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Regex matching 5-digit substrings not enclosed with digits
(2 answers)
Retrieve exactly 1 digit using regular expression in python
(3 answers)
Closed 1 year ago.
I'm looking to match numbers that are either 1 or 2 digit (but not more) long so I can add leading zeroes. My input strings look like these:
LL.1 ETX 189
1.20.3.4[8]
1.30.4[17]
229.c.85.8[4]
62.c.80.11
RR 60 H 2
R.60 H 2
Y.11.25[28]
Abc T.14.55
LL 108 ETX 189
Content 1364
With the application of the regex I would hope to identify the following:
LL.1 ETX 189 => match: 1
1.20.300.4[8] => match: 1, 20, 4, 8
1.30.4[17] => match: 1, 30, 4, 17
229.c.85.8[4] => match: 85,8,4
62.c.80.11 => match: 62, 80, 11
RR 60 H 2 => match: 60, 2
R.60 H 2 => match: 60, 2
Y.11.25[28] => match: 11, 25, 28
Abc T.14.55 => match: 14, 55
Whilst ignoring:
LL 108 ETX 189
Content 1364
I thought doing something as simple as: ([1-90-9]{1,2}) would work but this returns the following:
LL.1 ETX 189 => match: 1, 18, 9
1.20.300.4[8] => match: 1, 20, 30, 0, 4, 8
1.30.4[17] => match: 1, 30, 4, 17
229.c.85.8[4] => match: 22, 9, 85,8,4
62.c.80.11 => match: 62, 80, 11
RR 60 H 2 => match: 60, 2
R.60 H 2 => match: 60, 2
Y.11.25[28] => match: 11, 25, 28
Abc T.14.55 => match: 14, 55
LL 108 ETX 189 => match: 10, 8, 18, 9
Content 1364 => match: 13, 64
Any suggestions on how I can achieve this?
I've had a look at this question: 'RegEx Expression /w limited length and chars' and this one: Regex match one digit or two..
Related
Hello guys I have a small question that suppose I have a string as
"Hello My name is XYZ"
Now I know I can find the length of the words as "Hello" has 5 characters and "My" has 2 characters. By using following code
$text = file_get_contents('text.txt'); // $text = 'Hello my name is XYZ';
$words = str_word_count($text, 1);
$wordsLength = array_map(
function($word) { return mb_strlen($word, 'UTF-8'); },
$words
);
var_dump(array_combine($words, $wordsLength));
But what if i want to find that the number of words with length 1 is 0. The number of words with lengths 2 is 2. The number of words with length 3 is 1 and so on till number of length 10
Note- I am considering the word length till there is a space Suppose there is a date in the data like 20.04.2016 so it should show me that the number is words with length 10 is 1.
and one more thing how do I find the average length for the words in the string.
Thank you in advance
If you use array_count_values() on the $wordsLength array it will give a count of the string lengths there are. If you use this and a template array (created using array_fill()) with the elements 1-10 and a value of 0. You will get a list of all of the word counts...
$counts = array_replace(array_fill(1, 9, 0),
array_count_values($wordsLength));
will give...
Array
(
[1] => 0
[2] => 2
[3] => 1
[4] => 1
[5] => 1
[6] => 0
[7] => 0
[8] => 0
[9] => 0
)
Hi try this it works on the date and special chars,emojis
$text = 'Hello 20.04.2016 🚩 my face😘face is XYZ';
$words =preg_split('/\s+/', $text);
$wordsLength = array_map(
function($word) { return mb_strlen($word, 'UTF-8'); } ,$words);
print_r($words);
//Get Average word Length
$avg=round(array_sum($wordsLength)/count($words),1);
//print Avg
print($avg);
?>
(Demo)
$text = ' Hello 20.04.2016 🚩 my incredibleness face😘face is XYZ ';
Generate array of continuous visible characters
$words = preg_split('/\s+/', $text, 0, PREG_SPLIT_NO_EMPTY);
array (
0 => 'Hello',
1 => '20.04.2016',
2 => '🚩',
3 => 'my',
4 => 'incredibleness',
5 => 'face😘face',
6 => 'is',
7 => 'XYZ',
)
Replace visible strings with their multibyte length notice the simpler syntax
$wordsLength = array_map('mb_strlen', $words);
array (
0 => 5,
1 => 10,
2 => 1,
3 => 2,
4 => 14,
5 => 9,
6 => 2,
7 => 3,
)
Group and count lengths
$lengthCounts = array_count_values($wordsLength);
array (
5 => 1,
10 => 1,
1 => 1,
2 => 2,
14 => 1,
9 => 1,
3 => 1,
)
Establish an array of defaults, because $lengthCounts may have gaps
$defaultCounts = array_fill_keys(range(1,10), 0);
array (
1 => 0,
2 => 0,
3 => 0,
4 => 0,
5 => 0,
6 => 0,
7 => 0,
8 => 0,
9 => 0,
10 => 0,
)
Filter the counts to remove elements/counts that are out-of-range
$filteredCounts = array_intersect_key($lengthCounts, $defaultCounts);
array (
5 => 1,
10 => 1,
1 => 1,
2 => 2,
9 => 1,
3 => 1,
)
Overwrite the defaults with found counts to prevent gaps in the output
$gaplessCounts = array_replace($defaultCounts, $filteredCounts);
array (
1 => 1,
2 => 2,
3 => 1,
4 => 0,
5 => 1,
6 => 0,
7 => 0,
8 => 0,
9 => 1,
10 => 1,
)
My question is different from this one. I am trying to fix a broken encoding but I don't know how to proceed.
