This question already has answers here:
Get JSON object from URL
(11 answers)
Closed 2 years ago.
I am creating a Courier tracking plugin and get data using their API. The output they are returned is in JSON format. Here is the courier API
$curl_handle = curl_init();
// For Direct Link Access use below commented link
//curl_setopt($curl_handle, CURLOPT_URL, 'http://new.leopardscod.com/webservice/trackBookedPacket/?api_key=XXXX&api_password=XXXX&track_numbers=XXXXXXXX'); // For Get Mother/Direct Link
curl_setopt($curl_handle, CURLOPT_URL, 'http://new.leopardscod.com/webservice/trackBookedPacket/format/json/'); // Write here Test or Production Link
curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl_handle, CURLOPT_POST, 1);
curl_setopt($curl_handle, CURLOPT_POSTFIELDS, array(
'api_key' => 'your_api_key'
'api_password' => 'your_api_password'
'track_numbers' => 'string' // E.g. 'XXYYYYYYYY' OR 'XXYYYYYYYY,XXYYYYYYYY,XXYYYYYY' 10 Digits each number
));
$buffer = curl_exec($curl_handle);
curl_close($curl_handle);
How to echo the values get from this curl command?
Regards
Please use json_decode function after $buffer = curl_exec($curl_handle);
$buffer = curl_exec($curl_handle);
$json = json_decode($buffer, true);
print_r($json);
You can get PHP object array
Related
This question already has answers here:
Get JSON object from URL
(11 answers)
Closed 11 months ago.
i use a php post to get the number of users in the telegram group
<?php
$post = array(
'chat_id'=>$chat_id);
$ch = curl_init("https://api.telegram.org/bot$tokken/getChatMembersCount?");
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_ENCODING,"");
header('Content-Type: text/html');
$posres = curl_exec($ch);
$data1 = json_encode($posres);
echo $data1;
?>
the response are array :
{"ok":true,"result":3}
how can i access the result value i tried echo $data1[19]; this only give the index position value
thank you
The response is JSON, so you need to use json_decode() to convert it to a PHP array or object.
$data1 = json_decode($posres);
echo $data1->result;
Just in case Your response is array of object
echo $data1['19']->result; this should give 3 according to your question
This question already has answers here:
Decode gzipped web page retrieved via cURL in PHP
(2 answers)
Closed 2 years ago.
I'm struggling to retrieve data from an API using PHP.
My PHP code:
<?php
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, "https://api.coronavirus.data.gov.uk/v1/data?filters=areaName=United%2520Kingdom;areaType=overview&structure={%22areaName%22:%22areaName%22,%22date%22:%22date%22,%22newCasesByPublishDate%22:%22newCasesByPublishDate%22,%22cumCasesByPublishDate%22:%22cumCasesByPublishDate%22}");
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$output = curl_exec($curl);
curl_close($curl);
echo $output;
?>
Sadly this just outputs a random list of characters like this:
��9|_��M�\�E�JЀ���"�H*p�Kx���,:VK�`>���m��a˒��܆�V^��gt�d�e]���������������f�ӷ�7�?_�\=�^Z)�b�j��߽�����������{����������tu�������7���� +/J���~���������>������o>|�y�v�����s��Et{���i��L;�+>�Pq�F7��ĵQ�u�q9s��e��*͈f hkh�T����Ӵn�ճ�4�Dk�4��E��q��J����XUi�4-r��j�9UZB���s)�J9��a&�z�� �$�Ͳ��n &��4����� �a* ��UP�:Gz�4В:�Z�Pc�#KZsښJU'���mĔ3�#Kj�4KSU�#Kꜧ7�ڇ��ZR����ZUyݨ2I����`�֭�ӴQ�u-Y{JZX�i�%5*dwZ�;����4�Ű�FI�%A��3�������E�u��{#�e#TZm�u WidsVm� j�˱�`�V$��hrz�\���4� ������Fǜ��%˩e�xQ��J-F�*�к�m��.��Q��y�m��2�4�+ݚJ��Ts�R�(!Ge�t���\��F�e���)� �kȤ�ZN4Tf��-���ςhَ&*���T�ɕ����ZA �R."� �0�Y�#��Ԓ-��ֿ0�l#?թL�Uj��l,$�+md��t0�ȒLv�VM����f�$Abm�L#%)�hU�d�Sf�ݬ�vL�FǼ�k�VE�ܔ�%Y�/z�n��c�=UE&35��yd $3`�ʲ>jf��֬t�E��TvY����(#"]�9%�u��4�'E���U�utQcК�}�T��*�浨0�J%T�Z� ��AkVr�kFj����iL ��0�+S��Y�H9�>u���S�O�S�I0��|�95- ���g���Q +1d(HHԮ�Y�M=���IM�i8���T�PA��Ta�Ԇ��O���$*%�2����o�aU<��h��RR�2�.�#��cf�aT�8��JkF �! �O#y& ����h$˔ #���yς�&è� ��|DO�;Z��$X3U��2yX�b��e��0��Ȩ�4���ZT<�iCK�D�t�i��D���m���Pa� k!����D3&^��������e֔i�2:��s�4�j��*��]z�3�G�tT�g<.�&7����V����^yY٦N$9�%���TF�a?ÿ�T��Q���e��6�w2�~L��m� �C�E��#wԏV^�7l5�uk�DPixZ\˅Ny��6�'���"�d�ͭ�5lj��}�J��88��Z�J���S�Ir5V��g�M��#[cx�5�}M�:��k{Suo� \7˔i�%��[�=BUe�U�p���%U��V]#[my�Z��.