PHP/mysql:Rank users - php

Question

I have this table which displays data from mysql and ordering them by most of clicks
but i don't have #1 or #2 and so on....
here is the code:
<table align="center" style="width:50%">
<tr>
<th>User</th>
<th>clicks</th>
</tr>
<tr>
<td>
<?php include 'conn.php';
$sql = "select user, count(*) duplicates from users group by user order by duplicates desc";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $row["user"]. "<br>";
}
} else {
}
?>
</td>
<td>
<?php
include 'conn.php';
$sql = "select user, count(*) AS duplicates from users group by user order by duplicates desc";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $row["duplicates"]. "<br>";
}
} else {
}
$conn->close();
?></td>
</tr>
</table>
output is this in a table:
users clicks
user1 3
user2 2
user3 1
but i want the output to be:
rank users clicks
1 user1 3
2 user2 2
3 user3 1
thanks for answering

Answer 1

Add Rank section to table
<tr>
<th>Rank</th>
<th>User</th>
<th>clicks</th>
</tr>
Add rank for each result
<td>
<?php include 'conn.php';
$sql = "select user, count(*) duplicates from users group by user order by duplicates desc";
$result = $conn->query($sql);
$rank = 1;
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $rank. "<br>";
$rank++;
}
}
?>
</td>
Full Code
<table align="center" style="width:50%">
<tr>
<th>Rank</th>
<th>User</th>
<th>clicks</th>
</tr>
<tr>
<td>
<?php include 'conn.php';
$sql = "select user, count(*) duplicates from users group by user order by duplicates desc";
$result = $conn->query($sql);
$rank = 1;
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $rank. "<br>";
$rank++;
}
}
?>
</td>
<td>
<?php include 'conn.php';
$sql = "select user, count(*) duplicates from users group by user order by duplicates desc";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $row["user"]. "<br>";
}
}
?>
</td>
<td>
<?php
include 'conn.php';
$sql = "select user, count(*) AS duplicates from users group by user order by duplicates desc";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $row["duplicates"]. "<br>";
}
}
$conn->close();
?></td>
</tr>
</table>

Answer 2

using javascript:
<script type="text/javascript">
var nb = document.getElementsByClassName("number");
for (var i = 0; i < nb.length; i++) {
nb[i].innerHTML = (i+1)+".";
}
</script>
<table align="center" style="width:50%">
<tr>
<th>User</th>
<th>clicks</th>
</tr>
<tr>
<td class="number">
<?php include 'conn.php';
$sql = "select user, count(*) duplicates from users group by user order by
duplicates desc";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $row["user"]. "<br>";
}
} else {
}
?>
</td>
<td>
<?php
include 'conn.php';
$sql = "select user, count(*) AS duplicates from users group by user order by
duplicates desc";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $row["duplicates"]. "<br>";
}
} else {
}
$conn->close();
?></td>
</tr>
</table>