Newbie to PHP/Laravel here.
Expected behavior
I want to use a form action to get data from database by inserting the id, something like the couriers tracking id. Until now it is working, but i want to show the results only if that id exist on the database
Code
Controller
public function search(Request $request)
{
$request->validate([
'query' => 'required|min:10|max:10',
]);
$query = $request->input('id');
$orders = Order::where('id','LIKE',"%$query%")->get();
$name = $request->input('id', '$id');
return view('order-details', compact('orders'));
order.blade
<form action="{{ route('order-details') }}" method="GET" class="order-form">
<div class="row">
<div class="col-lg-12">
<input type="text" placeholder="Track Order ID" name="query" id="query" value="{{ request()->input('query') }}">
</div>
<div class="col-lg-12">
<button type="submit">Submit Now</button>
</div>
</div>
</form>
#if(count($errors) > 0)
<ul>
#foreach ($errors->all() as $error)
<li>{{$error}}</li>
#endforeach
</ul>
#endif
route
Route::get('order', 'OrderController#index')->name('order');
Route::get('order-detail', 'OrderController#search')->name('order-details');
I think your problem is you are using a like condition, like is notoriusly flakey on numbers.
$query = $request->input('id') ?? -1;
Order::where('id', $query)->get();
Where on only id, will only returns rows where id exists.
You are using a wrong query.
$orders = Order::where('id','LIKE',"%$query%")->get();
The like operator will get anything like that query and not only.
You just need to remove the like operator to get only orders that match the exact id.
$orders = Order::where('id',$query)->get();
You can also add the exists rule:
The field under validation must exist on a given database table.
$request->validate([
'query' => 'exists:orders,id',
]);
Related
My search functionality uses laravel. Whenever I'd search something, instead of returning the wanted result, it returns all the data within the database. For eg: if I searched 'a', it will return all data from the database.
My Search form is
<form class="form-inline my-2 my-md-0" action="/search" method="GET">
<input class="form-control" type="text" placeholder="Search">
</form>
Search.blade.php
#section('content')
#if($search->isNotEmpty())
#foreach ($search as $searched)
<div class="post-list">
<p>{{ $searched->filename }}</p>
<p>{{ $searched->albumname }}</p>
<p>{{ $searched->artistname }}</p>
#endforeach
#else
<div>
<h3>No songs/artist/albums found</h3>
</div>
#endif
#endsection
Search routing
Route::get('/search', [UploadController::class,'search']);
UploadController.php
public function search(Request $request){
$searching = $request->input('search');
// $posts = DB::select('select * from users where active = ?', [1])
$search = MusicUpload::query()
->where('filename','LIKE',"%{$searching}%")
->orWhere('artistname','LIKE',"%{$searching}%")
->orWhere('albumname','LIKE',"%{$searching}%")
->get();
return view('pages.search',compact('search'));
}
I think there is problem with the upload query in the controller, but I haven't found out the exact place where the problem occurs.
You must out or queries in callback - call-back here like a braces in sql query.
Or you can put this query to scope:
class MusicUpload extends Model
{
public function scopeSearch($query, $search)
{
return $query->where(function($query){
$query->where('filename','LIKE',"%{$searching}%")
->orWhere('artistname','LIKE',"%{$searching}%")
->orWhere('albumname','LIKE',"%{$searching}%");
});
}
}
$searching = $request->input('search');
$search = MusicUpload::search($searching)->get();
return view('pages.search',compact('search'));
I'm very confused, I need your help, this is the error:
Missing required parameter for [Route: single.temp] [URI: singlepost/{name}] [Missing parameter: name]. (View: C:\Users\Toshiba\Desktop\working\mouhawla\resources\views\index.blade.php)
The search field:
<div class="search">
<form role="form" action="{{route('single.temp')}}">
<i class="fa fa-search"></i>
<div class="field-toggle">
<input type="text" name="name" class="search-form" autocomplete="off" placeholder="Search">
</div>
</form>
</div>
The method:
public function getPostByName($name) {
$products = DB::table('templates')
->where('name', $name)
->first();
return view('singlepost', compact('products'));
}
The route:
Route::get('/singlepost/{name}', 'App\http\controllers\TemplatesController#getPostByName')->name('single.temp');
The final view:
<h1 style="text-align: center;">ACH-template</h1>
<table>
<tr>
<td><img src="/storage/{{$products->image_path}}"></td>
<td><img src="/storage/{{$products->image_path2}}"></td>
<td><img src="/storage/{{$products->image_path3}}"></td>
<td>
<p>
<h2 style="text-align:center;">{{$products->name}}</h2>
</br>
<p>{{$products->description}}</p>
</p>
</td>
</tr>
</table>
<a href="/storage/{{$products->file_path}}" class="btn btn-primary">
<button class="btn" style="width:100%">
<i class="fa fa-download"></i> Download
</button>
</a>
The error is very explanatory. You are trying to use /singlepost/{name} route, but on your blade file, you are doing route('single.temp'), it is telling you that it needs the parameter name, else it cannot create the URL as it is a missing parameter.
