I want to update two tables in a database after a button is clicked.
Already using an update query separated but sometimes the second query will not run and not updating the table.
This is my update queries
$wpdb->replace($table_name_users,$data_array_users);
$wpdb->update($table_name,$data_array,$data_where);
In this case I post just integers like 0,1,2 etc to database tables this queries is related to wordpress update queries.
What is the problem and how can I fix it out ?
Should add $format and $where_format as explained in wordpress developers documentation about wpdb::update for each array in update query.
Example :
wpdb::update( ‘table’, array( ‘column’ => ‘foo’, ‘field’ => ‘bar’ ), array( ‘ID’ => 1 ) ) wpdb::update( ‘table’, array( ‘column’ => ‘foo’, ‘field’ => 1337 ), array( ‘ID’ => 1 ), array( ‘%s’, ‘%d’ ), array( ‘%d’ ) )
You can find more information here :
https://developer.wordpress.org/reference/classes/wpdb/update/
Related
I'm trying to translate an SQL query into a CakePHP query. Where the SQL query returns one row, the CakePHP query returns 2 rows with the columns id & cover in the first row & files_with_cover in the second.
Naturally I'd like one row with all columns.
SQL query:
SELECT s1.id, s1.cover, COUNT(s2.id) files_with_cover FROM songs s1 LEFT JOIN songs s2 ON s2.cover=s1.cover WHERE s1.source_path=$path
CakePHP query:
$result = $this->Song->find('first', array(
'joins' => array(
array(
'table' => 'songs',
'alias' => 'Song2',
'type' => 'LEFT',
'conditions' => array('Song2.cover = Song.cover')
)
),
'fields' => array('Song.id', 'Song.cover', 'count(Song2.id) as files_with_cover'),
'conditions' => array('Song.source_path' => $file)
));
EDIT, example data set:
id cover source_path
-----------------------
1 image1 /example/1
2 image1 /example/2
3 image1 /example/3
4 image2 /example/4
When doing a select with the conditional source_path "/example/1" I want the following result:
id = 1, cover = image1, files_with_cover = 3.
The printout from the $result array may give a clue. Not sure why the files_with_cover column ends up in a separate row.
Array
(
[Song] => Array
(
[id] => 1
[cover] => cover1.jpeg
)
[0] => Array
(
[files_with_cover] => 3
)
)
Using CakePHP 2.8.1 & MySQL
What you receive there isn't two (database) rows, just a not entirely grouped single row. You need to use virtual fields if you want everything grouped under the main model alias.
$this->Song->virtualFields['files_with_cover'] = 'count(Song2.id)';
'fields' => array('Song.id', 'Song.cover', 'files_with_cover'),
See also Cookbook > Models > Virtual Fields
In my case I have a table name "friends" which has two attributes:
account_id
fb_id
I try to get all the account_id based on fb_id, and for this wrote the query as below:
$response = $dynamoClient->getItem ( array(
"TableName" => "facebook_friendlist",
"ConsistentRead" => true,
"Key" => array(
"fb_id" => array(
"S" => "171092723281123"//$fbId
)
),
"ProjectionExpression" => "account_id"
) );
But its not getting executed. I also tried to write the same query using getItem(),scan(),getIterator() but no result.
Help me out with the right way. Thanks in advance.
I am using subquery for id field.
$db = $this->AccountRequest->getDataSource();
$subQuery = $db->buildStatement(
array(
'fields' => array('MAX(id)'),
'table' => $db->fullTableName($this->AccountRequest),
'alias' => 'MaxRecord',
'limit' => null,
'offset' => null,
'order' => null,
'group' => array("user_id")
),
$this->AccountRequest
);
$searching_parameters = array(
#"AccountRequest.id IN " => "(SELECT MAX( id ) FROM `account_requests` GROUP BY user_id)"
"AccountRequest.id IN " => "(".$subQuery.")"