�V�*���z�4����݇�]�R^&�V�� o� �ɜ&^stS^(&���ʁv�W�p}l�\T)��]�#;�f *��S�U�YD�������\%� �ft��*�(� ��ZO�z���#G�͐6L9*O�W�-[Qu�S������L��n��݊��B�sJ���M�Q����>�+ �F�)9�|��f7?�D�ó�%��Ҁ �������al6m�c#GUDŽ(�pyl䨖Z��cVS�q�O�t�PV��1I�j��%Ŭ��F���(�*�)�7�h%�*�U��\����VA�ڠ�~Fл��{k����Rh�b{���i�nv��M� |Ƙhf-TZ����{���&6�z��uW��UC��&�7kC�����D�n��T3�i�.�'��6��w1���,M��B{7e�r#M��81��м�Tc���]TiDR�G�Y K5���`���d��9�G�%����=�r(Й �W���Zx���q�#�^�P���b Oi�S1� &���sB#��sF#G�oB�M(e U�_�26��M(� %6��M(�99�Y�?T�mB)爲J�']N3*��W���7��93&S��}W)mJ݄�P��O1l=����U]�>]_� �[��V��(��V���n�#�h+e�����R�Jl+e�����R�Jl+e�����R���2����l� e+e([)C�J��������7W��ǫ����w������_��}u�������������ot�����������������˻����W��?<�?}��t�|ֿ~����_��_/��}����_��>~۩ώ?����S�=��<}w��������5-��_��_fk��������ç�����m��3W��ߦ���x����nx
Putting the url directly into a browser works fine, giving a nice JSON, see see here.
I'm really scratching my head to know where to go from here to get this to parse properly in PHP.
Can anyone help, I'm completely out of my depth here.
Excellent....thank you soooo much !!!!!, you have just solved a problem I have been trying to sort out on-and-off for some time.
The retrieved data is encoded, to enable decoding, add this line.
curl_setopt($curl, CURLOPT_ENCODING, '');
This enables the decoding of the retrieved data, by using and empty string as parameter, it enables all encoding types.
With the line added, your code will look like this.
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, "https://api.coronavirus.data.gov.uk/v1/data?filters=areaName=United%2520Kingdom;areaType=overview&structure={%22areaName%22:%22areaName%22,%22date%22:%22date%22,%22newCasesByPublishDate%22:%22newCasesByPublishDate%22,%22cumCasesByPublishDate%22:%22cumCasesByPublishDate%22}");
curl_setopt($curl, CURLOPT_ENCODING, ''); // <--- ADDED LINE!
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$output = curl_exec($curl);
curl_close($curl);
echo $output;
you need just encoding, this is working code:
<?php
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, "https://api.coronavirus.data.gov.uk/v1/data?
filters=areaName=United%2520Kingdom;areaType=overview&structure{%22areaName%22:%22areaName%22,%22date%22:%22date%22,%22newCasesByPublishDate%22:%22newCasesByPublishDate%22,%22cumCasesByPublishDate%22:%22cumCasesByPublishDate%22}");
curl_setopt($curl, CURLOPT_ENCODING, '');
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$output = curl_exec($curl);
curl_close($curl);
echo $output;
?>
This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 4 years ago.
I am trying to get an api(steam api) response as a variable.
{"response":{"players":[{"steamid":"XXXXXXXXXXXXXXXXXXXX","communityvisibilitystate":3,"profilestate":1,"personaname":"The value I want to get","lastlogoff":XXXXXXXXXX,"profileurl":"XXX","avatar":"X","avatarmedium":"X","avatarfull":"X","personastate":1,"realname":"X","primaryclanid":"X","timecreated":XXXXXXXXXX,"personastateflags":0}]}}
Formatted: https://pastebin.com/8QtLzwVX
Currently I am using the following code to get the array:
$url="http://api.steampowered.com/ISteamUser/GetPlayerSummaries/v0002/?key=XXXXXXXXXXXXXXXXXXXXXXXXXXXXXX&steamids=" . $sid;
// Initiate curl
$ch = curl_init();
// Disable SSL verification
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
// Will return the response, if false it print the response
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
// Set the url
curl_setopt($ch, CURLOPT_URL,$url);
// Execute
$result=curl_exec($ch);
// Closing
curl_close($ch);
I don't know how to get the personaname value from the JSON I get in $result and put it in a variable like $personaname.
try with this one:
<?php
$json_array = json_decode($result, true);
echo $json_array['response']['players'][0]['personaname'];
I am trying to fetch data from a URL using cURL...this is something I would be able to do but the URL that I want to fetch data from has a section of php code within it - i.e. the URL is populated using a values generated by an earlier section of code.
