I am getting only one row from database php - php

Question

I have this following PHP code in search.php to gather information from the form in the same file. It's a search engine and when I put something into the search bar I get only one row even when I should get more than one row.
Here is php script:
<?php
$error = "";
$con=mysqli_connect('localhost', 'root', '');
$db=mysqli_select_db($con, 'vodici');
if(isset($_POST['button'])){ //trigger button click
$search=$_POST['search'];
$query=mysqli_query($con,"select distinct * from users where meno like '%{$search}%' || priezvisko like '%{$search}%' || mesto like '%{$search}%' || kraj like '%{$search}%' || rok_narodenia like '%{$search}%' || email like '%{$search}%' ");
if (mysqli_num_rows($query) > 0) {
while($row = mysqli_fetch_array($query)) {
$div = "<div style='border: 1px solid black; border-radius: 5px;'>".$row['id'];
$vysledok = "<h2 style='text-decoration: underline; padding-left: 2%;'>".$row['meno']." ".$row['priezvisko']."</h2>";
$mail = "<p style='padding-left : 2%; font-size: 11px;'><strong>Rok narodenia:</strong> ".$row['rok_narodenia']." <br><strong>E-mail: </strong> ".$row['email']."</p>";
$mesto = "<p style='padding-left: 2%'><strong>Mesto:</strong> ".$row['mesto']." <strong>Kraj:</strong> ".$row['kraj']."</p>";
$div_end = "</div>";
}
}else{
$error = "Nič sme nenašli :/ <br><br>";
}
}
mysqli_close($con);
?>
Here is form:
<form class="search-form" action="" method="post">
<div class="input-group">
<input name="search" type="text" class="form-control" placeholder="Vyhľadať...">
<div class="input-group-append">
<button class="btn btn-secondary" type="submit" name="button"><i class="fa fa-search"></button></i>
</div>
</div>
</form>
<p><?php if(isset($_POST['button']) && $error == "") {
while($row = mysqli_fetch_array($query)) {
echo $div,$vysledok,$mail,$mesto,$div_end;
}
}?></p>
<p><?php if(isset($_POST['button']) && $error !== "") {echo $error;}?></p>
What can I do here? I am out of ideas
Thanks

Answer 1

You only added one row. You need to add each row to the generated html.
$result = '';
if (mysqli_num_rows($query) > 0) {
while($row = mysqli_fetch_array($query)) {
$div = "<div style='border: 1px solid black; border-radius: 5px;'>".$row['id'];
$vysledok = "<h2 style='text-decoration: underline; padding-left: 2%;'>".$row['meno']." ".$row['priezvisko']."</h2>";
$mail = "<p style='padding-left : 2%; font-size: 11px;'><strong>Rok narodenia:</strong> ".$row['rok_narodenia']." <br><strong>E-mail: </strong> ".$row['email']."</p>";
$mesto = "<p style='padding-left: 2%'><strong>Mesto:</strong> ".$row['mesto']." <strong>Kraj:</strong> ".$row['kraj']."</p>";
$div_end = "</div>";
$result .= $div. $vysledok. $mail.$mesto. $div_end ;
}
}else{
$error = "Nič sme nenašli :/ <br><br>";
}
echo $result;
}

Answer 2

In compensation to wakeels answer, that is correct, I would like to ask you to use prepared statements like in my example below
$sql="
SELECT `id`,`meno`,`priezvisko`,`rok_narodenia`,`email`,`mesto`,`kraj`
FROM `users`
WHERE
`meno` LIKE '%?%'
OR `priezvisko` LIKE '%?%'
OR `mesto` LIKE '%?%'
OR `kraj` LIKE '%?%'
OR `rok_narodenia` LIKE '%?%'
OR `email` LIKE '%?%'
;"
$stmt = $con->prepare($sql);
$stmt->bind_param("s", $search);
$stmt->execute();
$result = $stmt->get_result();
while ($row = $result->fetch_assoc()) {
echo $div,$vysledok,$mail,$mesto,$div_end;
}