I'm trying to merge to arrays using array_merge however I'm either not doing it right or this function doesn't do what I'm expecting.
Here I have 2 arrays
array_merge($array[0], $array[1]);
Array
(
[0] => Array
(
[apples] => 1
[pears] =>
[oranges] =>
[grapes] =>
[melons] => 1
)
[1] => Array
(
[apples] =>
[pears] => 1
[oranges] => 1
[grapes] =>
[melons] =>
[pineapples] =>
[bananas] =>
[lemons] =>
)
)
I'm getting this back, which is just seems to be using the second array
Array
(
[apples] =>
[pears] => 1
[oranges] => 1
[grapes] =>
[melons] =>
[pineapples] =>
[bananas] =>
[lemons] =>
)
But my desired outcome is:
Array
(
[0] => Array
(
[apples] => 1
[pears] => 1
[oranges] => 1
[grapes] =>
[melons] => 1
[pineapples] =>
[bananas] =>
[lemons] =>
)
)
Any help with this would be much appreciated.
From the manual:
If the input arrays have the same string keys, then the later value for that key will overwrite the previous one.
If you want the ones from either that contain values to overwrite empty ones in either, then filter out the empties:
$result = array_merge(array_filter($array[0]), array_filter($array[1]));
However, if both arrays have the same key and they both have a value then this will still result in the second value. Also, this will not keep keys that are empty in both arrays like pineapples so you might need to loop and check what you want to include or not, or possibly:
$result = array_merge(array_merge(array_filter($array[0]), array_filter($array[1])),
array_filter($array[0]),
array_filter($array[1]));
Method I. Use array_walk_recursive
array_walk_recursive($a, function($v, $k) use (&$r){
isset($r[$k]) ? (!$v ? '' : ($r[$k] = $v)) : ($r[$k] = $v);
});
print_r($r);
Working example : https://3v4l.org/UpR2f
Method 2. Iterate using foreach with ternary operator
$r = [];
foreach($a as $k => $v){
foreach($v as $k1 => $v1){
isset($r[$k1]) ? ($v1==1 ? ($r[$k1] = $v1) : '') : ($r[$k1] = $v1);
}
}
Working example :- https://3v4l.org/WXCpd
If you want to keep keys that are empty in both arrays you can loop and merge the arrays by yourself.
You can take first array, that add keys from second array in foreach loop.
$result = $array[0];
foreach ($array[1] as $key => $value) {
if (empty($result[$key])) {
$result[$key] = $value;
}
}
This will keep the values from the first array if there are conflicting keys. If you rather want to keep the values from second array you can do following.
$result = $array[0];
foreach ($array[1] as $key => $value) {
$result[$key] = $value;
}
Related
I have a multidimensional array like:
Array
(
[0] => Array
(
[division] => Mymensingh
[A] => 1
)
[1] => Array
(
[division] => Dhaka
[A] => 5
)
[2] => Array
(
[division] => Mymensingh
[B] => 2
[C] => 5
)
)
I need to find the rows with matching division values and merge them in one array.
From this array, I want the output as:
Array
(
[0] => Array
(
[division] => Mymensingh
[A] => 1
[B] => 2
[C] => 5
)
[1] => Array
(
[division] => Dhaka
[A] => 5
)
)
Keys in the subarrays can be different and the subarrays may have a differing number of elements.
I think it's relatively simple to just iterate through the array and continuously merge the entries separated by "division":
function mergeByDiscriminator($input, $discriminator = 'division') {
$result = [];
foreach ($input as $array) {
$key = $array[$discriminator];
$result[$key] = array_merge(
array_key_exists($key, $result) ? $result[$key] : [],
$array
);
}
return array_values($result);
}
$result = mergeByDiscriminator($input); // $input is your array
The only solution that I can think of is as below. Of course there might be other feasable solutions, but I am giving one from my end.
$array = array(
'0' => array (
'division' => 'Mymensingh',
'A' => 1
),
'1' => array (
'division' => 'Dhaka',
'A' => 5
),
'2' => array (
'division' => 'Mymensingh',
'B' => 2,
'C' => 5
),
);
$result = array();
foreach ($array as $arr) {
if (!is_array($result[$arr['division']])) $result[$arr['division']] = array();
foreach ($arr as $key => $value) {
$result[$arr['division']][$key] = $value;
}
}
echo "<pre>"; print_r($result);
The above code is giving you the desired output. Please give it a try.
Hope this helps.
This task is concisely completed with zero iterated function calls thanks to the null coalescing operator and the union operator.
Merge each iterated row with the pre-existing data in that keyed-group. If the keyed-group has not yet been encountered merge the row with an empty array.