You should have something like:
<form role="form" action="{{route('single.temp', ['name' => VALUE'])}}">
But that will not solve your problem, as you are trying to do a search, so you want something like /singlepost/John, and John is going to be input by the user on the input field. So you have to do an AJAX call because {{ route('single.temp') }} is going to be rendered by PHP and served to the user, so it is always going to miss the needed parameter.
What you can also do is get that value from the Request instead of a URL parameter.
You have defined a route which requires a parameter: {$name}. You have also used the route helper to generate a URL which takes the name of a route as the first argument and an array of parameters as an optional second argument.
When you have used route('single.temp') in your form action, you have not specified any parameters and so Laravel is throwing the error you're seeing. To resolve this error, you would need to specify a $name parameter as the second argument (i.e. route('single.temp', ['name' => 'something'])). This is not ideal though as if you're using $name as a search term, you don't know the value when the page is first rendered and so can't provide that value.
There are a few ways you could achieve your goal of searching records, a basic example of how you could do this follows.
web.php
Define two routes, the first to return a view with a form and another to process the form submission and show the results.
Route::get('/templates', [TemplateController::class, 'index'])
->name('templates.index');
Route::get('/templates/search', [TemplateController::class, 'search')
->name('templates.search');
TemplateController.php
Define the two functions which will be used when one of the routes defined above is requested.
class TemplateController extends Controller
{
// return a view
public function index()
{
return view('templates.search', ['templates' => []]);
}
// process the form submission
// perform a search for the $request search term
// return a view with the results
public function search(Request $request)
{
$request->validate([
'term' => ['required', 'string']
]);
$templates = Template::where('name', $request->term)->get();
return view('templates.search', ['templates' => $templates]);
}
}
templates/search.blade.php
{{-- create a form which will submit to the search route --}}
{{-- note I use GET rather than POST here, explained later --}}
<form action="{{ route('templates.search') }}" method="GET">
#csrf
<input type="text" id="term" name="term" />
<button type="submit">
{{ __('Search') }}
</button>
{{-- loop over and show results if there are any --}}
#forelse ($templates as $template)
{{ $template->name }}
#empty
{{ __('Empty') }}
#endforelse
</form>
The above should be self explanatory. My reason for using GET rather than POST in the search is because the value will be added to the URL as a query string parameter meaning it can be bookmarked or shared with ease.
i have a question about the Laravel search function, i had follow the guildeline online and i still fail to search the category, can someone guide me and tell me where i did wrongly ? Much appreciated
My category Controller php code:
public function search(Request $request)
{
$search = $request->get('search');
$posts = DB::table('bit_app_policy_category')->where('id','like','%' .$search. '%')->paginate(5);
return view('category.index',['posts' => $posts]);
}
My index.blade code
<div align="left">
<div class="col-md-4">
<h1>Policy</h1>
</div>
<div class="col-md-4">
<form action="/search" method="get" role="search">
{{ csrf_field() }}
<div class="input-group">
<input type="text" class="form-control" name="_method" placeholder="Search ID / Code"> <span class="input-group-btn">
<button type="submit" class="btn btn-primary">Search</button></span>
</div>
</form>
</div>
</div>
web.php
Route::get('/search','categoryController#search');
What error i get is here
Error image
interface
Database
You are sending $posts variable to your view. But the error says you are referencing a $category variable.
return view('category.index',['posts' => $posts]);
Maybe you might want to update view to use $posts. If you could post your full code (category/index.blade.php) we might be able to help you better.