In my database I have this name:
mysql> select filename from file WHERE filename LIKE 'MAC%';
+-------------------------------------------------+
| filename |
+-------------------------------------------------+
| MAC-1600PVå–扱説明書.pdf |
+-------------------------------------------------+
1 row in set (0.00 sec)
But on my filesystem the file is named:
$ ls files/*MAC*
files/MAC-1600PV取扱説明書.pdf
I have tried to unpack both strings from PHP and the content differ:
The utf-8 sequence read from the filesystem:
=> "MAC-1600PV取扱説明書"
>>> unpack('C*', $u)
...
7 => 48,
8 => 48,
9 => 80,
10 => 86,
11 => 195,
12 => 165,
13 => 226,
14 => 128,
15 => 147,
16 => 195,
17 => 166,
18 => 226,
And for the one read from the database:
...
7 => 48,
8 => 48,
9 => 80,
10 => 86,
11 => 229,
12 => 143,
13 => 150,
14 => 230,
15 => 137,
16 => 177,
So at some-point I lost the original encoding and I have no clue of how to fix my database which is in utf8mb4.
Any advice?
I have to make this kind of structure in array;
We have three ( 3 ) variables which creates this structure:
$numberOfParticipants = 38; // 38 is example
$numberOfParticipantsPerHeat = 8 // 8 is example
$numberOfHeats = 5; // 5 is example
Based on this variables I have this table:
The problem is that, I can't place the ' - ' or null after 31 OR 38. The task is that i have to make the arrays of array "almost equal" like the photo and must depend on the variables above. By the way, after I create the correct list I will slice the array to 5 or 6 or whatever parts I need this is not the problem, the problem is that I have to parse the list like this first. This is what I tried so far:
$calc1 = (int)round($numberOfParticipants * $numberOfParticipantsPerHeat, -1); //First round the numberOfParticipants to closest integer by 10
$readyArr = [];
for ($i = 1; $i <= $calc1; $i++) {
if ($i <= $numberOfParticipants) {
$readyArr[$i] = $i;
} else {
$readyArr[$i] = null;
}
}
The problem with this snippet is that it places the null at the end of the list not after 31, or based on the var.
This is the result I have:
array:40 [▼
1 => 1
2 => 2
3 => 3
4 => 4
5 => 5
6 => 6
7 => 7
8 => 8
9 => 9
10 => 10
11 => 11
12 => 12
13 => 13
14 => 14
15 => 15
16 => 16
17 => 17
18 => 18
19 => 19
20 => 20
21 => 21
22 => 22
23 => 23
24 => 24
25 => 25
26 => 26
27 => 27
28 => 28
29 => 29
30 => 30
31 => 31
32 => 32
33 => 33
34 => 34
35 => 35
36 => 36
37 => 37
38 => 38
39 => null
40 => null
]
The Array after partition I want should be:
array(
0 => array(0 => 1, 1 => 2, 2 => 3, 3 => 4, 4 => 5, 5 => 6, 6 => 7, 7 => 8,),
1 => array(0 => 9, 1 => 10, 2 => 11, 3 => 12, 4 => 13, 5 => 14, 6 => 15, 7 => 16,),
2 => array(0 => 17, 1 => 18, 2 => 19, 3 => 20, 4 => 21, 5 => 22, 6 => 23, 7 => 24,),
3 => array(0 => 25, 1 => 26, 2 => 27, 3 => 28, 4 => 29, 5 => 30, 6 => 31, 7 => null,),
4 => array(0 => 32, 1 => 33, 2 => 34, 3 => 35, 4 => 36, 5 => 37, 6 => 38, 7 => null,),
);
Every help, every clue will be highly appreciated.
