I try to run multiple queries inside while loop, and nothing happens, not showing error and not showing success. anyone can explain or help me solve this?
here's my code
<?php
include('config.php');
$sql = 'SELECT * FROM inventory_masuk_dummy';
$query = mysqli_query($conn, $sql);
while($row = mysqli_fetch_array($query)) {
$jumlah = $row['jml'];
$size = $row['size'];
$nama_barang = $row['nama_barang'];
$status = $row['status'];
$sql2 = "UPDATE inventory_dummy SET jumlah = jumlah+$jumlah WHERE nama_barang = '$nama_barang' AND size = '$size'";
$sql3 = "UPDATE inventory_masuk_dummy SET status = '2' WHERE status='1'";
while($row = mysqli_fetch_array($sql2) && $row = mysqli_fetch_array($sql3)) {
echo "Berhasil di ubah, anda akan segera dialihkan";
}
}
echo "Nothing...";
?>
The problem is your code does not execute the $sql2 and $sql3, you can execute it again with mysqli_query
<?php
include('config.php');
$sql = 'SELECT * FROM inventory_masuk_dummy';
$query = mysqli_query($conn, $sql);
while($row = mysqli_fetch_array($query)) {
$jumlah = $row['jml'];
$size = $row['size'];
$nama_barang = $row['nama_barang'];
$status = $row['status'];
$sql2 = "UPDATE inventory_dummy SET jumlah = jumlah+$jumlah WHERE nama_barang = '$nama_barang' AND size = '$size'";
$sql3 = "UPDATE inventory_masuk_dummy SET status = '2' WHERE status='1'";
if ( mysqli_query($conn, $sql2) && mysqli_query($conn, $sql3) ) {
echo "Berhasil di ubah, anda akan segera dialihkan";
}
}
echo "Nothing...";
Related
i have two button on my homepage one is time-in and the other is time-out,
i want to prevent the user/student to time-in using same id if he did not put time-out on his last time-in to create valid entry. Hope you can help me.
here is my php code:
<?php
include_once('connection.php');
if(isset($_POST['submit0'])){
$rfid = $_POST['rfid'];
$time=date("H:i:s");
$sql = mysqli_query($conn, "SELECT * FROM stud WHERE rfid_num = '$rfid'");
$count = mysqli_num_rows($sql);
if ($count == 0 ) {
header("location:notexist.php");
} elseif (empty($row['timeout'])) {
header("location:page say the user/student need to put timeout first before time-in again");
} else {
while( $row = mysqli_fetch_array($sql)) {
$rfid=$row['rfid_num'];
$id=$row['id'];
$name0 = $row['name'];
$course0 = $row['course'];
$image = $row['image'];
$InsertSql = "INSERT INTO student_att(rfid_num,id,name,course,image,timein) VALUES ('$rfid','$id','$name0','$course0','$image','$time')";
$res = mysqli_query($conn, $InsertSql);
}
}
}
?>
this is my answer just wanna share it, i just add select student_att table
to fetch the data and check if timeout column is empty.
<?php
include_once('connection.php');
if(isset($_POST['submit0'])){
$rfid = $_POST['rfid'];
$time=date("H:i:s");
$sql = mysqli_query($conn,"select * from stud where rfid_num ='$rfid' ");
$count = mysqli_num_rows($sql);
if ($count == 0) {
header("location:notexist.php");
}else{
while( $row = mysqli_fetch_array($sql)) {
$rfid=$row['rfid_num'];
$id=$row['id'];
$name0 = $row['name'];
$course0 = $row['course'];
$image = $row['image'];
$sql1 = mysqli_query($conn,"select * from student_att where rfid_num ='$rfid' order by number DESC limit 1 ");
while( $row = mysqli_fetch_array($sql1)) {
if(empty($row['timeout'])){
header("location:logout.php");
}else{
$InsertSql = "INSERT INTO student_att(rfid_num,id,name,course,image,timein) VALUES ('$rfid','$id','$name0','$course0','$image','$time')";
$res = mysqli_query($conn, $InsertSql);
}
}
}
}
}
?>
In my project I am trying to generate a QR code with an image in it based on stored blobs (1 Qr code + 1 logo) in my SQL table.
I have thw following code but can't seem to store the new image into my table.
Any help is appreciated.
