I am relatively new to PHP and want to know a more efficient way of echo'ing the following in less steps or even just one statement.
$sql = "SELECT * FROM comments";
$result = OpenCon()->query($sql);
while( $row = $result->fetch_assoc()) {
echo "<div class='card'><p class: card-text>";
echo $row['uid']."<br>";
echo $row['date']."<br>";
echo $row['message']."<br><br>";
echo "</p></div>";
As #droopsnoot has commented on above, you should try doing the next thing here.
while( $row = $result->fetch_assoc()) {
echo "<div class='card'><p class: card-text>". $row['uid']."<br>" . $row['date']."<br>".$row['message']."<br><br>". "</p></div>";
}
It should work perfectly.
Another option is to close php tag (?>) and use html markup with <?=$var?>:
<?php
$sql = "SELECT * FROM comments";
$result = OpenCon()->query($sql);
while( $row = $result->fetch_assoc()) {?>
<div class="card">
<p class="card-text">
<?=$row['uid']?><br>
<?=$row['date']?><br>
<?=$row['message']?><br><br>
</p>
</div>
<?php
} // end while
Related
How can I echo inside an html tag? I read some articles here and I understood that I have to put the all HTML tag inside the PHP, but when I do, it won't show the correct layout. I mean, it puts it in the top of the page instead of showing it where it belong. How can I make this work? Attached two pictures to explain my broken english better
<?php
include("config.php");
if ($con->connect_error) {
die("Connection failed: " . $con->connect_error);
}
$sql = "SELECT id FROM users";
$result = $con->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<div class='inner'> <h2 class='major'>How many accounts</h2> <p>We currently have ". $row["id"] . " accounts!</p></div>";
}
} else {
echo "0 results";
}
$con->close();
?>
And I would like to put only row id inside HTML tag because, in the HTML inside PHP it shows the first on the page, it doesn't show where it should belong.
<section id="four" class="wrapper alt style1">
<div class="inner">
<h2 class="major">How many accounts</h2>
<p>We currently have <?php echo $row["id"] ?> accounts!</p>
How it shows now:
How it should look
Why don't you echo $result->num_rows instead of id? What happen if someone close their account or you delete some rows in the middle of table?
I have reached to an answer.
in HTML section I added <?php echo $ID ?> and in the PHP section I modified it with
while($row = $result->fetch_assoc()) {
$ID = $row['id'];
}
Now script looks like this
<?php
include("config.php");
if ($con->connect_error) {
die("Connection failed: " . $con->connect_error);
}
$sql = "SELECT id FROM users";
$result = $con->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$ID = $row['id'];
}
} else {
echo "0 results";
}
$con->close();
?>
and the HTML part
<h2 class="major">How many Accounts?</h2>
<p>Currently we have <?php echo $ID ?> accounts.</p>
Assign a variable to your result.
while($row = $result->fetch_assoc()) {
$id = $row["id"]; }
Then anywhere in your html all you will have to do is the following.
<?php echo $id; ?>
I hope this helps. Have a great day.
$sql = "SELECT * FROM today WHERE heading='$heading' and day='$day'";
$sql1 = "SELECT * FROM today WHERE day='$day'";
$result = $conn->query($sql);
$result1 = $conn->query($sql1);
if ($result->num_rows > 0) {
echo "<div id='post'><h1>".$row["heading"]."</h1>
<aside class='related-post'>".while($row = $result1->fetch_assoc())
{echo'<img src='".$row["image"]."'>;}
.</aside>}";
I have been using while loops for fetching data from table. My connection is working is perfect but I need another loop in the first that is not working. Isn't it the good way?
Update: I tried to finish echo and again started as follow but still an error
while($row = $result->fetch_assoc()) {
echo "<div id='post'><h1>"
.$row["heading"].
"</h1><div class='post-side'><img class='post-image' src='"
.$row["image"].
"'><div class='post-data'><p><strong>Age: </strong><span>$age</span></p><p><strong>Date of birth: </strong><span>"
.$row["day"].
"-"
.$row["month"].
"-"
.$row["year"].
"</span></p></div></div></div><div class='description'><p>"
.$row["description"].
"</p></div><div class='bottom-related'><aside class='related-post'>";
while($row = $result1->fetch_assoc())
{echo"<img src='"
.$row["image"].
