$_POST variable is duplicating - php

Question

I do not even know how to google this one...imagine it is something stupid...but any help would be great...
passing a variable when submitting a form...when echo the $_POST it is good...but when i put it into a php variable it is duplicated
<?
//list transactions by month
if ($_POST['m']=="yes"){
$table = $_POST['month'];
$_SESSION['table']=$_POST['month'];
$conn = mysql_connect("localhost", "mss_records", "3205") or die(mysql_error());
mysql_select_db('store_records', $conn) or die(mysql_error());
$result = mysql_query("SELECT * FROM $table");
while($row = mysql_fetch_array($result))
{
$id=$row['transaction'];
$date=$row['date'];
$time=$row['time'];
$paid=$row['payment'];
$total=$row['total'];
echo '<style type="text/css">
<!--
.list {
font-family: Georgia, "Times New Roman", Times, serif;
font-size: 12px;
color: #000;
padding: 2px;
border: 2px solid #009;
}
.view {
width: 100px;
}
-->
</style>
<div class="list">
<p><span style="color: #900">Transaction #</span>'.$id.'
<span style="color: #900">Date:</span>'.$date.'
<span style="color: #900">Time:</span>'.$time.'<span style="color: #900">
Paid By:</span>'.$paid.' <span style="color: #900">Total:</span>'
.number_format($total, 2).'
<form name="form1" method="post" action="find.php">
<label>
<input type="submit" name="view" id="view" value="'.$id.'">
</label>
</form>
</p>
</div>
<p></p>';
}
}
//view transaction after viewing by month
if (isset($_POST['view'])){
$conn = mysql_connect("localhost", "mss_records", "3205") or die(mysql_error());
mysql_select_db('store_records', $conn) or die(mysql_error());
$table = $_SESSION['table'];
echo "this is the number ".$_POST['view'];
$post=$_POST['view'];
echo "this is the post ".$post;
$result = mysql_query("SELECT * FROM $table WHERE transaction = '$post'")
or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$items=$row['transaction'];
}
echo $items;
}
?>
after the user goes through the first selection and on the second window the output is...
this is the number 46this is the $post 4646

Answer 1

Your query is mysql_query("SELECT * FROM $table WHERE transaction = '$post'"). Therefore the value of $items=$row['transaction']; is also going to be 46. When you echo out everything without line breaks, it smashes everything together.
POST is not duplicating anything, you are just echoing $items directly after it.
Try this:
$table = $_SESSION['table'];
echo "this is the number ".$_POST['view']."<br /> \n";
$post=$_POST['view'];
echo "this is the post ".$post."<br /> \n";
$result = mysql_query("SELECT * FROM $table WHERE transaction = '$post'")
or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$items=$row['transaction'];
}
echo $items;
}