I want to access the URL, take the figures out of it and then plug those figures into something else. At the minute I am hitting a bit of a roadblock as the php doesn't populate the URL...any ideas?
The code I am using is:
$url = "https://*START OF API ADDRESS*<?php echo $request_ids; ?>*END OF API ADDRESS*";
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL,$url);
$result=curl_exec($ch);
curl_close($ch);
//var_dump(json_decode($result, true));
$rates = json_decode($result, true);
// Save result
$rates['last_updated'] = time();
file_put_contents($file, json_encode($rates));
}
I am trying to send an image to a web service API that asks for images to be sent as byte data. After clarifying with them that the data from file_get_contents() is what they are looking for, I wrote my cURL script to send it to them, which is at the end of my post.
What I would like to know is if this is the correct way of sending file_get_contents() data to a web service? Will the 'odd' characters that file_get_contents() produces be OK in transit or do I need to do something to protect them?
So far, none of my attempts have been successful - the API always returns the below error message.
I've only ever transferred images over APIs by base64 encoding them, so many thanks for any assistance you can offer.
My coding to send to the API:
// get the byte data
$image = file_get_contents("/path/to/my/image.jpg");
// url of api to post to
$url = "http://api.web.address";
// data to pass to api
$fields["username"] = "myusername";
$fields["password"] = "mypassword";
$fields["image"] = $image;
$ch = curl_init();
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 10);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($fields));
$data = curl_exec($ch);
The error returned from the API:
System.ArgumentException: Cannot convert ���� FExif II* �� ! © Corbis. All Rights Reserved. �� Ducky d �� �http://ns.adobe.com/xap/1.0/ <?xpacket begin="" id="W5M0MpCehiHzreSzNTczkc9d"?> <x:xmpmeta xmlns:x="adobe:ns:meta/" x:xmptk="Adobe XMP Core 5.5-c021 79.154911, 2013/10/29-11:47:16 "> <rdf:RDF xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"> <rdf:Description rdf:about="" xmlns:xmpRights="http://ns.adobe.com/xap/1.0/rights/" xmlns:xmpMM="http://ns.adobe.com/xap/1.0/mm/" xmlns:stRef="http://ns.adobe.com/xap/1.0/sType/ResourceRef#" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:xmp="http://ns.adobe.com/xap/1.0/" xmpRights:Marked="True" xmpRights:WebStatement="http://pro.corbis.com/search/searchresults.asp?txt=42-17167222&openImage=42-17167222" xmpMM:DocumentID="xmp.did:50BE9125E81E11E38F86E55FB7D795DA" xmpMM:InstanceID="xmp.iid:50BE9124E81E11E38F86E55FB7D795DA" xmp:CreatorTool="Adobe Photoshop CC Windows"> <xmpMM:DerivedFrom stRef:instanceID="8FBAF5153D10876B7ED66A56BC16FEE3" stRef:documentID=... to System.Byte.
Parameter name: type ---> System.FormatException: Input string was not in a correct format.
at System.Number.StringToNumber(String str, NumberStyles options, NumberBuffer& number, NumberFormatInfo info, Boolean parseDecimal)
at System.Number.ParseInt32(String s, NumberStyles style, NumberFormatInfo info)
at System.Byte.Parse(String s, NumberStyles style, NumberFormatInfo info)
at System.String.System.IConvertible.ToByte(IFormatProvider provider)
at System.Convert.ChangeType(Object value, Type conversionType, IFormatProvider provider)
at System.Web.Services.Protocols.ScalarFormatter.FromString(String value, Type type)
--- End of inner exception stack trace ---
at System.Web.Services.Protocols.ScalarFormatter.FromString(String value, Type type)
at System.Web.Services.Protocols.ValueCollectionParameterReader.Read(NameValueCollection collection)
at System.Web.Services.Protocols.HttpServerProtocol.ReadParameters()
at System.Web.Services.Protocols.WebServiceHandler.CoreProcessRequest()
UPDATE
It turns out that it was a byte array that I should have been sending to the API. I wasn't familiar with this in PHP, but this post helped me. So my working code is now:
// get the byte data
$image = file_get_contents("/path/to/my/image.jpg");
// url of api to post to
$url = "http://api.web.address";
// data to pass to api
$fields["username"] = "myusername";
$fields["password"] = "mypassword";
$fields["image"] = unpack('C*', $image);
$ch = curl_init();
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 10);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($fields));
$data = curl_exec($ch);
You're doing it wrong. Just have CURL do a standard file upload:
$fields = array(
'username' => 'foo',
'password' => 'bar',
'image' => '#/path/to/your/image'
);
curl_setopt($ch, CURLOPT_POSTFIELDS, $fields);
Note the # in the image field - that's a signal to CURL to do a file upload, using the path specified after the #. ALso note that http_build_query is NOT being used. CURL will recognize that you're passing in an array and do all the work for you.
If you're on PHP 5.5+, the # option is deprecated, and you have a new CURLFile class for doing this.