"'>/";}.echo"</aside><aside class='ad2'>".$includead."</aside></div>";
}
echo "</div>";
} else {
echo "No table found";
}
$conn->close();
You're trying to concatenate to a string a WHILE loop; this is wrong.
You should echo your first part, end with it and then do your while loop, and echo the end afterwards:
Your quotes are a bit messed up as well
if ($result->num_rows > 0)
{
echo "<div id='post'><h1>".$row["heading"]."</h1>
<aside class='related-post'>";
while($row = $result1->fetch_assoc())
{
echo'<img src="'.$row["image"].'">';
}
echo '</aside>';
}
You can't concatene while with String, it's a syntaxic error
Also, you have a probleme when trying to echo a String, you can use this syntax:
echo "PHP"; // will evaluate PHP variables and whitespace inside a string
echo 'PHP'; // will evaluate nothing;
But you can not start flushing a string ' and finish by " or vice-versa.
Here the correct code :
<?php
$sql = "SELECT * FROM today WHERE heading='$heading' and day='$day'";
$sql1 = "SELECT * FROM today WHERE day='$day'";
$result = $conn->query($sql);
$result1 = $conn->query($sql1);
if ($result->num_rows > 0) {
echo "<div id='post'><h1>" . $row["heading"] . "</h1><aside class='related-post'>";
while($row = $result1->fetch_assoc()) {
echo'<img src="' . $row["image"] .'">';
}
echo "</aside>";
}
<div id="first"></div>
<div id="second"></div>
<div id="third"></div>
Is there any way to print each third database row in a div? So every div gets one row. Like a newsfeed.
I want the first print to be in the fist, second in the second, third in the third, fourth in the first, fifth in the second and so on.
Is this possible? Like skip every third or something. With php
You have to write the code like below. May this helps you.
$result = mysql_query("select * from table_name");
$k=1;
while($row = mysql_fetch_array($result)){
if($k==1){
echo '<div id="first"></div>';
}
if($k==2){
echo '<div id="second"></div>';
}
if($k==3){
echo '<div id="third"></div>';
$k=1;
}
$k++;
}
OR
$result = mysql_query("select * from table_name");
$k=1;
while($row = mysql_fetch_array($result)){
if($k==1){
$div_id = "
}
if($k==2){
$div_id = "second";
}
if($k==3){
$div_id = "third";
$k=1;
}
echo '<div id="'.$div_id.'"></div>';
$k++;
}
I am newbie in php. i am using the following code to get my desired data from mysql database. but what i want to do, whenever database show a result i want to put it into a bootstrap grid( like col-sm-4) each time. Right now my grid is coded in HTML, how can i generate it with the query result each time ? thanks in advance.
<div class="col-sm-4">
<h3>image </h3><br>
<?php
$sql = "SELECT * FROM sctable";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
$link = "http://localhost/sc/uploads/" .$row[1];
echo "<img width='100%' height='200' src=$link />"."<br />";
echo "";
}
?>
</div>
Do you mean something like this where you just want to put each rows data into its own div
<?php
$sql = "SELECT * FROM sctable";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
echo '<div class="col-sm-4">';
echo '<h3>image </h3><br>';
$link = "http://localhost/sc/uploads/" .$row[1];
echo '<img style="width:100%;height:200px" src="' . $link . '"/>';
echo '</div>';
}
?>
Just for future reference, its a bad idea to use the full url for your own site in code like this. If you move it to a live site this code wont work anymore. Better to use relative paths and let the system do some of the work for you. So it should work whatever the domain is where you move the code.
<?php
$sql = "SELECT * FROM sctable";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
echo '<div class="col-sm-4">';
echo '<h3>image </h3><br>';
> Changed next line
$link = "sc/uploads/" .$row[1];
echo '<img style="width:100%;height:200px" src="' . $link . '"/>';
echo '</div>';
}
?>
You can just wrap the image:
echo "<div class='col-sm-4'> <img width='100%' height='200' src='$link' /></div>";
I have now spent several hours without getting anywhere.
