$_post variable foreach loop logic problem [closed] - php

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This code should check the input if it's found in the array, but it does not. It just works for the first index [0]
<?php
$array = array(
"joe",
"sarah",
"jaison",
"klai",
"hanna"
);
if ($_POST){
foreach($array as $value){
echo $value;
if($_POST["name"] == $value){
echo "yeb,i know him !";
break;
} else {
echo "i dont know him";
break;
}
}
}
?>
<p>please enter a name</p>
<form method="post">
<input name="name" type="text">
<input type="submit" value="go!">

Answer 1

1.Use in_array() instead of foreach()
2.Directly check posted name is empty or not.
3.Remove break;
<?php
$array=array("joe","sarah","jaison","klai","hanna");
if(!empty($_POST['name'])){
// add true as 3rd parameter to in_array if you want to check types as well
if(in_array($_POST['name'] ,$array)){
echo "yeb,i know him !";
}else{
echo "i dont know him";
}
}
?>
<p>please enter a name</p>
<form method="post">
<input name="name" type="text">
<input type="submit" value="go!">
Sample output:- https://3v4l.org/VObsX AND https://3v4l.org/HWkU1

Answer 2

You dont have to use a foreach loop here. There is a function in_array that checks if an value is present in an array. Look at this example:
$array = array("joe", "sarah", "jaison", "klai", "hanna");
if (isset($_POST['name'])) {
if( in_array ($_POST["name"], $array) ) {
echo "yeb,i know him !";
} else {
echo "i dont know him";
}
}
?>
<p>please enter a name</p>
<form method="post">
<input name="name" type="text">
<input type="submit" value="go!">
</form>

Answer 3

You can use in_array() function for it. Like this way:
$array=array("joe",
"sarah",
"jaison",
"klai",
"hanna");
if ($_POST){
if(in_array( $_POST["name"], $array )){
echo "yeb,i know him !";
}
else{
echo "i dont know him";
}
}