);
$this->Paginator->settings = array(
#'fields' => array('AccountRequest.*'),
'conditions' => $searching_parameters,
'limit' => $limit,
'page' => $page_number,
#'group' => array("AccountRequest.user_id"),
'order' => array(
'AccountRequest.id' => 'DESC'
)
);
$data = $this->Paginator->paginate('AccountRequest');
This structure is producing a query is:
SELECT
`AccountRequest`.`id`,
`AccountRequest`.`user_id`,
`AccountRequest`.`email`,
`AccountRequest`.`emailchange`,
`AccountRequest`.`email_previously_changed`,
`AccountRequest`.`first_name`,
`AccountRequest`.`first_namechange`,
`AccountRequest`.`f_name_previously_changed`,
`AccountRequest`.`last_name`,
`AccountRequest`.`last_namechange`,
`AccountRequest`.`l_name_previously_changed`,
`AccountRequest`.`reason`,
`AccountRequest`.`status`,
`AccountRequest`.`created`,
`AccountRequest`.`modified`
FROM
`syonserv_meetauto`.`account_requests` AS `AccountRequest`
WHERE
`AccountRequest`.`id` IN '(SELECT MAX(id) FROM `syonserv_meetauto`.`account_requests` AS `MaxRecord` WHERE 1 = 1 GROUP BY user_id)'
ORDER BY
`AccountRequest`.`id` DESC
LIMIT 25
In the subquery, its add an extra single quote so it's producing an error.
So, How can I remove these single quotes from this subquery?
Thanks
What are you trying to achieve with the sub query?
The MAX(id) just means it will pull the id with the largest value AKA the most recent insert. The sub query is completely redundant when you can just ORDER BY id DESC.
using MAX() will return only one record, if this is what you want to achieve you can replicate by adding LIMIT 1
If the sub query is just an example and is meant to be from another table I would just run the query that gets the most recent id before running the main query. Getting the last inserted id in a separate query is very quick and I cant see much of a performance loss. I think it will result in cleaner code that`s easier to follow to.
edit 1: From the comments it sounds like all your trying to get is a particular users latest account_requests.
You dont need the sub query at all. My query below will get the most recent account record for the user id you choose.
$this->Paginator->settings = array(
'fields' => array('AccountRequest.*'),
'conditions' => array(
'AccountRequest.user_id' => $userID // you need to set the $userID
)
'page' => $page_number,
'order' => array(
'AccountRequest.id DESC' //shows most recent first
),
'limit' => 1 // set however many you want the maximum to be
);
The other thing you cold be meaning is to get multiple entries from multiple users and display them in order of user first and then the order of recent to old for that user. MYSQL lets you order by more than one field, in that case try:
$this->Paginator->settings = array(
'conditions' => array(
'AccountRequest.user_id' => $userID // you need to set the $userID
)
'page' => $page_number,
'order' => array(
'AccountRequest.user_id', //order by the users first
'AccountRequest.id DESC' //then order there requests by recent to old
)
);
If the example data you have added into the question is irrelevant and you are only concerned about how to do nested subqueries it has already been answered here
CakePHP nesting two select queries
However I still think based on the data in the question you can avoid using a nested query.
i.e : i have 2 tables
Product ( id, name )
Photo ( id, name, photo_id )
And I need to get result in array like this:
array(
'id' => 1,
'name' => product,
'photos' => array(
array('id' => 1, 'name' => 'photo1')
array('id' => 2, 'name' => 'photo2')
)
}
Is it possible in PHP using clear SQL?
I know that is possible to get 2 arrays and connect it but I have many records and I dont want to wase time to quering.
You have to add a foreign_key in your photo table "product_id".
Then create a method getPhotos() in your Product class with will collect all photos for your product.
Is it possible in PHP using clear SQL?
Not in a single SQL call. With a single call, this is the closest you can get:
array(
'id' => 1,
'name' => product,
'photo_id' => 1,
'photo_name' => 'photo1')
),
array(
'id' => 1,
'name' => product,
'photo_id' => 2,
'photo_name' => 'photo2')
)
Your only choice for the format you want is to run queries separately or to combine them into the data structure you want.
As mentioned, this is not possible with SQL. SQL is based on the relational model which is a 1-Normal-Form data model. That means, the result relation is also flat (no nested relations in a relation).