I want to display number of rows in my query and here here is my code:
<?php
$user_id = 1;
$statement = $dbConn->query("select badoo_interest.*, badoo_category.icon_class from badoo_interest, badoo_user_interest, badoo_category where badoo_user_interest.interest_id = badoo_interest.id and badoo_user_interest.user_id = :id_user_profile and badoo_category.id = badoo_interest.category_id");
$statement->execute(array(':id_user_profile'=> $id_user_profile));
$rResult = $statement->fetchAll();
echo count($rResult);
echo "<h2>Interesi</h2>";
while( $row = $statement->fetch(PDO::FETCH_ASSOC) ){
?>
<div class="interest" id = "int<?php echo $row['id'];?>">
<span class = "intr-ico <?php echo $row['icon_class'];?>"></span>
<?php echo $row['name'];?>
</div>
<?php
}
?>
And i getting number 10 but now im not getting any interests displayed.
If you use this code now:
<?php
//$user_id = 1;
$statement = $dbConn->query("select badoo_interest.*, badoo_category.icon_class from badoo_interest, badoo_user_interest, badoo_category where badoo_user_interest.interest_id = badoo_interest.id and badoo_user_interest.user_id = :id_user_profile and badoo_category.id = badoo_interest.category_id");
$statement->execute(array(':id_user_profile'=> $id_user_profile));
echo "<p>" . $statement->rowCount(). " interests:</p>";
while( $row = $statement->fetch(PDO::FETCH_ASSOC) ){
?>
<div class="interest" id = "int<?php echo $row['id'];?>">
<span class = "intr-ico <?php echo $row['icon_class'];?>"></span>
<?php echo $row['name'];?>
</div>
<?php
}
?>
And now im getting all the interests displayed but it counts: 0 interests.
Any ideas who i can count number of interests?
If you read the documentation for PDOStatement::rowCount you will see this line
If the last SQL statement executed by the associated PDOStatement was
a SELECT statement, some databases may return the number of rows
returned by that statement. However, this behaviour is not
guaranteed for all databases and should not be relied on for portable
applications.
The work around is to count() function from php like you did. If that did not work then use COUNT(*) as result_count. then when you fetch read that value.
And i getting number 10 but now im not getting any interests displayed
problem
The reason why the result aren't displaying is because you fetched all the row already so you cannot use fetch() again.
solution
Use the array returned by fetchAll() instead and use a foreach instead
$rows = $statement->fetchAll();
echo "<p>" . count($rows). " interests:</p>";
foreach ($rows as $row){
//echo $row['name']
}
<?php
//$user_id = 1;
$statement = $dbConn->query("select badoo_interest.*, badoo_category.icon_class from badoo_interest, badoo_user_interest, badoo_category where badoo_user_interest.interest_id = badoo_interest.id and badoo_user_interest.user_id = :id_user_profile and badoo_category.id = badoo_interest.category_id");
$statement->execute(array(':id_user_profile'=> $id_user_profile));
echo "<p>" . $statement->rowCount(). " interests:</p>";
$counter = 0; //declare counter
while( $row = $statement->fetch(PDO::FETCH_ASSOC) ){
$counter++; //increment counter
?>
<div class="interest" id = "int<?php echo $row['id'];?>">
<span class = "intr-ico <?php echo $row['icon_class'];?>"></span>
<?php echo $row['name'];?>
</div>
<?php
}
?>
[NOTE: Edit by #DinoAmino removed the emphasis characters around the two uses of $counter, which caused the code to not compile for the question asker]
I solved my problem like this:
Here is the updated solving version. Thank you all for the input:
<?php
$user_id = 1;
$statement = $dbConn->query("select badoo_interest.*, badoo_category.icon_class from badoo_interest, badoo_user_interest, badoo_category where badoo_user_interest.interest_id = badoo_interest.id and badoo_user_interest.user_id = :id_user_profile and badoo_category.id = badoo_interest.category_id");
$statement->execute(array(':id_user_profile'=> $id_user_profile));
$rows = $statement->fetchAll();
if(count($rows) >= '1') {
?>
<div class="your-interests">
<?php
echo "<p>" . count($rows). " interests:</p>";
foreach ($rows as $row){
?>
<div class="interest" id = "int<?php echo $row['id'];?>">
<span class = "intr-ico <?php echo $row['icon_class'];?>"></span>
<?php echo $row['name'];?>
</div>
<?php
}
?>
</div>
<?php } ?>