This question already has answers here:
PHP - parse current URL
(6 answers)
Closed 2 years ago.
I'm looking to be able to extract a Twitter username from a URL.
E.g: https://twitter.com/jack => jack
I found this Regex to be helpful.
if (preg_match("/^https?:\/\/(www\.)?twitter\.com\/(#!\/)?(?<name>[^\/]+)(\/\w+)*$/", $url, $regs)) {
return $regs['name'];
}
It doesn't seem to work when twitter URL contains query parameters.
For example = https://twitter.com/jack?lang=en returns jack?lang=en
Any idea how to improve the regex to prevent this ?
preg_match('/https?:\/\/twitter\.com\/(?<name>[^\?]+)\??.*/', 'https://twitter.com/jack?lang=en', $m);
var_dump(trim($m['name']));
$path = parse_url('https://twitter.com/jack?lang=en',PHP_URL_PATH);
var_dump(str_replace('/','', $path));
string(4) "jack"
Related
This question already has answers here:
Get parts of URL in PHP
(4 answers)
Closed 1 year ago.
I had previously been using basename to grab the last part of my URL however have noticed some issues if my URL contains parameters.
So if my URL is this:
https://www.google.com/test-page/?utm_source=test
How would I pull test-page from this?
You split it by the / delimiter, and then take the fourth item
$link = 'https://www.google.com/test-page/?utm_source=test';
$split = explode('/', $link);
if(isset($split[3]))
{
echo $split[3];
}
This question already has answers here:
PHP - parse current URL
(6 answers)
Closed 2 years ago.
How to get a part of string using PHP?
I have a string like this.
https://test-app.com/admin/api/2019-10/orders.json?limit=2&page_info=eyJpZHMiOiIyMDY3MTczMTEzOTg3LDIwNjU0ODU0MzA5MTUsMjA2NTQ3OTI3MDUzMSwyMDYyODE3MzI5MjgzIiwibGFzdF9pZCI6MjA2NTQ4NTQzMDkxNSwibGFzdF92YWx1ZSI6IjIwMjAtMDMtMTcgMTg6MTc6NTkiLCJkaXJlY3Rpb24iOiJuZXh0In0
I want only the link.. like this
orders.json?limit=2&page_info=eyJpZHMiOiIyMDY3MTczMTEzOTg3LDIwNjU0ODU0MzA5MTUsMjA2NTQ3OTI3MDUzMSwyMDYyODE3MzI5MjgzIiwibGFzdF9pZCI6MjA2NTQ4NTQzMDkxNSwibGFzdF92YWx1ZSI6IjIwMjAtMDMtMTcgMTg6MTc6NTkiLCJkaXJlY3Rpb24iOiJuZXh0In0
That's not just a string it's a URL so use URL and path functions:
$parts = parse_url($str);
echo basename($parts['path']).$parts['query'];
This question already has answers here:
PHP, Delete parts of a URL variable [duplicate]
(3 answers)
Closed 4 years ago.
I want to replace '/50' with URL.my URL is
http://localhost/CI/admin/pcustomer/cprofile/50?customer=18267&mobile=&nearby=
I want url as
http://localhost/CI/admin/pcustomer/cprofile?customer=18267&mobile=&nearby=
From that little info in your question, this seems to be the simplest way to achieve "I want to replace '/50' with URL"
$url = str_replace('/50', '', 'http://localhost/CI/admin/pcustomer/cprofile/50?customer=18267&mobile=&nearby=');
This question already has answers here:
Get path from URL
(2 answers)
Closed 8 years ago.
Can anyone please tell me how to remove url from a string using PHP
I have this string
src="http://cdn1.vox-cdn.com/uploads/chorus_image/image/34918177/layering__1_.0_standard_90.0.png"
Desired Output:
src="/uploads/chorus_image/image/34918177/layering__1_.0_standard_90.0.png"
You can use the parse_url() buil-in php function for this.
For example:
<?php
$url = 'http://cdn1.vox-cdn.com/uploads/chorus_image/image/34918177/layering__1_.0_standard_90.0.png';
$parsed_url = parse_url($url);
var_dump($parsed_url);
?>
Output:
So, after the url is parsed, the bit you want is found on $parsed_url['path']. Hope this helps.
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Detecting a url using preg_match? without in the string
I wanting to search a string that is input by the user, for instances of http:// if one is found I want to wrap the link in the correct html,
so for example, the following could be input by a user,
Google's url is http://www.google.com,
what I want to save that as it,
Google's url is http://www.google.com
is this possible?
function make_clickable($sText) {
$sClickText = str_replace(' www.', ' http://www.', $sText);
$sClickText = preg_replace("/([\s])?(http|ftp|https)([\:\/\/])([^\s]+)/i", " $2$3$4",$sClickText);
return $sClickText;
}
Tadaa!