => false],
"50" => ["status" => true],
"31" => ["status" => true],
"82" => ["status" => false],
"12" => ["status" => true]
];
foreach ($array1 as $tocheck) {
if ($array2[$tocheck['id']]['status']) {
$new[] = $tocheck;
}
}
print_r($new);