How do i find the occurence of words of particular number - php

Question

Hello guys I have a small question that suppose I have a string as
"Hello My name is XYZ"
Now I know I can find the length of the words as "Hello" has 5 characters and "My" has 2 characters. By using following code
$text = file_get_contents('text.txt'); // $text = 'Hello my name is XYZ';
$words = str_word_count($text, 1);
$wordsLength = array_map(
function($word) { return mb_strlen($word, 'UTF-8'); },
$words
);
var_dump(array_combine($words, $wordsLength));
But what if i want to find that the number of words with length 1 is 0. The number of words with lengths 2 is 2. The number of words with length 3 is 1 and so on till number of length 10
Note- I am considering the word length till there is a space Suppose there is a date in the data like 20.04.2016 so it should show me that the number is words with length 10 is 1.
and one more thing how do I find the average length for the words in the string.
Thank you in advance

Answer 1

If you use array_count_values() on the $wordsLength array it will give a count of the string lengths there are. If you use this and a template array (created using array_fill()) with the elements 1-10 and a value of 0. You will get a list of all of the word counts...
$counts = array_replace(array_fill(1, 9, 0),
array_count_values($wordsLength));
will give...
Array
(
[1] => 0
[2] => 2
[3] => 1
[4] => 1
[5] => 1
[6] => 0
[7] => 0
[8] => 0
[9] => 0
)

Answer 2

Hi try this it works on the date and special chars,emojis
$text = 'Hello 20.04.2016 🚩 my face😘face is XYZ';
$words =preg_split('/\s+/', $text);
$wordsLength = array_map(
function($word) { return mb_strlen($word, 'UTF-8'); } ,$words);
print_r($words);
//Get Average word Length
$avg=round(array_sum($wordsLength)/count($words),1);
//print Avg
print($avg);
?>

Answer 3

(Demo)
$text = ' Hello 20.04.2016 🚩 my incredibleness face😘face is XYZ ';
Generate array of continuous visible characters
$words = preg_split('/\s+/', $text, 0, PREG_SPLIT_NO_EMPTY);
array (
0 => 'Hello',
1 => '20.04.2016',
2 => '🚩',
3 => 'my',
4 => 'incredibleness',
5 => 'face😘face',
6 => 'is',
7 => 'XYZ',
)
Replace visible strings with their multibyte length notice the simpler syntax
$wordsLength = array_map('mb_strlen', $words);
array (
0 => 5,
1 => 10,
2 => 1,
3 => 2,
4 => 14,
5 => 9,
6 => 2,
7 => 3,
)
Group and count lengths
$lengthCounts = array_count_values($wordsLength);
array (
5 => 1,
10 => 1,
1 => 1,
2 => 2,
14 => 1,
9 => 1,
3 => 1,
)
Establish an array of defaults, because $lengthCounts may have gaps
$defaultCounts = array_fill_keys(range(1,10), 0);
array (
1 => 0,
2 => 0,
3 => 0,
4 => 0,
5 => 0,
6 => 0,
7 => 0,
8 => 0,
9 => 0,
10 => 0,
)
Filter the counts to remove elements/counts that are out-of-range
$filteredCounts = array_intersect_key($lengthCounts, $defaultCounts);
array (
5 => 1,
10 => 1,
1 => 1,
2 => 2,
9 => 1,
3 => 1,
)
Overwrite the defaults with found counts to prevent gaps in the output
$gaplessCounts = array_replace($defaultCounts, $filteredCounts);
array (
1 => 1,
2 => 2,
3 => 1,
4 => 0,
5 => 1,
6 => 0,
7 => 0,
8 => 0,
9 => 1,
10 => 1,
)