PHP Table. Displaying multiple rows into one - php

Question

Here is my code:
<table border="2px solid #FFF" width="100%">
<tr>
<td width="50%"><Center>Username:</Center><br /></td>
<td width="50%"><center>Numebr Of Warnings:</center><br /></td>
</tr>
</table>
<?
$query = mysql_query("SELECT * FROM warnings");
$numrows = mysql_num_rows($query);
if($numrows != "0"){
while($row = mysql_fetch_assoc($query)){
$warned = $row['username'];
$by = $row['by'];
$sql = mysql_query("SELECT * FROM warnings WHERE username='$warned'");
$warns = mysql_num_rows($sql);
?>
<table border="2px solid #FFF" width="100%">
<tr>
<td width="50%"><center><b><?php echo $warned; ?></b></center></td>
<td width="50%"><center><b><?php echo $warns; ?></center></b></td>
</tr>
</table>
<?php
}
}
else
echo "No Currently Warned Users";
?>
<hr />
And here is the result:
How can I make it so that instead of showing the 2 results for the user Mrg..... I just want it to show one result with the number or rows there are.
Help would be appreciated.

Answer 1

You can use DISTINCT in your query to avoid duplicate rows in your results:
SELECT DISTINCT username, `by` FROM warnings

Answer 2

Change the mysql_fetch_assoc with mysql_feth_array
You're getting the user with double record. Then for each user you are getting 2 lines
The best way to check it is to add pseudo-points to your code.
$query = mysql_query("SELECT * FROM warnings");
$arr=array();
while($row = mysql_fetch_assoc($query))
{
$arr[]=$row;
}
echo "<pre>";
print_r($arr);
echo "</pre>";
exit;
Here check if the $arr has double entries. Then change the mysql_fetch_assoc with mysql_fetch_array and try again

Answer 3

Here is the table
(by,id,username,date)
a1,1,u1,date
a2,2,u2,date
a3,3,u2,date
a4,4,u2,date
And here is the php code
<?php
$conn = mysqli_connect("localhost","username","password");
mysqli_select_db($conn,"dbname");
$warns = mysqli_query($conn,"select username, count(username) as warncount from dtest.warnings W group by username");
while($line = mysqli_fetch_array($warns))
{
echo $line['username']." has ".$line['warncount']. " warns <br/> ";
}
?>