The union operator is suitable/reliable in this case because it is writing one associative array into another associative array.
Language Construct Iteration: (Demo)
$result = [];
foreach ($array as $row) {
$result[$row['division']] = ($result[$row['division']] ?? []) + $row;
}
var_export(array_values($result));
Functional Iteration: (Demo)
var_export(
array_values(
array_reduce(
$array,
function($result, $row) {
$result[$row['division']] = ($result[$row['division']] ?? []) + $row;
return $result;
},
[]
)
)
);
I have an array in PHP code below, and I want to convert this array to be grouped by data value. It's always hard to simplify arrays.
Original array:
Array
(
[0] => Array
(
[date] => 2017-08-22
[AAA] => 1231
)
[1] => Array
(
[date] => 2017-08-21
[AAA] => 1172
)
[2] => Array
(
[date] => 2017-08-20
[AAA] => 1125
)
[3] => Array
(
[date] => 2017-08-21
[BBB] => 251
)
[4] => Array
(
[date] => 2017-08-20
[BBB] => 21773
)
[5] => Array
(
[date] => 2017-08-22
[CCC] => 3750
)
[6] => Array
(
[date] => 2017-08-20
[CCC] => 321750
)
)
Below is my desired array:
Array
(
[2017-08-22] => Array
(
[AAA] => 1231
[CCC] => 3750
)
[2017-08-21] => Array
(
[AAA] => 1172
[BBB] => 251
)
[2017-08-20] => Array
(
[AAA] => 1125
[BBB] => 21773
[CCC] => 321750
)
)
It is also ok to have empty null value if the data doesn't exist. [BBB] => NULL for 2017-08-22.
Can anybody help? Thanks in advance...
A simple loop should do this..
$group = [];
foreach ($data as $item) {
if (!isset($group[$item['date']])) {
$group[$item['date']] = [];
}
foreach ($item as $key => $value) {
if ($key == 'date') continue;
$group[$item['date']][$key] = $value;
}
}
Here : this should do the work.
$dst_array = array();
foreach ($array as $outerval) {
foreach ($outerval as $key => $innerval) {
if ($key != 'date') {
$dst_array[$outerval['date']][$key] = $innerval;
}
}
}
It iterates through the array and then through the entries in each subarray. Any any that is not a date is assigned in the destination array in the subarray corresponding to its date and with its own current key.
I definitely wouldn't recommend any techniques that involve more than one loop -- this process can certainly be performed in a single loop.
If you like language construct iteration, use a foreach() loop: (Demo)
$result = [];
foreach ($array as $row) {
$date = $row['date'];
unset($row['date']);
$result[$date] = array_merge($result[$date] ?? [], $row);
}
var_export($result);
If you like to use functional programming and fewer global variables, use array_reduce(): (Demo)
var_export(
array_reduce(
$array,
function($accumulator, $row) {
$date = $row['date'];
unset($row['date']);
$accumulator[$date] = array_merge($accumulator[$date] ?? [], $row);
return $accumulator;
},
[]
)
);
These techniques unconditionally push data into the subarray with the key based on the date column value.
The above technique will work consistently even if the order of your subarray elements changes.
The ?? (null coalescing operator) is to ensure that array_merge() always has an array in the first parameter -- if processing the first occurrence of a given date, you simply merge the current iteration's data (what's left of it after unset() removes the date element) with an empty array.
I believe this solution will work for you:
<?php
$array = Array
(
0 => Array
(
'date' => '2017-08-22',
'AAA' => '1231',
),
1 => Array
(
'date' => '2017-08-21',
'AAA' => '1172',
),
2 => Array
(
'date' => '2017-08-20',
'AAA' => '1125'
),
3 => Array
(
'date' => '2017-08-21',
'BBB' => '251'
),
4 => Array
(
'date' => '2017-08-20',
'BBB' => '21773',
),
5 => Array
(
'date' => '2017-08-22',
'CCC' => '3750'
),
6 => Array
(
'date' => '2017-08-20',
'CCC' => '321750'
)
);
echo '<pre>';
$array1 = array('AAA' => null, 'BBB' => null, 'CCC' => null);
$array2 = array();
array_walk($array, function ($v) use (&$array2, $array1) {
$a = $v['date'];
if (!isset($array2[$a])) {
$array2[$a] = $array1;
}
unset($v['date']);
$array2[$a] = array_merge($array2[$a], $v);
});
print_r($array2);
Output
Array
(
[2017-08-22] => Array
(
[AAA] => 1231
[BBB] =>
[CCC] => 3750
)
[2017-08-21] => Array
(
[AAA] => 1172
[BBB] => 251
[CCC] =>
)
[2017-08-20] => Array
(
[AAA] => 1125
[BBB] => 21773
[CCC] => 321750
)
)
check output at: https://3v4l.org/NvLB8
Another approach (quick & dirty) making use of an arrays internal pointer:
$newArray = [];
foreach ($array as $childArray) {
$date = current($childArray);
$value = next($childArray); // this advances the internal pointer..
