I would appreciate it if anyone willing to tell how to echoing /print.
Below is the process of entering data into the database, before inserting it how can I echoing it to the table?
<?php
session_start();
if(isset($_POST['submit']))
{
include('class/stock_class.php');
$st = new st_exchange_conv(DEFAULT_SOURCE);
$from = mysql_real_escape_string(stripslashes($_POST['from']));
$value = floatval($_POST['amount']);
$date = date('Y-m-d H:i:s');
$_SESSION['selected'] = $from;
$stocks = $st->stocks();
asort($stocks);
foreach($stocks as $key=>$stock)
{
$st->convert($from,$key,$date);
$stc_price = $st->price($value);
$stock = mysql_real_escape_string(stripslashes($stock));
$count = "SELECT * FROM oc_stock WHERE stock = '$key'";
$result = mysql_query($count) or die(mysql_error());
$sql = '';
if(mysql_num_rows($result) == 1)
{
$sql = "UPDATE oc_stock SET stock_title = '$stock', stc_val = '$stc_price', date_updated = '$date' WHERE stock = '$key'";
}
else
{
$sql = "INSERT INTO oc_stock(stock_id,stock_title,stock,decimal_place,stc_val,date_updated) VALUES ('','$stock','$key','2',$stc_price,'$date')";
}
$result = mysql_query($sql) or die(mysql_error().'<br />'.$sql);
}
header("Location: index.php");
exit();
}
?>
Insert this:
echo "<table><tr><th>".implode(array_keys($stocks), '</th><th>')."</th></tr>";
foreach($stocks as $row) echo "<tr><td>".implode('</td><td>', $row)."</tr>";
echo "</table>";
Edit: If printing the data is the goal and the table-view is not important, I recommend print_r($stocks) instead.
Related
i have two button on my homepage one is time-in and the other is time-out,
i want to prevent the user/student to time-in using same id if he did not put time-out on his last time-in to create valid entry. Hope you can help me.
here is my php code:
<?php
include_once('connection.php');
if(isset($_POST['submit0'])){
$rfid = $_POST['rfid'];
$time=date("H:i:s");
$sql = mysqli_query($conn, "SELECT * FROM stud WHERE rfid_num = '$rfid'");
$count = mysqli_num_rows($sql);
if ($count == 0 ) {
header("location:notexist.php");
} elseif (empty($row['timeout'])) {
header("location:page say the user/student need to put timeout first before time-in again");
} else {
while( $row = mysqli_fetch_array($sql)) {
$rfid=$row['rfid_num'];
$id=$row['id'];
$name0 = $row['name'];
$course0 = $row['course'];
$image = $row['image'];
$InsertSql = "INSERT INTO student_att(rfid_num,id,name,course,image,timein) VALUES ('$rfid','$id','$name0','$course0','$image','$time')";
$res = mysqli_query($conn, $InsertSql);
}
}
}
?>
this is my answer just wanna share it, i just add select student_att table
to fetch the data and check if timeout column is empty.
<?php
include_once('connection.php');
if(isset($_POST['submit0'])){
$rfid = $_POST['rfid'];
$time=date("H:i:s");
$sql = mysqli_query($conn,"select * from stud where rfid_num ='$rfid' ");
$count = mysqli_num_rows($sql);
if ($count == 0) {
header("location:notexist.php");
}else{
while( $row = mysqli_fetch_array($sql)) {
$rfid=$row['rfid_num'];
$id=$row['id'];
$name0 = $row['name'];
$course0 = $row['course'];
$image = $row['image'];
$sql1 = mysqli_query($conn,"select * from student_att where rfid_num ='$rfid' order by number DESC limit 1 ");
while( $row = mysqli_fetch_array($sql1)) {
if(empty($row['timeout'])){
header("location:logout.php");
}else{
$InsertSql = "INSERT INTO student_att(rfid_num,id,name,course,image,timein) VALUES ('$rfid','$id','$name0','$course0','$image','$time')";
$res = mysqli_query($conn, $InsertSql);
}
}
}
}
}
?>
Firstly I got the workers name from BIRTHDAYS and then want to get e-mail address from USERS.There is no problem to take workers name's from Table1 but when I try to get the e-mail addresses the db returns me NULL.My DB is mssql.
