$sql = "SELECT * FROM today WHERE heading='$heading' and day='$day'";
$sql1 = "SELECT * FROM today WHERE day='$day'";
$result = $conn->query($sql);
$result1 = $conn->query($sql1);
if ($result->num_rows > 0) {
echo "<div id='post'><h1>".$row["heading"]."</h1>
<aside class='related-post'>".while($row = $result1->fetch_assoc())
{echo'<img src='".$row["image"]."'>;}
.</aside>}";
I have been using while loops for fetching data from table. My connection is working is perfect but I need another loop in the first that is not working. Isn't it the good way?
Update: I tried to finish echo and again started as follow but still an error
while($row = $result->fetch_assoc()) {
echo "<div id='post'><h1>"
.$row["heading"].
"</h1><div class='post-side'><img class='post-image' src='"
.$row["image"].
"'><div class='post-data'><p><strong>Age: </strong><span>$age</span></p><p><strong>Date of birth: </strong><span>"
.$row["day"].
"-"
.$row["month"].
"-"
.$row["year"].
"</span></p></div></div></div><div class='description'><p>"
.$row["description"].
"</p></div><div class='bottom-related'><aside class='related-post'>";
while($row = $result1->fetch_assoc())
{echo"<img src='"
.$row["image"].
"'>/";}.echo"</aside><aside class='ad2'>".$includead."</aside></div>";
}
echo "</div>";
} else {
echo "No table found";
}
$conn->close();
You're trying to concatenate to a string a WHILE loop; this is wrong.
You should echo your first part, end with it and then do your while loop, and echo the end afterwards:
Your quotes are a bit messed up as well
if ($result->num_rows > 0)
{
echo "<div id='post'><h1>".$row["heading"]."</h1>
<aside class='related-post'>";
while($row = $result1->fetch_assoc())
{
echo'<img src="'.$row["image"].'">';
}
echo '</aside>';
}
You can't concatene while with String, it's a syntaxic error
Also, you have a probleme when trying to echo a String, you can use this syntax:
echo "PHP"; // will evaluate PHP variables and whitespace inside a string
echo 'PHP'; // will evaluate nothing;
But you can not start flushing a string ' and finish by " or vice-versa.
Here the correct code :
<?php
$sql = "SELECT * FROM today WHERE heading='$heading' and day='$day'";
$sql1 = "SELECT * FROM today WHERE day='$day'";
$result = $conn->query($sql);
$result1 = $conn->query($sql1);
if ($result->num_rows > 0) {
echo "<div id='post'><h1>" . $row["heading"] . "</h1><aside class='related-post'>";
while($row = $result1->fetch_assoc()) {
echo'<img src="' . $row["image"] .'">';
}
echo "</aside>";
}
Related
I am new in php. I make a quiz app and I want to show questions that is not repeated again . here's my code.
Please help me to show require result.
<?php
include('connect.php');
$sql = "SELECT * FROM quiz_question WHERE theme_id= 2 ORDER BY RAND ()";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$id = $row['id'];
echo "
<h2>" . $row["question"]. "</h2>";
break;
}
}
$check_id = array ($row['id']);
echo $check_id['0'];
if(array ($row['id']) == $check_id){
echo "no question ";
}
else{
echo "
<h2>" . $row["question"]. "</h2>";
}
?>
Your question is not clear. But I guess, you can solve it by array_unique($array).
array_unique($array);
<?php
include('connect.php');
$sql = "SELECT * FROM quiz_question WHERE theme_id= 2 ORDER BY RAND ()";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$id = $row['id'];
$question = $row['question'];
echo "
<h2>" . $row["question"]. "</h2>";
$check_id = array($id);
}
}
$check_id_unique=array_unique($check_id);
?>
I'm trying to get this to echo a warning message when the cell contains a certain text like "0" or "N/A". It would work when there was no value entered in the first place, but I can't get it to echo when there is already a certain value. Any help would be great. Thanks!
<?php
$listing = "$_POST[listing]";
$sql = "SELECT open_house_attended FROM property_flyers WHERE street_property = '$listing' ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "</span><span class='report_bignumber'><br>". $row["open_house_attended"]."</span>";
}
} else {
echo "<br> ". $noresults . "</span>";
}
?>
You can use a little regex -
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
preg_match(trim($row["open_house_attended"]), '/[0]|[N\/A]/', $matches); // try to match '0' or 'N/A'
if(count($matches) == 0) { // do we have matches?
echo "</span><span class='report_bignumber'><br>". $row["open_house_attended"]."</span>";
} else {
echo "<br> ". $noresults . "</span>";
}
}
}
?>
Or you can go a little more directly -
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$ohCount = $row["open_house_attended"];
if(( $ohCount != '0') && ($ohCount != 'N/A')) { // do we have matches?
echo "</span><span class='report_bignumber'><br>". $ohCount ."</span>";
} else {
echo "<br> ". $noresults . "</span>";
}
}
}
?>
preg_match()
$sql = "SELECT open_house_attended FROM property_flyers WHERE street_property = '$listing' AND open_house_attended NOT IN ('0', 'N/A')";
use NOT IN and a list of values to reject. It's one option anyway. The preg match option works as well, just it asks php to do the work and this asks sql to do it.