$key = key($childArray); // ..so that you get the correct key here
$newArray[$date][$key] = $value;
}
This of course only works with the given array structure.
Another perfect usage example for the PHP function array_reduce():
// The input array
$input = array(
0 => array(
'date' => '2017-08-22',
'AAA' => '1231',
),
// The rest of your array here...
);
$output = array_reduce(
$input,
function (array $carry, array $item) {
// Extract the date into a local variable for readability and speed
// It is used several times below
$date = $item['date'];
// Initialize the group for this date if it doesn't exist
if (! array_key_exists($date, $carry)) {
$carry[$date] = array();
}
// Remove the date from the item...
// ...and merge the rest into the group of this date
unset($item['date']);
$carry[$date] = array_merge($carry[$date], $item);
// Return the partial result
return $carry;
},
array()
);
The question is not clear. What is the expected result if one key (AAA f.e) is present on two or more dates? This answer keeps only the last value associated with it.
I have two different dimensional arrays.
Array 1:
Array1
(
[0] => Array
(
[id] => 123
[price] => 5
[purchase_time] => 2014/4/10
)
[1] => Array
(
[id] => 123
[price] => 5
[purchase_time] => 2014/5/17
)
)
Array 2:
Array2
(
[0] => 5
[1] => 8
)
I want something like this:
Array
(
[0] => Array
(
[id] => 123
[price] => 5
[purchase_time] => 2014/4/10
[Qty] => 5
)
[1] => Array
(
[id] => 123
[price] => 5
[purchase_time] => 2014/5/17
[Qty] => 8
)
)
Basically the first array is the information I got from a SQL table. The second array contains the quantity for the products sold. I now want to combine these two array together and use the combined array to create a new table. Since these two arrays have different dimensions. I'm not sure how to do it. Here is my try:
$i = 0;
foreach($array1 as $row)
{
$newarray = array_merge($row,$array2[$i]);
$i++;
}
Might be a simpler way, but for fun without foreach:
array_walk($array1, function(&$v, $k, $a){ $v['Qty'] = $a[$k]; }, $array2);
The simplest way is:
$i = 0;
foreach($array1 as &$row) {
$row['Qty'] = $array2[$i++];
}
Or if keys of both arrays are the same (0,1,2...) and array have the same length:
foreach($array1 as $k => &$row) {
$row['Qty'] = $array2[$k];
}
If the $array1 and $array2 are mapped by the same indexes, so they have same length, you can try:
foreach($array2 as $index=>$quantity){
$array1[$index]['Qty'] = $quantity;
}
And it´s done!
If you want to keep the original $array1 untouched, you can make a copy before the foreach.
Create new array and store it there. You can access the value of $array2 because they have the same index of $array1 so you can use the $key of these two arrays.
$array3 = [];
foreach($array1 as $key => $val) {
$array3[] = [
'id' => $val['id'],
'price' => $val['price'],
'purchase_time' => $val['purchase_time'],
'Qty' => $array2[$key]
];
}
print_r($array3);
I am trying to combine two arrays while respecting their shared value.
$array1 = array(
array("id" => "1","name"=>"John"),
array("id" => "2","name"=>"Peter"),
array("id" => "3","name"=>"Tom"),
array("id" => "12","name"=>"Astro")
);
$array2 = array(
array("id" => "1","second_name"=>"Lim"),
array("id" => "2","second_name"=>"Parker"),
array("id" => "3","second_name"=>"PHP")
);
My expected output:
$result = array(
array("id" => "1","name"=>"John","second_name"=>"Lim"),
array("id" => "2","name"=>"Peter","second_name"=>"Parker"),
array("id" => "3","name"=>"Tom","second_name"=>"PHP"),
array("id" => "12","name"=>"Astro")
);
I have made a try by
$arraycomb = array_unique(array_merge($array1,$array2), SORT_REGULAR);
My output is:
Array
(
[0] => Array
(
[id] => 1
[name] => John
)
[1] => Array
(
[id] => 2
[name] => Peter
)
[2] => Array
(
[id] => 3
[name] => Tom
)
[3] => Array
(
[id] => 12
[name] => Astro
)
[4] => Array
(
[id] => 1
[second_name] => Lim
)
[5] => Array
(
[id] => 2
[second_name] => Parker
)
[6] => Array
(
[id] => 3
[second_name] => PHP
)
)
How can I combine the key value inside same array? or how can I bring the expected output?