<?php
include_once("connect.php");
$today = '05.07';
$today1 = $today . "%";
$sql = "SELECT NAME FROM BIRTHDAYS WHERE BIRTH LIKE '$today1' ";
$stmt = sqlsrv_query($conn,$sql);
if($stmt == false){
echo "failed";
}else{
$dizi = array();
while($rows = sqlsrv_fetch_array($stmt,SQLSRV_FETCH_ASSOC))
{
$dizi[] = array('NAME' =>$rows['NAME']);
$newarray = json_encode($dizi,JSON_UNESCAPED_UNICODE);
}
}
foreach(json_decode($newarray) as $nameObj)
{
$nameArr = (array) $nameObj;
$names = reset($nameArr);
mb_convert_case($names, MB_CASE_UPPER, 'UTF-8');
echo $sql2 = "SELECT EMAIL FROM USERS WHERE NAME = '$names' ";
echo "<br>";
$stmt2 = sqlsrv_query($conn,$sql2);
if($stmt2 == false)
{
echo "failed";
}
else
{
$dizi2 = array();
while($rows1 = sqlsrv_fetch_array($stmt2,SQLSRV_FETCH_ASSOC))
{
$dizi1[] = array('EMAIL' =>$rows['EMAIL']);
echo $newarray1 = json_encode($dizi1,JSON_UNESCAPED_UNICODE);
}
}
}
?>
while($rows1 = sqlsrv_fetch_array($stmt2,SQLSRV_FETCH_ASSOC))
{
$dizi1[] = array('EMAIL' =>$rows['EMAIL']);
echo $newarray1 = json_encode($dizi1,JSON_UNESCAPED_UNICODE);
}
you put in $rows1 and would take it from $rows NULL is correct answer :)
take $rows1['EMAIL'] and it would work
and why foreach =?
you can put the statement in while-loop like this:
while ($rows = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)) {
$names = $rows['NAME'];
$sql2 = "SELECT EMAIL FROM USERS WHERE NAME = '$names' ";
echo "<br>";
$stmt2 = sqlsrv_query($conn, $sql2);
if ($stmt2 == false) {
echo "failed";
} else {
$dizi2 = array();
while ($rows1 = sqlsrv_fetch_array($stmt2, SQLSRV_FETCH_ASSOC)) {
$dizi1[] = array('EMAIL' => $rows1['EMAIL']);
echo $newarray1 = json_encode($dizi1, JSON_UNESCAPED_UNICODE);
}
}
}
I want edit record in db table but it doesn't save in db table and nothing changed after i submit this form.
Here codes that i forgot to put.
<?php
require('db.php');
include("auth.php"); //include auth.php file on all secure pages
$id_doc=$_REQUEST['id_doc'];
$query = "SELECT * from doc where id_doc='".$id_doc."'";
$result = mysqli_query($connection, $query) or die ( mysqli_error());
$row = mysqli_fetch_assoc($result);
?>
This is my php codes
<?php
if(isset($_POST['new']) && $_POST['new']==1)
{
$id_doc=$_REQUEST['id_doc'];
$query = "SELECT * from doc where id_doc='".$id_doc."'";
$result = mysqli_query($connection, $query) or die ( mysqli_error());
$row = mysqli_fetch_assoc($result);
$title =$_REQUEST['title'];
$date = $_REQUEST['date'];
$from_to = $_REQUEST['from_to'];
$details = $_REQUEST['details'];
$d_location = $_REQUEST['d_location'];
$d_stat = $_REQUEST['d_stat'];
$update="update doc set title='".$title."', date='".$date."', from_to='".$from_to."', details='".$details."', d_location='".$d_location."', d_stat='".$d_stat."' where id_doc='".$id_doc."'";
mysqli_query($connection, $update) or die(mysql_error());
$status = "File Record Updated Successfully. </br></br><a href='v_doc.php'>View Updated Record</a>";
echo '<p style="color:#FF0000;">'.$status.'</p>';
}else {
// here some else code
}
?>
Not an answer. Too long for a comment.
The issue of parametrised queries aside, I find this easier to read:
UPDATE doc
SET title = '$title'
, date = '$date'
, from_to = '$from_to'
, details = '$details'
, d_location = '$d_location'
, d_stat = '$d_stat'
WHERE id_doc = '$id_doc'
And now see about parametrised queries
Try below:
<?php
if(isset($_POST['new']) && $_POST['new']==1)
{
$id_doc=$_REQUEST['id_doc'];
$query = "SELECT * from doc where id_doc='".$id_doc."'";
$result = mysqli_query($connection, $query) or die ( mysqli_error());
$row = mysqli_fetch_assoc($result);
$title =$_REQUEST['title'];
$date = $_REQUEST['date'];
$from_to = $_REQUEST['from_to'];
$details = $_REQUEST['details'];
$d_location = $_REQUEST['d_location'];
$d_stat = $_REQUEST['d_stat'];
$update="update doc set title='".$title."', date='".$date."', from_to='".$from_to."', details='".$details."', d_location='".$d_location."', d_stat='".$d_stat."' where id_doc='".$id_doc."'";
if(mysqli_query($connection, $update)) {
$status = "File Record Updated Successfully. </br></br><a href='v_doc.php'>View Updated Record</a>";
} else {
die(mysqli_error($connection));
}
echo '<p style="color:#FF0000;">'.$status.'</p>';
} else {
// here some else code
}
?>
This should show you exact error, once you get it. show it here, so we can check and do correction.