__
Here is how I would do:
$categories= DB::table('bit_app_policy_category')->where('id','like','%' .$search. '%')->paginate(5);
return view('category.index',['categories' => $categories]); //you can also use compact return view('category.index', compact('categories') );
And to display:
#foreach( $categories as $category )
<div>{{ $category->id }}</div>
#endforeach
Another tip: you can name your routes like so
Route::get('search','categoryController#search')->name('search');
Then you can reference this route (in form or anywhere else you want) like so:
<form action="{{ route('search') }}" ..>
Here is my routes
Route::get('add-members/{id}','MemberController#create');
Route::post('save-member/{id}','MemberController#store');
This is my code to show the create form
public function create($id)
{
$team=Team::find($id);
$users = User::doesntHave('teams')->whereHas('roles', function($role) {
$role->where('name', 'member');
})->get();
return view('members.create',compact('users','team'));
}
An this is my code to store it
public function store(Request $request,$id)
{
$team=Team::find($id);
dd($request->id);
$team->users()->attach($request->id);
return redirect('home');
}
and this is my blade file
#extends('layouts.app')
#section('content')
<form action="{{url('save-member',$team->id)}}" method="post" accept-charset="utf-8">
#csrf
<div class="form-group row">
<label for="name" class="col-md-4 col-form-label text-md-right">{{ __('Select Member/s') }}</label>
<div class="col-md-6">
#foreach($users as $key => $user)
<input type="checkbox" name="id[]" value="{{$user->id}}">{{$user->email}}<br>
#endforeach
#error('member_id')
<span class="invalid-feedback" role="alert"><strong><font
color="red">{{ $message }}</font></strong></span>
#enderror
</div>
</div>
<button type="submit" class="btn btn-primary">Save</button>
</form>
#endsection
Now when i select none of the user and just click save button it will save the the user id as 1. After i am doing dd($request->id) it will show me the output 1. But in my form there is no users left or my form is empty.So where from 1 is coming. you can see this picture for clearify.
Please help me to solve this problems
You should be more specific with what data you are requesting from the Request:
$request->id; // could be an input named 'id' or a route parameter named 'id'
$request->input('id'); // is an input
$request->route('id'); // is a route parameter
You are running into a situation where you have a route parameter named id and potentially an input named id. Using the dynamic property of the Request, $request->id, will return the input id if it is there, if not it falls back to returning a route parameter named id.
Here is an article from the past that shows the issue with not being specific about what you are trying to get from the Request object:
asklagbox - blog - watch out for request
I'm currently new on Laravel and trying to develop my first project. I have this MethodNotAllowedHttpException in RouteCollection.php line 218 error during my development for inserting data into database. I have searched both Google & Stackoverflow for solutions but non are related to my current problem and some of them way too complex for this simple problem (I think so...).
