Turn this into an if / else statement - php

Question

When an item is chosen on my site, it opens a details page. This is the top of the details page above the html tags:
<?php require_once('dbconnection.php');
mysqli_select_db($conn, $dbname);
$recordID = $_GET['recordID'];
$query_Master_details = "
SELECT *
FROM Master_List
WHERE Master_List.Master_Id = $recordID
";
$Master_details = mysqli_query($conn, $query_Master_details) or die(mysqli_error());
$row_Master_details = mysqli_fetch_assoc($Master_details);
$totalRows_Master_details = mysqli_num_rows($Master_details);
?>
This is the code that makes the body of the page:
<div class="container2">
<div class="category"><h2><?php echo $row_Master_details['Name']; ?></h2></div>
<p><?php echo $row_Master_details['Name']; ?></p>
<p><img src="img/<?php echo $row_Master_details['Img']; ?>" /></p>
<p><?php echo $row_Master_details['Code']; ?></p>
<p><?php echo $row_Master_details['Length']; ?> Characters</p>
<?php
mysqli_free_result($Master_details);
?>
<!-- end .container2 --></div>
What I would like to do is create an if/else statement that will look at the Style_ID of the selected item and determine if the number is > 3. If it is, I want it to choose an item that has a Style_Id of 1, 2, or 3 and the same Length as the item chosen and return a random row in the layout above, skip a few lines and then display the information for the selected item in the layout above. Else if it is < or = 3, then I need it to just display as above.
I have tried using:
<?php
If (Style_ID > 3) {
echo 'Test';
}Else {
<div class="category"><h2><?php echo $row_Master_details['Name']; ?></h2></div>
<p><?php echo $row_Master_details['Name']; ?></p>
<p><img src="img/<?php echo $row_Master_details['Img']; ?>" /></p>
<p><?php echo $row_Master_details['Code']; ?></p>
<p><?php echo $row_Master_details['Length']; ?> Characters</p>
}
?>
<?php
mysqli_free_result($Master_details);
?>
But it doesn't work and has syntax errors. How can I create this if/else statement?
Note: I would appreciate being able to get one setup for all of it, but if not just fixing this part would be a big help right now.

Answer 1

Thanks to #Brad for his responses, I finally got this one figured out. I ended up changing some of my field names and finally figured out where to close the php tags to make this work. Here is what I ended up with:
<div class="container2">
<div class="category"><h2><?php echo $row_master_details['name']; ?></h2></div>
<?php
if ($row_master_details['type_id'] > 3) {
echo "Test";
}else { ?>
<p><?php echo $row_master_details['name']; ?></p>
<p><img src="img/<?php echo $row_master_details['img']; ?>" /></p>
<p><?php echo $row_master_details['item_code']; ?></p>
<p><?php echo $row_master_details['length']; ?> Characters</p>
<?php
mysqli_free_result($master_details);
?>
<?php } ?>
<!-- end .container2 --></div>

Answer 2

For starters, PHP is case-sensitive.
If (...) {
...
}Else {
You'll want to use lower-case if and else.
Next, if Style_ID is an attribute of the record, you'll need to access it like you did the others.
if ($row_Master_details['Style_ID'] > 3) {