There are two things you need to know about the target structure:
How many players are in the first (which will always be the largest, if only by one) set.
$playersPerHeat = ceil($numberOfParticipants / $numberOfHeats);
// note this replaces your hard-coded $numberOfParticipantsPerHeat
You also need to know how many heats actually have that many, that is how many heats are actually full.
$fullHeats = $numberOfParticipants % $numberOfHeats ?: $numberOfHeats;
// The ?: bit means that if we get zero (ie. all equal heats), then we
// count all the heats instead, since they're all full.
Now it's easy!
$players = range(1,$numberOfParticipants);
$heats = array_merge(
array_chunk(
array_slice($players, 0, $fullHeats * $playersPerHeat),
$playersPerHeat
),
array_chunk(
array_slice($players, $fullHeats * $playersPerHeat),
$playersPerHeat - 1
)
);
That's it! Demo
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So I have an array like this:
[
543 => 1,
22 => 3,
65 => 4,
10 => 5,
50 => 6,
]
Now I get a key and a value as input. For example 22 as key and 5 as value.
Now I want to use those two inputs as start and end point in my array and want to shift all keys one forward between those two positions.
[
543 => 1,
22 => 3, ─┐ ┌─ 65 => 3,
65 => 4, ├ Shift all those keys one forward to: ┤ 10 => 4,
10 => 5, ─┘ └─ 22 => 5,
50 => 6,
]
So the expected output would be:
[
543 => 1,
65 => 3,
10 => 4,
22=> 5,
50 => 6,
]
Figure out the start and end offset from your inputs in your array:
$startIndex = array_search(22, array_keys($arr));
$endIndex = array_search(5 , array_values($arr));
//↑ Your input
So for your example array this would look like this:
[
543 => 1, //Offset: 0
22 => 3, //Offset: 1 ← 22 found; offset: 1
65 => 4, //Offset: 2
10 => 5, //Offset: 3 ← 5 found; offset: 3
50 => 6, //Offset: 4
]
Split your array into three parts:
$before = array_slice($arr, 0, $startIndex, true);
$data = array_slice($arr, $startIndex, ($endIndex - $startIndex) + 1, true);
$after = array_slice($arr, $endIndex, null, true);
Visualized this would look like this:
[
543 => 1, → $before; Where you do NOT want to shift your keys
22 => 3, ┐
65 => 4, ├ $data; Where you want to shift your leys
10 => 5, ┘
50 => 6, → $after; Where you do NOT want to shift your keys
]
Rotate the data part keys, just by merging the last key at the start with the other keys at the end:
$keys = array_keys($data);
$keys = array_merge(array_slice($keys, -1), array_slice($keys, 0, -1));
$data = array_combine($keys, $data);
Put it all back together:
$arr = $before + $data + $after;
I have searched a number of different items but I have not found any answers. Chances are I just don't know how to word this correctly.
Anyway, I have set up a system in PHP/SQL to allow instantaneous scanning of thousands of results. Each data entry has 4 numbers, and it can easily scan for entries that match all 4 of these numbers. What I am trying to achieve is to have the script search the database for entries that match exactly 3 out of the 4 entries with the other being incorrect, kind of like a lottery.
For example, we have the entries:
Steve - 1, 4, 10, 13
Bill - 3, 4, 10, 13
Tom - 1, 17, 20, 39
Jill - 1, 4, 13, 21
Jane - 5, 10, 13, 18
Now, I would scan based on the results 1, 4, 10, 13, and would like to return the following results, as these matched 3 of the 4 entries:
Bill - 3, 4, 10, 13
Jill - 1, 4, 13, 21
How would I achieve this?
Many thanks
EDIT: Sorry yes the table has the structure
Name - Number1 - Number2 - Number3 - Number4
So yes, stored as separate fields
You can do this by counting the matches and setting this equal to 3:
select t.*
from t
where (val1 in (1, 4, 10, 13) +
val2 in (1, 4, 10, 13) +
val3 in (1, 4, 10, 13) +
val4 in (1, 4, 10, 13)
) = 3;
In MySQL a TRUE boolean expression evaluates to 1. You can add these together to get the number of matches.