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I wrote a code such that if I fill all fields of form and I submit then I should get "Ok"
and if I left the form blank then I should get "Please fill all fields".
I am not getting any errors so I am confused how to proceed .
<?php
if(isset($_POST['submit_text']) && isset($_POST['find_word']) && isset($_POST['replaced_word'])){
$sub_text = $_POST['submit_text'];
$fin_text = $_POST['find_word'];
$rep_text = $_POST['replace_word'];
if(!empty($sub_text )&& !empty($fin_text) && !empty($rep_text)){
echo "Ok.";
}else{
echo "Please fill all fields.";
}
}
?>
<html>
<head>
</head>
<body>
<form id="myForm" name="myForm" action="index.php" method="post" >
<p>
Submit Text<br/>
<textarea rows="5" cols="40" type="text" id="submit_text" name="submit_text" ></textarea>
</p>
<p>
Find<br/>
<input id="find_word" name="find_word" type="text" />
</p>
<p>
Replace<br/>
<input id="replace_word" name="replace_word" type="text" />
</p>
<input id="submit" name="submit" type="submit" value="Submit" />
</form>
</body>
</html>
For any query please comment below.
you have missed few characters here
isset($_POST['replaced_word'])
you have to use same name you use in input field.like this
isset($_POST['replace_word'])
Your first "if" needs an "else", I think it would trigger that in your scenario.
I generally try separating these, and do not put them into one large IF..
for example, I would do an if isset and else on each one separately, converting to a different variable accordingly before doing the rest of the logic.
In the first if, you wrote "replaced_word", but the name of the input tag is "replace_word" without the "d". So $_POST['replaced_word'] is never set so that's why it's not working.
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I'm trying to get submit form event to update a field. I found a test code on internet and that's worked. But when I change the button name for my button nothing happens, and the if always returns false to my button and I have no idea what i'm doing wrong.
Example code works:
<form action="" method="POST">
<input type="submit" name="add" Value="Call Add fun">
<input type="submit" name="sub" Value="Call Sub funn">
<?php echo #$a; ?>
<?php
if(#$_POST['add'])
{
function add()
{
$a="You clicked on add fun";
echo $a;
}
add();
} else if (#$_POST['sub']) {
function sub()
{
$a="You clicked on sub funn";
echo $a;
}
sub();
}
?>
I've tried some variations with if (isset($_POST["course_submit_btn"])) but again nothin happens.
I don't know if it has any interface, but the page url is "panel/create-course/?course_ID=3493/"
My page https://www.file.io/c0pn/download/C1kmP2TblfcU
<form action="" method="POST">
<input type="submit" name="add" Value="Call Add fun">
<input type="submit" name="sub" Value="Call Sub fun">
<?php
if(isset($_POST['add'])) {
add();
} else if (isset($_POST['sub'])) {
sub();
}
function add() {
echo "You clicked on add fun";
// todo: more meaningful functionality
}
function sub() {
echo "You clicked on sub fun";
// todo: more meaningful functionality
}
?>
Your code should work, however there are some tips, you should stick to:
Use consistent code styling (spaces, brackets etc),
Use more meaningful names, in a few days you won't know what variable $a is for
Don't put functions within if sections
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Background:
I have looked through the variations on this question and solutions, but I have not found one that applies to my situation. I know I'm most likely overlooking something incredibly obvious, but it's been hours and I can't for the life of me pinpoint what it is. I'm following along with this tutorial but making it my own: https://www.taniarascia.com/create-a-simple-database-app-connecting-to-mysql-with-php/.
What happens: When I click the submit button, nothing happens. I see "not set" displayed on the screen when the page loads and after clicking submit, so I know I'm in my else block, which means $_POST is not being set.
What I expect to happen: I expect to see "not set" on page load, but then once I have filled out the form and clicked submit, I expect to see "set" in my echo statement to indicate that I'm in my if statement and isset($_POST['submit']) is true/successful, followed by "Success" indicating that the try code block was successful, plus the values I entered in the form fields appearing in the database. For now, though, I'd just be happy if I got that first "set" to display.
I have tried: I've tried breaking out the php into a separate file and linking it up to the form via action="thatfile.php", but I get the same result. I've also tried using "get" instead of "post" for the method and $_REQUEST instead of $_POST, but again, same outcome - "not set" displayed, no data in the db.