I'm not very sure how can I put them into words. I'm trying to display result in each div as shown in the image but unfortunately I'm only able to make it appear only in the "request for quote" div.
May I know where have I gone wrong?
<?php
$query2 = "SELECT * FROM client c, sales_card s WHERE c.id = s.client_id and emp_id_followup = '".$_SESSION["ID"]."'";
$result2 = mysql_query($query2);
if (mysql_num_rows($result2) > 0) {
while($row2 = mysql_fetch_assoc($result2)) {
$swimlaneID = $row2['swimlane_id'];
}
}
$query = "SELECT * FROM swimlane";
$result = mysql_query($query);
if (mysql_num_rows($result) > 0) {
while($row = mysql_fetch_assoc($result)) {
echo '<div id="right">';
echo '<div style="border-style:solid; height:1020px;">';
echo '<h2>'. $row["swimlane_name"].'</h2>';
echo '<ul id="'. $row["shortform"].'">';
if ($swimlaneID == $row["id"])
{
echo $display-> $row["shortform"]();
}
echo '</ul>';
echo '</div>';
echo '</div>';
}
}else{
echo "no row";
}
?>
We have a basic PHP script to extract the title and description for each job from a MySQL database as simply display this information. This is what it looks like:
$sql = "SELECT `title`, `desc` FROM jobs WHERE active = 'y'";
$query = mysql_query($sql) or die('<em><strong>SQL Error:</strong> ' . mysql_error() . '</em>');
$results = mysql_fetch_assoc($query);
<?php while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$results['title']}</h2>";
echo "<p>{$results['desc']}</p>";
echo '</div>';
} ?>
Now, this only extracts one row from the database, but it should extract two. So, I tried the following to replace the while statement:
<?php foreach($results as $result) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$result['title']}</h2>";
echo "<p>{$result['desc']}</p>";
echo '</div>';
} ?>
This statement doesn't work either. This just displays (weirdly) the first character of each column in the first row in the table.
Does anyone have any idea as to why this isn't working as it should?
In your while use same variable $result as you started:
while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$result['title']}</h2>";
echo "<p>{$result['desc']}</p>";
echo '</div>';
}
and remove the first $results = mysql_fetch_assoc($query);
Result variable you have used is result not results
Replace
$sql = "SELECT `title`, `desc` FROM jobs WHERE active = 'y'";
$query = mysql_query($sql) or die('<em><strong>SQL Error:</strong> ' . mysql_error() . '</em>');
**$results = mysql_fetch_assoc($query);** // remove this line
<?php while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$results['title']}</h2>";
echo "<p>{$results['desc']}</p>";
echo '</div>';
} ?>
to
$sql = "SELECT `title`, `desc` FROM jobs WHERE active = 'y'";
$query = mysql_query($sql) or die('<em><strong>SQL Error:</strong> ' . mysql_error() . '</em>');
<?php while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$result['title']}</h2>";
echo "<p>{$result['desc']}</p>";
echo '</div>';
} ?>
You already fetched the first row before your loop started, which is why it only prints the second row. Simply comment out that line:
#$results = mysql_fetch_assoc($query); # here is your first row,
# simply comment this line
<?php while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$result['title']}</h2>";
echo "<p>{$result['desc']}</p>";
echo '</div>';
} ?>
You are also looping over $result but using $results in your while loop body.
Check this:
$sql = "SELECT `title`, `desc` FROM jobs WHERE active = 'y'";
$query = mysql_query($sql) or die('<em><strong>SQL Error:</strong> ' . mysql_error() . '</em>');
<?php
while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$result['title']}</h2>";
echo "<p>{$result['desc']}</p>";
echo '</div>';
}
?>
Change this line
<?php while($result = mysql_fetch_assoc($query)) {
to
<?php while($results = mysql_fetch_assoc($query)) {
I have a php script that tries to find a particular name in a database where the specified program is $q, a variable passed from an html page. I'm very new to this so I'm having trouble figuring out how to code an if not found, then display type of message. Below is what I currently have:
$sql="SELECT * FROM names WHERE program='".$q."'";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
echo "<div class='header'>Program Name:</div>";
echo "<div class='data'>";
echo $row['program'];
echo "</div>";
}
And I need it to echo a message saying if nothing was found. I tried looking at NOT IN condition in SQL and http://www.techonthenet.com/sql/exists.php along with other things on the internet but I'm not sure if this is the right thing to use. Any help would be appreciated.
use th php function
mysql_num_rows($result);
to check results found
So your code should be like:
$sql="SELECT * FROM names WHERE program='".addslashes($q)."'";
$result = mysql_query($sql);
if(mysql_num_rows($result) > 0)
while($row = mysql_fetch_array($result))
{
echo "<div class='header'>Program Name:</div>";
echo "<div class='data'>";
echo $row['program'];
echo "</div>";
}
else
echo "No data found";
please note i added
addslashes($q)
in query, in order to avoid SQL injection problems.
$sql="SELECT * FROM names WHERE program='".$q."'";
$result = mysql_query($sql);
$found = false;
while($row = mysql_fetch_array($result))
{
$found = true;
echo "<div class='header'>Program Name:</div>";
echo "<div class='data'>";
echo $row['program'];
echo "</div>";
}
if ($found == false)
echo "I found nothing";