Note: I am trying for value instead of key ref: PHP Array Merge two Arrays on same key
Alternatively, you could use a foreach in this case then merge them if they share the same id key
With using reference &
foreach($array1 as &$value1) {
foreach ($array2 as $value2) {
if($value1['id'] == $value2['id']) {
$value1 = array_merge($value1, $value2);
}
}
}
echo '<pre>';
print_r($array1);
You can use array_map() for this. Try this -
function modifyArray($a, $b)
{
if (!empty($a) && !empty($b)) {
return array_merge($a, $b);
} else if (!empty($a) && empty($b)) {
return $a;
} else if (empty($a) && !empty($b)) {
return $b;
}
}
$new = array_map("modifyArray", $array1, $array2);
var_dump($new);
It will generate the new array will all the values in both arrays.if the first array's element is empty then the second array will be merged and vice-versa.
Assign temporary first level keys to your first array to aid in identifying rows. Then loop the second array and append the desired column value to the appropriate group. Re-index the array after looping with array_values().
Code: (Demo)
$result = array_column($array1, null, 'id');
foreach ($array2 as $row) {
$result[$row['id']]['second_name'] = $row['second_name'];
}
var_export(array_values($result));
This is a more direct approach than brute force scanning arrays with nested loops.
If all ids in the second array exist in the first array, then the following simpler line can be written inside the body of the foreach().
$result[$row['id']] += $row;
I have an array that looks like
Array
(
[1] => Array
(
[0] => Date
[1] => Action
)
[2] => Array
(
[0] => 2011-01-22 11:23:19
[1] => SHARE_TWEET
)
[3] => Array
(
[0] => 2011-01-22 11:23:19
[1] => SHARE_FACEBOOK
)
and many other different values (about 10), what I want to do is I want to count the number of times a string is in the array. I was going to use array_count_values but it doesn't count multidimensional arrays.
Any other options?
This could be done by first flattening the array, and then using array_count_values() on it:
For flattening, here is the trick:
$array = call_user_func_array('array_merge', $arrays);
And then:
$counts = array_count_values($array);
Output:
array (
'Date' => 1,
'Action' => 1,
'2011-01-22 11:23:19' => 2,
'SHARE_TWEET' => 1,
'SHARE_FACEBOOK' => 1,
)
Full code:
$array = call_user_func_array('array_merge', $arrays);
var_export(array_count_values($array));
Any time you're dealing with arrays, especially with loops in PHP I can't string enough suggest you look at the array documentation, You'd be suprised how quickly you realise most of the loops in your code is unnecessary. PHP has a built in function to achieve what you're after called array_walk_recursive. And since you're using PHP5 you can use closures rather that create_function (which can be very troublesome, especially to debug, and can't be optimised by the PHP interpreter afik)
$strings = array();
array_walk_recursive($arr, function($value, $key) use (&$strings) {
$strings[$value] = isset($strings[$value]) ? $strings[$value]+1 : 1;
});
I know, unary statements aren't always clear, but this one is simple enough, but feel free to expand out the if statement.
The result of the above is:
print_r($strings);
Array
(
[Date] => 1,
[Action] => 1,
[2011-01-22 11:23:19] => 2,
[SHARE_TWEET] => 1,
[SHARE_FACEBOOK] => 1,
)
Pseudo Code
$inputArray = // your array as in the example above
foreach ($inputArray as $key => $value) {
$result[$value[1]] = $result[$value[1]] + 1;
}
var_dump($result);
Here is a way to do the job:
$arr = Array (
1 => Array (
0 => 'Date',
1 => 'Action'
),
2 => Array (
0 => '2011-01-22 11:23:19',
1 => 'SHARE_TWEET'
),
3 => Array (
0 => '2011-01-22 11:23:19',
1 => 'SHARE_FACEBOOK'
)
);
$result = array();
function count_array($arr) {
global $result;
foreach($arr as $k => $v) {
if (is_array($v)) {
count_array($v);
} else {
if (isset($result[$v])) {
$result[$v]++;
} else {
$result[$v] = 1;
}
}
}
}
count_array($arr);
print_r($result);
output:
Array
(
[Date] => 1
[Action] => 1
[2011-01-22 11:23:19] => 2
[SHARE_TWEET] => 1
[SHARE_FACEBOOK] => 1
)