How to understand "if(!($value%2))" in php code? - php

Question

I am just coding in PHP but not understand below-mentioned coding so please help for understanding coding simply
$new_array=array(100,101,61,1075);
foreach($new_array as $value){
if(!($value%2)){
continue;
}
}

Answer 1

You may read this condition as "is number $value can be divided by 2 without a remainder?"

Answer 2

foreach
this is a Array method which we can use to execute on each element of the array. So in your code
foreach($new_array as $value){
This will assign
$value[0] = 100
$value[1] = 101
$value[2] = 61
$value[3] = 1075
Then in php % mean modules. When this operator is used within two numbers it will output the remainder after deviding first number from second number.See below examples.
5%5 = 0
5%4 = 1
5%3 = 2
10%7 = 3
($value%2)
In here each assigned values from array will be divided from 2 and check the remainder.
$value[0] = 100 => 100%2 = 0
$value[1] = 101 => 101%2 = 1
$value[2] = 61 => 61%2 = 1
$value[3] = 1075 => 1075%2 = 1
(!($value%2)) After using NOT operator(!). This means that ($value%2) should be false.It means that ($value%2) should output a value equal to 0. You can check and understand this code as below.
<?php
$new_array=array(100,101,61,1075);
foreach($new_array as $value){
if(!($value%2)){
echo($value." " );
}
}
?>
Output =100
?php
$new_array=array(100,101,61,1075);
foreach($new_array as $value){
if(($value%2)){
echo($value." , " );
}
}
?>
Output = 101 , 61 , 1075 ,
So hope you can have a idea with this.
For more just follow this links.click here to know about modules operator via official document
Thanks