How can I perform a autocompute in my database ex. the value of Stock and Quantity(Quantity-Stock) the answer will be save in CarryO column
create.php
<?php
require_once 'dbconfig.php';
$con = mysql_connect("localhost","root","");
if($con)
{
mysql_select_db("testproduct",$con);
}
if($_POST)
{
$sql = mysql_query("SELECT * FROM tblproduct WHERE id = '".$_POST['pid']."'");
$prod = mysql_fetch_array($sql);
$pname = $prod['name'];
$actualprice = $prod['actualprice'];
$sellprice = $prod['sellprice'];
$stock = $prod['Stock'];
$gname = $_POST['gname'];
$saledate = $_POST['saledate'];
$quantity = $_POST['quantity'];
$profit = $_POST['profit'];
$carryO = $_POST['carryO'];
$sells = $_POST['sells'];
$expense = $_POST['expense'];
try{
$stmt = $db_con->prepare("INSERT INTO tblsales(pname,gname,saledate,quantity,actualprice,sellprice,carryO,sells,expense,profit,stock)
VALUES(:upname,:ugname,:usaledate,:uquantity,:uactualprice,:usellprice,:ucarryO,:usells,:uexpense,:uprofit,:ustock)");
$stmt->bindParam(":upname", $pname);
$stmt->bindParam(":ugname", $gname);
$stmt->bindParam(":usaledate", $saledate);
$stmt->bindParam(":uquantity", $quantity);
$stmt->bindParam(":uactualprice", $actualprice);
$stmt->bindParam(":usellprice", $sellprice);
$stmt->bindParam(":ucarryO", $carryO);
$stmt->bindParam(":usells", $sells);
$stmt->bindParam(":uexpense", $expense);
$stmt->bindParam(":uprofit", $profit);
$stmt->bindParam(":ustock", $stock);
if($stmt->execute())
{
echo "Successfully Added";
}
else{
echo "Query Problem";
}
}
catch(PDOException $e){
echo $e->getMessage();
}
}
?>
thanks for your help just new in php and please let me know if I can use your code or its only a example
Change this part:
$prod = mysql_query("SELECT * FROM tblproduct WHERE id = ".$_POST['pid']);
echo $prod;
$pname = [$prod['name']];
Into:
$sql = mysql_query("SELECT * FROM tblproduct WHERE id = '".$_POST['pid']."'");
$prod = mysql_fetch_array($sql);
$pname = $prod['name'];
You may want to try this.
$prod = mysql_query("SELECT * FROM tblproduct WHERE id = ".$_POST['pid'],$db_con); //$db_con must be your database connection
if(!$prod) { die("Database query failed: " . mysql_error()); } //always check if your query is properly done.
$pname = "";
while ($row = mysql_fetch_array($prod)) {
$pname = $row["name"]; }
also if you are fetching only one column which is the name then be specific to your query for fastest result. e.g. "SELECT name FROM tblproduct WHERE id = ".$_POST['pid']
I'm trying to fetch couple of single data in my server database but this is throwing some errors. The incoming data is correct. The search function just don't get completed.
Here's the code:
<?php
if($_SERVER['REQUEST_METHOD']=='POST'){
define('HOST','xxxxxxxxxxx');
define('USER','xxxxxxxxxxxx');
define('PASS','xxxxxxxxx');
define('DB','xxxxxxxxxx');
$con = mysqli_connect(HOST,USER,PASS,DB);
$post_id = $_POST['id'];
$buyer_mobile = $_POST['mobile'];
$buyer_name = $_POST['name'];
$sql = "select mobile from flatowner where id='$post_id'";
$res = mysqli_query($con,$sql);
$owner_mobile = $row['mobile'];
$sql = "select name from user where mobile='$owner_mobile'";
$r = mysqli_query($con,$sql);
$owner_name = $row['name'];
$sql = "INSERT INTO flat_booking (post_id,owner_mobile,owner_name,buyer_mobile,buyer_name) VALUES ('$post_id','$owner_mobile','$owner_name','$buyer_mobile','$buyer_name')";
if(mysqli_query($con,$sql)){
echo "Success";
}
else{
echo "error";
}
mysqli_close($con);
}else{
echo 'error1';
}
What am I doing wrong here? Maybe this:
$owner_mobile = $row['mobile'];
Thanks in advance!
create table flatower and add mobile column
$post_id = 1;
$sql = "select mobile from flatowner where id='$post_id'";
$res = mysql_query($con,$sql);
$row = mysql_fetch_array($res);
$owner_mobile = $row[0]['mobile'];
Your problem is this line:
$owner_mobile = $row['mobile'];
You have not created the $row variable. For this you would need to do something such as:
Do this first:
<?php
$row = array();
while ($result = mysqli_fetch_assoc($res))
{
$row[] = $result;
}
?>
This allows you to do this:
<?php
foreach ($row as $r)
{
var_dump($r); print "<br />"; // One row from the DB per var dump
}
?>