Here is my code:
<?php
if (isset($_POST['submit'])) {
require "../config.php";
echo "set";
try {
$connection = new PDO($dsn, $username, $password, $options);
$new_item = array(
"luggage" => $_POST['luggage'],
"category" => $_POST['category'],
"item" => $_POST['item'],
"description" => $_POST['description']
);
$sql = sprintf(
"INSERT INTO %s (%s) values (%s)",
"stuff",
implode(", ", array_keys($new_item)),
":" . implode(", :", array_keys($new_item))
);
$statement = $connection->prepare($sql);
$statement->execute($new_item);
echo "Success";
} catch(PDOException $error) {
echo $sql . "<br>" . $error->getMessage();
}
} else {
echo "not set";
}
?>
<?php include "header.php"; ?>
<h1>Add An Item</h1>
<form method="post">
<label for="item">Luggage</label>
<input type="text" name="luggage" id="luggage"></form>
<label for="item">Category</label>
<input type="text" name="category" id="category"></form>
<label for="item">Item</label>
<input type="text" name="item" id="item"></form>
<label for="description">Description</label>
<input type="text" name="description" id="description">
<input type="submit" name="submit" value="submit">
</form>
Back to home
<?php include "footer.php"; ?>
You are closing the form </form> multiple times before the final end of the form </form> so the submit is not in the form. Remove these:
<label for="item">Luggage</label>
<input type="text" name="luggage" id="luggage"></form> ***HERE***
<label for="item">Category</label>
<input type="text" name="category" id="category"></form> ***HERE***
<label for="item">Item</label>
<input type="text" name="item" id="item"></form> ***HERE***
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Closed 3 years ago.
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I try to calculate the body mass index from values entered in a HTML form, but I don't get any result.
I'm new to php and I tried it for 30 minutes, without any result. Could you help me, please?
<?php
$size = $_POST['size'];
$weight = $_POST['weight'];
?>
<form method="post">
<p>Größe in Zentimeter:
<input type="number" name="size">
</p>
<p>Gewicht in Kilogramm:
<input type="numer" name="weight">
</p>
<p>
<input type="submit" value="Berechnen"
</p>
</form>
<?php
$bmi = weight / (size * size);
echo $bmi;
?>
You are missing the dollar in the beginning of some variables. Also, is important to only do the calculation if the user posts the form:
<form method="post">
<p>Größe in Zentimeter:
<input type="number" name="size">
</p>
<p>Gewicht in Kilogramm:
<input type="number" name="weight">
</p>
<p>
<input type="submit" value="Berechnen"
</p>
</form>
<?php
if (isset($_POST['size'])){
$size = $_POST['size'];
$weight = $_POST['weight'];
$bmi = $weight / ($size * $size);
echo $bmi;
}
?>
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Closed 7 years ago.
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I'm trying to capture the value of a text area and pick you up php so that it kept on the server. The functionality that is what I do is to change texts and photos so pretend that these changes I have made are saved.
Where I can move friends.
Thank you very much for your time .
That's my last try:
if(isset($_GET['submit'])){
$salida = $_GET['textarea'];
$archivo = fopen("prueba2.html", "w+");
fputs($archivo, $salida);
$contenido = file_get_contents($archivo);
fclose($abrir);
}
You are using $_GET variable, but your <form> has method POST. You have to use $_POST variable instead.
Thats it the html form really thank you
<form id="formulario" action="" method="POST" enctype="multipart/form-data">
<div>
<h3>Haga "click" encima del contenido a modificar</h3>
</div>
<iframe id="probando" src="prueba2.html" scrolling="auto" height="700" width="800" marginheight="0" marginwidth="0" name="probando"></iframe>
<textarea name="textarea" rows="4" cols="50"></textarea>
<input id="botonGuardar" type="submit" value="Confirmar cambios"/>
</form>
Give your textarea a name:
<form>
<textarea name="myTextarea"></textarea>
<!-- the rest of your form -->
</form>
And then in your php:
$salida = $_GET['myTextarea'];
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How do I Get This HTML 5 Form To Give PHP The Input Data Then Display It On The Screen. I want to collect data in a form. Convert it into a php variable and then echo it out in a way that I can read it.
<form>
First name:<br>
<input type="text" name="name">
</form>
<body>
<pre>
<?php
$taco = htmlspecialchars($_POST["name"]) . '!';
$taco = $_POST;
echo $taco;
?>
</pre>
</body
</html>
How about the following:
<?php
if($_POST) { // check if the page is posted not with a $_GET
foreach($_POST as $field => $value) { // Foreach field
$value = strip_tags($value); // Strip html tags (you can add more)
echo 'Field: '.$field.' has value: '.$value.'<br>'; // output
}
}
?>
<form action="" method="post">
First name: <input type="text" name="first_name">
<input type="submit" value="Display">
</form>
Just put it all in one php file. You can add as many fields as you want.