However, there are good frameworks which generate intermediary models in your corresponding target language (e.g. Python, Java, ...) that circumvent the impression of a flat data model. Check for example Django.
https://docs.djangoproject.com/en/1.8/topics/db/models/
Moo
Here I want to join two table with comma separated ids
For example my data is like:
[Restaurant] => Array
(
[RST_ID] => 171
[RST_NAME] => oneone
[RST_IMAGE] =>
[RST_CAT_ID] => 2,4,6
[RST_CT_ID] => 27
[RST_IS_TOP] => 3
[RST_QR_CODE] =>
[RST_CREATED_DATE] => 1394536725
[RST_MODIFIED_DATE] => 1394536725
[RST_STATUS] => 1
)
[Category] => Array
(
[CAT_ID] => 2
[CAT_NAME] => Vegetarian
[CAT_CREATED_DATE] => 1375175962
[CAT_MODIFIED_DATE] => 1375175962
[CAT_STATUS] => 1
)
My Model Code:
var $belongsTo = array(
'Category' => array(
'className' => 'Category',
'foreignKey' => 'RST_CAT_ID',
'conditions' => array('Category.CAT_ID IN ( Restaurant.RST_CAT_ID)')
)
);
Real Query:
SELECT
`Restaurant`.`RST_ID`, `Restaurant`.`RST_NAME`, `Restaurant`.`RST_IMAGE`,
`Restaurant`.`RST_CAT_ID`, `Restaurant`.`RST_CT_ID`, `Restaurant`.`RST_IS_TOP`,
`Restaurant`.`RST_QR_CODE`, `Restaurant`.`RST_CREATED_DATE`,
`Restaurant`.`RST_MODIFIED_DATE`, `Restaurant`.`RST_STATUS`,
`Category`.`CAT_ID`, `Category`.`CAT_NAME`, `Category`.`CAT_CREATED_DATE`,
`Category`.`CAT_MODIFIED_DATE`, `Category`.`CAT_STATUS`, `City`.`CT_ID`,
`City`.`CT_NAME`, `City`.`CT_CREATED_DATE`, `City`.`CT_MODIFIED_DATE`,
`City`.`CT_STATUS`
FROM `dailybit_dailybites`.`restaurant` AS `Restaurant`
LEFT JOIN `dailybit_dailybites`.`category` AS `Category`
ON (`Restaurant`.`RST_CAT_ID` = `Category`.`CAT_ID`
AND `Category`.`CAT_ID` IN ( `Restaurant`.`RST_CAT_ID`))
LEFT JOIN `dailybit_dailybites`.`city` AS `City`
ON (`Restaurant`.`RST_CT_ID` = `City`.`CT_ID`)
WHERE 1 = 1
So what’s the solution here?
It's giving me just one category data that for first id only.
First have a look at this question: MySQL search in comma list
As you can see the belongsTo query is just generating a join on the single id, CakePHP by default doesn't respect this special case. You will have to alter your query and pass all the ids manually, but your DB design is bad and it doesn't follow the CakePHP conventions at all.
How do you prevent duplicates (which would waste space)
How do you remove a given value (Requires custom function, leading to possibility of errors?
How do you respond to performance issues as the size of my tables increase?
Instead of changing the query you should change this awkward DB design. You want to use HABTM here and a join table: Restaurant hasAndBelongsToMany Categoryy.
restaurants <-> restaurants_categories <-> categories
If you insist on using this bad DB design you'll have to use bindModel() and set the conditions manually:
'conditions' => array('FIND_IN_SET (Category.CAT_ID, ' . $listOfIds. ')')
I haven't tested this, try it yourself, see FIND_IN_SET() vs IN()
You'll have to have another method that gets you all the ids you want here before. Like I said, this is ineffectice and bad design.
You have to set your foreign Key false and find_in_set condition
var $belongsTo = array(
'Category' => array(
'className' => 'Category',
'foreignKey' => false,
'conditions' => array('FIND_IN_SET(Category.CAT_ID,Restaurant.RST_CAT_ID)')
)
);
// you can pass an array at the place of 'Restaurant.RST_CAT_ID'