<?php
//for connection
$sName = "localhost";
$sUser = "Username";
$sPass = "Password";
$sDb = "Database";
$Conn = new mysqli ($sName, $sUser, $sPass, $sDb);
//variables i pass from another app
$Email = mysqli_real_escape_string($Conn, $_POST["PassEmail"]);
$qContent = addslashes(file_get_contents($_FILES["file"]["tmp_name"]));
$qOverlay = addslashes (file_get_contents($_FILES["overlay"]["tmp_name"]));
$Sql = "SELECT * FROM `userprofile_login` INNER JOIN `userprofile_personalprofile` ON userprofile_login.userid = userprofile_personalprofile.userid WHERE userprofile_login.email = '".$Email."' ";
$Result = mysqli_query($Conn, $Sql);
if (mysqli_num_rows ($Result) > 0) {
$Row = mysqli_fetch_assoc ($Result);
$qCheckSql = "SELECT `userid` FROM `userprofile_qr` WHERE userid = '".$Row['userid']."' ";
$qCheckResult = mysqli_query($Conn, $qCheckSql);
$Row2 = mysqli_fetch_assoc($qCheckResult);
if (mysqli_num_rows ($qCheckResult) < 1) {
//if there 0 result from previous query, insert new data
$InsertSql = "INSERT INTO `userprofile_qr` (`userid`, `qrcode`, `overlay`)
VALUES ('".$Row['userid']."', '$qContent', '$qOverlay')";
$InsertResult = mysqli_query($Conn, $InsertSql);
} else {
//is there ia a result from the previous query, update data
$UpdateSql = "UPDATE `userprofile_qr` SET
`qrcode` = '$qContent',
`overlay` = '$qOverlay'
WHERE userid = '".$Row2['userid']."' ";
$UpdateResult = mysqli_query($Conn, $UpdateSql);
}
The first part works, the problem is the bottom part where I want to combine the QR code and the logo:
$qSql = "SELECT `qrcode`, `overlay` FROM `userprofile_qr` WHERE userid = '".$Row2['userid']."' ";
$qSelect = mysqli_query($Conn, $qSql);
include 'phpqrcode/qrlib.php';
$qRow = mysqli_fetch_assoc($qSelect);
$tImage = "<img src='data:image/png;base64,".base64_encode($qRow['qrcode'])."'/>";
$tOverlay = "<img src='data:image/png;base64,".base64_encode($qRow['overlay'])."'/>";
header("Content-type: image/png");
$aQr = imagecreatefromjpeg($tImage);
$QrWidth = imagesx($aQr);
$QrHeight = imagesy($aQr);
$aOverlay = imagecreatefrompng($tOverlay);
$OverlayWidth = imagesx($aOverlay);
$OverlayHeight = imagesy($aOverlay);
$OverlayQrWidth = $QrWidth / 3;
$OverlayQrHeight = $OverlayHeight / ($OverlayWidth / $OverlayQrWidth);
imagecopyresampled($aQr, $aOverlay, $OverlayQrWidth, $OverlayQrHeight, 0, 0, $OverlayQrWidth, $OverlayQrHeight, $OverlayWidth, $OverlayHeight);
imagepng($aQr);
$oImage = "<img src='data:image/png;base64,".base64_encode($aQr)."'/>";
$UpdateCombineSql = "UPDATE `userprofile_qr` SET
`combine` = '$oImage'
WHERE userid = '".$Row2['userid']."' ";
$CombineResult = mysqli_query($Conn, $UpdateCombineSql);
echo "Success";
}
?>
I want edit record in db table but it doesn't save in db table and nothing changed after i submit this form.
Here codes that i forgot to put.
<?php
require('db.php');
include("auth.php"); //include auth.php file on all secure pages
$id_doc=$_REQUEST['id_doc'];
$query = "SELECT * from doc where id_doc='".$id_doc."'";
$result = mysqli_query($connection, $query) or die ( mysqli_error());
$row = mysqli_fetch_assoc($result);
?>
This is my php codes
<?php
if(isset($_POST['new']) && $_POST['new']==1)
{
$id_doc=$_REQUEST['id_doc'];
$query = "SELECT * from doc where id_doc='".$id_doc."'";
$result = mysqli_query($connection, $query) or die ( mysqli_error());
$row = mysqli_fetch_assoc($result);
$title =$_REQUEST['title'];
$date = $_REQUEST['date'];
$from_to = $_REQUEST['from_to'];
$details = $_REQUEST['details'];
$d_location = $_REQUEST['d_location'];
$d_stat = $_REQUEST['d_stat'];
$update="update doc set title='".$title."', date='".$date."', from_to='".$from_to."', details='".$details."', d_location='".$d_location."', d_stat='".$d_stat."' where id_doc='".$id_doc."'";
mysqli_query($connection, $update) or die(mysql_error());
$status = "File Record Updated Successfully. </br></br><a href='v_doc.php'>View Updated Record</a>";
echo '<p style="color:#FF0000;">'.$status.'</p>';
}else {
// here some else code
}
?>
Not an answer. Too long for a comment.
