Filling table in a specific way with sql data using loops - php

Question

I want to put data from the following database table in a html table in a specific way.
Below is my php code:
echo "<table style='border:2px solid black;width:100%;'>";
foreach ($results as $key => $value) {
for ($i = 1; $i < 4; $i++) { // 3 + 1 = 4 (itération sur la valeur de $value['ligne'])
if ($i == $value['ligne']) {
echo "<tr>";
for ($j = 1; $j < 4; $j++) { // itération sur la valeur de $value['colonne']
//if ($j == $value['colonne'] ) {
echo "<td style='padding:1em;border:1px solid black;'>".$value['contenu']."</td>";
//}
}
echo "</tr>";
}
}
}
echo "</table>";
And here is the output that i'm having:
What I want to achieve is having "colonne1" only in the column 1 of the table; "colonne2" only in column 2, etc. In the same way, "Ligne1" should appear only in row 1; "Ligne2" in row 2, which is what i've been able to do. Any idea? Thanks, in advance.

Answer 1

You can use a two dimensional array to achieve the object seeing you’re looking for.
First, build a data structure from the database results.
// assuming you’ve retrieved table into $results
$table =array();
foreach($results as $v) {
$row = $v[‘ligne’];
$col = $v[‘colonne’];
$content = $v[‘contenue’];
$table[$row][$col] = $content;
}
// build html table
?>
Then you can print it out in the view:
<table>
<?php foreach($table as $row_array): ?>
<tr>
<?php foreach($row_array as $col): ?>
<td><?= $col ?></td>
<?php endforeach; ?>
</tr>
<?php endforeach; ?>
</table>