Where two id matching, erase the value in two arrays - php

Question

I have two arrays like this :
$data = [
0 => ['id' => 123, 'value' => 'Text'],
1 => ['id' => 124, 'value' => 12]
];
$data2 = [
"custom" => [
0 => ['id' => 123, 'name' => 'Custom1', 'value' => null],
1 => ['id' => 124, 'name' => 'Custom2', 'value' => null]
]
];
I would like to put the value in $data in the value of $data2 instead of "null" values where the ID are matching.
How can I do this ?
I try to do this but does not work :
foreach ($data2['custom'] as $d) {
foreach ($data as $cf) {
if ($cf['id'] == $d['id']):
$cf['value'] = $d['value'];
endif;
}
}
Thanks

Answer 1

Here is a suggestion, first transform the $data array into an array with the id as a key to make the following process simple.
Then process over the $data2 array and in the foreach us the & reference indicator, so that amendments inside the foreach loop are applied to the original $data2 array and not the copy of the $data2 array that would normally be created as part of a foreach loop
$data = [ ['id' => 123, 'value' => 'Text'],['id' => 124, 'value' => 12] ];
$data2 = [ "custom" => [
['id' => 123, 'name' => 'Custom1', 'value' => null],
['id' => 124, 'name' => 'Custom2', 'value' => null]]
];
// transform $data into an array with a useful key
foreach( $data as $d){
$useful[$d['id']] = $d['value'];
}
foreach ( $data2['custom'] as &$data ) {
// first check that the id exists in the new useful array
if ( isset($useful[$data['id']]) ) {
// if it does apply the value to the data2 array
$data['value'] = $useful[$data['id']];
}
}
print_r($data2);
RESULT
Array
(
[custom] => Array
(
[0] => Array
(
[id] => 123
[name] => Custom1
[value] => Text
)
[1] => Array
(
[id] => 124
[name] => Custom2
[value] => 12
)
)
)
In reply to your comment about doing it without using the reference in the loop, yes like this
foreach ( $data2['custom'] as $idx => $data ) {
if ( isset($useful[$data['id']]) ) {
$data2['custom'][$idx]['value'] = $useful[$data['id']];
}
}

Answer 2

Check out this one:
$data = [
0 => ['id' => 123, 'value' => 'Text'],
1 => ['id' => 124, 'value' => 12]
];
$data2 = [
"custom" => [
0 => ['id' => 123, 'name' => 'Custom1', 'value' => null],
1 => ['id' => 124, 'name' => 'Custom2', 'value' => null]
]
];
foreach ($data2['custom'] as $d) {
foreach ($data as $key => $cf) {
if ($cf['id'] == $d['id']):
$data2['custom'][$key]['value'] = $cf['value'];
endif;
}
}
print_r($data2);

Answer 3

You could try to iterate the first array and put the values of it inside the second. If they're always the same size.
Using a foreach go trough the elements on the first array and get the values:
$data = [
0 => ['id' => 123, 'value' => 'Text'],
1 => ['id' => 124, 'value' => 12
]
];
$data2 = [
"custom" => [
0 => ['id' => 123, 'name' => 'Custom1', 'value' => null],
1 => ['id' => 124, 'name' => 'Custom2', 'value' => null]
]
];
foreach ($data as $key=>$singleData){
$data2['custom'][$key]['value'] = $singleData['value'];
}
var_dump($data2);
The ouptup from var_dump() will be:
array(1) {
["custom"]=>
array(2) {
[0]=>
array(3) {
["id"]=>
int(123)
["name"]=>
string(7) "Custom1"
["value"]=>
string(4) "Text"
}
[1]=>
array(3) {
["id"]=>
int(124)
["name"]=>
string(7) "Custom2"
["value"]=>
int(12)
}
}
}