The issue of parametrised queries aside, I find this easier to read:
UPDATE doc
SET title = '$title'
, date = '$date'
, from_to = '$from_to'
, details = '$details'
, d_location = '$d_location'
, d_stat = '$d_stat'
WHERE id_doc = '$id_doc'
And now see about parametrised queries
Try below:
<?php
if(isset($_POST['new']) && $_POST['new']==1)
{
$id_doc=$_REQUEST['id_doc'];
$query = "SELECT * from doc where id_doc='".$id_doc."'";
$result = mysqli_query($connection, $query) or die ( mysqli_error());
$row = mysqli_fetch_assoc($result);
$title =$_REQUEST['title'];
$date = $_REQUEST['date'];
$from_to = $_REQUEST['from_to'];
$details = $_REQUEST['details'];
$d_location = $_REQUEST['d_location'];
$d_stat = $_REQUEST['d_stat'];
$update="update doc set title='".$title."', date='".$date."', from_to='".$from_to."', details='".$details."', d_location='".$d_location."', d_stat='".$d_stat."' where id_doc='".$id_doc."'";
if(mysqli_query($connection, $update)) {
$status = "File Record Updated Successfully. </br></br><a href='v_doc.php'>View Updated Record</a>";
} else {
die(mysqli_error($connection));
}
echo '<p style="color:#FF0000;">'.$status.'</p>';
} else {
// here some else code
}
?>
This should show you exact error, once you get it. show it here, so we can check and do correction.
<?php
$tid = $_GET['tid'];
$id = $_SESSION['userid'];
$sql1 = "SELECT * FROM topics WHERE id='$tid' LIMIT 1";
$res1 = mysqli_query($connect, $sql1) or die(mysqli_error($connect));
while ($row = mysqli_fetch_array($res1, MYSQLI_ASSOC)) {
$title = $row['topic_title'];
$creator = $row['topic_creator'];
}
$sql = "SELECT * FROM users WHERE id='$creator' LIMIT 1";
$user_query = mysqli_query($connect, $sql) or die(mysqli_error($connect));
while ($row = mysqli_fetch_array($user_query, MYSQLI_ASSOC)) {
$name = $row["first"].$row["last"];
}
echo $name;
?>
I'm a little new to PHP, but I've done things exactly like this, but this time I'm getting an error. Everything here works except for $name. I checked my SQL tables and made sure users exist and that there's first and a last area. I don't see what else could be wrong.
Notice: Undefined variable: name in * on line **
Thank you.
Try this code on for size:
<?php
$tid = $_GET['tid'];
$id = $_SESSION['userid'];
$tid = mysqli_escape_string($connect, $tid);
$sql1 = "SELECT * FROM topics WHERE id='{$tid}' LIMIT 1";
$res1 = mysqli_query($connect, $sql1) or die(mysqli_error($connect));
// Check for rows first.
if($res1 and mysqli_num_rows($res1)){
// Use if as while is pointless on LIMIT 1
if($row = mysqli_fetch_array($res1, MYSQLI_ASSOC)) {
$title = $row['topic_title'];
$creator = $row['topic_creator'];
$creator = mysqli_escape_string($connect, $creator);
$sql = "SELECT * FROM users WHERE id='{$creator}' LIMIT 1";
$user_query = mysqli_query($connect, $sql) or die(mysqli_error($connect));
// Check for rows first.
if($user_query and mysqli_num_rows($user_query)){
// Use if as while is pointless on LIMIT 1
if ($row = mysqli_fetch_array($user_query, MYSQLI_ASSOC)) {
$name = $row["first"].$row["last"]; // NO HIT!
}
echo $name;
}else{
echo 'no rows found (query 2).';
}
}
}else{
echo 'no rows found (query 1).';
}
?>
Variable $name is undefined because the $name = ...; line is not reached. So make sure you $sql query actually returns results. It has to in order to define $name.
I would appreciate it if anyone willing to tell how to echoing /print.
Below is the process of entering data into the database, before inserting it how can I echoing it to the table?
<?php
session_start();
if(isset($_POST['submit']))
{
include('class/stock_class.php');
$st = new st_exchange_conv(DEFAULT_SOURCE);
$from = mysql_real_escape_string(stripslashes($_POST['from']));
$value = floatval($_POST['amount']);
$date = date('Y-m-d H:i:s');
$_SESSION['selected'] = $from;
$stocks = $st->stocks();
asort($stocks);
foreach($stocks as $key=>$stock)
{
$st->convert($from,$key,$date);
$stc_price = $st->price($value);
$stock = mysql_real_escape_string(stripslashes($stock));
$count = "SELECT * FROM oc_stock WHERE stock = '$key'";
$result = mysql_query($count) or die(mysql_error());
$sql = '';
if(mysql_num_rows($result) == 1)
{
$sql = "UPDATE oc_stock SET stock_title = '$stock', stc_val = '$stc_price', date_updated = '$date' WHERE stock = '$key'";
}
else
{
$sql = "INSERT INTO oc_stock(stock_id,stock_title,stock,decimal_place,stc_val,date_updated) VALUES ('','$stock','$key','2',$stc_price,'$date')";
}
$result = mysql_query($sql) or die(mysql_error().'<br />'.$sql);
}
header("Location: index.php");
exit();
}
?>
Insert this:
echo "<table><tr><th>".implode(array_keys($stocks), '</th><th>')."</th></tr>";
foreach($stocks as $row) echo "<tr><td>".implode('</td><td>', $row)."</tr>";
echo "</table>";
Edit: If printing the data is the goal and the table-view is not important, I recommend print_r($stocks) instead.