I have my form in my checklist page:-
<form action="{{url('addchecklist')}}" method="POST">
{{ csrf_field() }}
<div class="row">
<div class="col-sm-12">
<div class="text-left">
<input type="hidden" name="schmFK" value="{{$id}}">
<div class="col-sm-6">
<h4>
<label>Section</label>
<select class="selectpicker form-control" data-live-search="true" name="sctionPK">
<option selected>Select the Section</option>
#foreach ($sction as $key=>$slct1)
<option value="{{$slct1->ssctionPK}}">{{strtoupper($slct1->ssctionName)}}</option>
#endforeach
</select>
</h4>
</div>
<div class="col-sm-2">
<button type="button" data-toggle="modal" data-target=".bs-example-modal-lg" class="btn btn-primary btn-sm" style="margin-top:33px; padding-top:7px; padding-bottom:7px;">Add Section</button>
</div>
<div class="col-sm-4">
<h4>
<label>Severity</label>
<select class="selectpicker form-control" name="svrityPK">
<option selected>Select the Severity</option>
#foreach ($svrity as $key=>$slct2)
<option value="{{$slct2->severityPK}}">{{strtoupper($slct2->severityName)}}</option>
#endforeach
</select>
</h4>
</div>
<div class="col-sm-12">
<h4>
<label>Question</label>
<input class="form-control" type="text" placeholder="Question" name="question">
</h4>
</div>
<div class="col-sm-6">
#include('widgets.button', array('class'=>'primary btnaddstd', 'size'=>'lg', 'type'=>'submit', 'value'=>'Add Checklist'))
</div>
</div>
</div>
</div>
</form>
Then I have this route for inserting data from the form into database:-
Route::post('/addchecklist', function (Request $request){
// Create instance to store record
$scheme = new App\checklists;
$scheme->schmFK = $request->schmFK;
$scheme->schSectionFK = $request->sctionPK;
$scheme->severityFK = $request->svrityPK;
$scheme->clQuestion = $request->question;
$scheme->save(); // save the input
// Sort all records descending to retrieve the newest added record
$input = App\checklists::orderBy('cklistPK','desc')->first();
// Set search field variable default value of null
$src = isset($src) ? $src : null;
// Get Checklist reference from cklists_stddetails with the designated ID
$chkstd = App\Cklists_stddetail::where('cklistFK', $input->cklistPK)
->join('stddetails', 'stdDtlFK', '=', 'stddetails.sdtlPK')
->get();
// Get the newest stored record
$chcklst = App\checklists::where('cklistPK', $input->cklistPK)->firstOrFail();
// Get all data from table 'stddetails'
$stddetail = App\stddetails::all();
// Get all data from table 'standards'
$stndrd = App\standard::all();
// Get all data from table 'sections'
$sction = App\Section::all();
// Redirect to 'addref.blade' page with the newest added record
return redirect('addref/'.$input->cklistPK)
->with('src', $src)
->with('chkstd', $chkstd)
->with('id',$input->cklistPK)
->with('schmid', $request->schmFK)
->with('chcklst', $chcklst)
->with('stddetail', $stddetail)
->with('stndrd', $stndrd)
->with('sction', $sction);
});
My scenario is this, I have a form for user to input data in it. Then when the data is saved, they will be redirected to the page of that data to do something there. The data is successfully saved in the database but the redirection to the designated page (addref.blade) with the newest record ID return error:-
But the URL goes where I wanted it to go (means the URL is right):-
As you can see, the usual solution from the net that I found are:-
Make sure both method from routes and the form is the same, and mine it is:-
method="POST"
Route::post
Make sure the URL routes can recognize the form's action URL, and mine it is:-
<form action="{{url('addchecklist')}}" method="POST">
Route::post('/addchecklist', function (Request $request)
Include CSRF token field in the form, and mine it have been included:-
<form action="{{url('addchecklist')}}" method="POST">
{{ csrf_field() }}
I have tried those simple solution provided on the net and nothing is helpful enough. I'm still wondering what else I have missed and hoped that anyone here can assist on solving my issue.
I think the error is that you have a redirect which you have not registered in your routes or web.php file.
Sample redirect:
Route::post('/addchecklist', function (Request $request){
//some post process here...
return redirect('addref/'.$input->cklistPK)
->with('src', $src)
->with('chkstd', $chkstd)
->with('id',$input->cklistPK)
->with('schmid', $request->schmFK)
->with('chcklst', $chcklst)
->with('stddetail', $stddetail)
->with('stndrd', $stndrd)
->with('sction', $sction);
});
Route::get('addref/{id}', function(Request $request){
//show the blade.php with data
});
Can you please write :
url('/addchecklist')
instead of :
url('addchecklist')
and then print_r('in');
and die; and check what you get.
Route::post('/addchecklist', function (Request $request){
print_r('in');
die;
});