I just want to build a php function that checking if string is contain brackets and return boolean, anyone can help?
example:
$string = "{hallo}"; // true
$string2 = "h{allo}"; //true
$string3 = "hal}{o"; //false
$string4 = "hallo{}";//false
Check this
<?php
$string = "{hallo}";
$res = preg_match('/{\w+}/',$string);
print_r($res);
?>
Related
need to extract an info from a string which strats at 'type-' and ends at '-id'
IDlocationTagID-type-area-id-492
here is the string, so I need to extract values : area and 492 from the string :
After 'type-' and before '-id' and after 'id-'
You can use the preg_match:
For example:
preg_match("/type-(.\w+)-id-(.\d+)/", $input_line, $output_array);
To check, you may need the service:
http://www.phpliveregex.com/
P.S. If the function preg_match will be too heavy, there is an alternative solution:
$str = 'IDlocationTagID-type-area-id-492';
$itr = new ArrayIterator(explode('-', $str));
foreach($itr as $key => $value) {
if($value === 'type') {
$itr->next();
var_dump($itr->current());
}
if($value === 'id') {
$itr->next();
var_dump($itr->current());
}
}
This is what you want using two explode.
$str = 'IDlocationTagID-type-area-id-492';
echo explode("-id", explode("type-", $str)[1])[0]; //area
echo trim(explode("-id", explode("type-", $str)[1])[1], '-'); //492
Little Simple ways.
echo explode("type-", explode("-id-", $str)[0])[1]; // area
echo explode("-id-", $str)[1]; // 492
Using Regular Expression:
preg_match("/type-(.*)-id-(.*)/", $str, $output_array);
print_r($output_array);
echo $area = $output_array[1]; // area
echo $fnt = $output_array[2]; // 492
You can use explode to get the values:
$a = "IDlocationTagID-type-area-id-492";
$data = explode("-",$a);
echo "Area ".$data[2]." Id ".$data[4];
$matches = null;
$returnValue = preg_match('/type-(.*?)-id/', $yourString, $matches);
echo($matches[1]);
It might seem easy to do but I have trouble extracting this string. I have a string that has # tags in it and I'm trying to pull the tags maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa
And here is what I want to extract 33.536759,-7.613825,17z :
$var = preg_match_all("/#(\w*)/",$path,$query);
Any way I can do this? Much appreciated.
Change your regex to this one: /#([\w\d\.\,-]*)/.
This will return the string beginning with #.
$string = 'maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa';
$string = explode('/',$string);
//$coordinates = substr($string[3], 1);
//print_r($coordinates);
foreach ($string as $substring) {
if (substr( $substring, 0, 1 ) === "#") {
$coordinates = $substring;
}
}
echo $coordinates;
This is working for me:
$path = "maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa";
$var = preg_match_all("/#([^\/]+)/",$path,$query);
print $query[1][0];
A regex would do.
/#(-*\d+\.\d+),(-*\d\.\d+,\d+z*)/
If there is only one # and the string ends with / you can use the following code:
//String
$string = 'maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa';
//Save string after the first #
$coordinates = strstr($string, '#');
//Remove #
$coordinates = str_replace('#', '', $coordinates);
//Separate string on every /
$coordinates = explode('/', $coordinates );
//Save first part
$coordinates = $coordinates[0];
//Do what you want
echo $coordinates;
do like this
$re = '/#((.*?),-(.*?),)/mi';
$str = 'maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa';
preg_match_all($re, $str, $matches);
echo $matches[2][0].'<br>';
echo $matches[3][0];
output
33.536759
7.613825
I have this string
$s = 'Yo be [diggin = array("fruit"=> "apple")] scriptzors!';
which then gets checked by
$matches = null;
preg_match_all('/\[(.*?)\]/', $s, $matches);
var_dump($matches[1]);
but what I want it to do is the following, it should return the following
print "yo be";
$this->diggin(SEND ARRAY HERE);
print "scriptzors!";
EDIT to show issue with below answer
$s = 'Yo be [diggin = array("fruit"=>"apple")] scriptzors!';
$matches = null;
preg_match_all('/\[(.*?)\]/', $s, $matches);
$var = explode(' = ', $matches[1]);
print $var[0]; //THIS DOES NOT PRINT
You're sort of close. You can explode the string with = but with spaces included around the =. Then the first element would be the function name, in this case diggin and the second element would be the array but as a string. You'll need to eval that one so that it'll be a proper array data type.
$var = explode(' = ', $matches[1][0]);
call_user_func_array(array($this, $var[0]), eval($var[1] . ';'));
// or do
$this->{var[0]}(eval($val[1] . ';'));
As an alternative, you can also modify the regex so that you don't have to call explode.
preg_match_all('/\[([a-z0-9_]*)\s*?=\s*(.*)\]/i', $s, $matches);
Either way, you'll want to make sure that you sanitize the user input because eval can be evil.
This will call the function without using eval and exposing yourself to code injection.
preg_match_all('/\[([a-z0-9_]*)\s*?=\s*array\((.*)*\)\]/i', $s, $matches);
$var = explode(',', $matches[2][0]);
$result = array();
foreach ($var as $value) {
$keyvaluepair = explode('=>', $value);
$result[$keyvaluepair[0]] = $keyvaluepair[1];
}
$this->{var[0]}($result);
Ok to be clear ill give an example
$email = 'name#example.com';
$domain = strstr($email, '#');
echo $domain; // prints #example.com
$user = strstr($email, '#', true); // As of PHP 5.3.0
echo $user; // prints name
as it says, it prints what before '#' using true, and blank to print what follows #
im looking for a function to print # itself by giving it 2 strings and grab what between them
like this
$string= 'someXthing';
$tograb = phpfunction("some","thing");
echo $tograb; // should be printing X
^ this doesnt work, im just writing it to explain
I dont know of a native function that does that but you can use regular expression
$string= 'someXthing';
preg_match("/some(.*)thing/",$string,$matches);
var_dump($matches[1]);
Read More about preg_match
From internet
function GetBetween($content,$start,$end){
$r = explode($start, $content);
if (isset($r[1])){
$r = explode($end, $r[1]);
return $r[0];
}
return '';
}
Original code
For the example you said, you can use strpos to print X like this:
$string = 'someXthing';
$start = strpos($string, "some") + strlen("some");
$end = strpos($string, "thing", $start);
$tograb = substr($string, $start, $end - $start);
echo $tograb;
and X will be printed.
I am trying to trim a string in PHP so that I can only get certain text from the String.
I have an email stored to a String for instance some_name#somedomain.com .
How can I remove the text after the '#' so that I would only 'some_name'?
In PHP you can do :
$string = 'some_name#somedomain.com';
$res = explode('#', $string);
echo $res[0];
Or you can use regexp, string functions in php ... etc
You should know both ways to do this:
substr
$mail = "some_name#somedomain.com";
echo substr($mail, 0, strpos($mail, '#') );
explode
list($name, $domain) = explode('#', $mail);
echo $name;
If you don't need the $domain you can skip it:
list($name) = explode('#', $mail);
More about list.
Demo: http://ideone.com/lbvQF
$str = 'some_name#somedomain.com';
$strpos = strpos($str, "#");
echo $email = substr($str, 0,$strpos);
you can try this to get string before #
Try This
$str1 = "Hello World";
echo trim($str1,"World");
You could try split using regex and the # symbol. This will return two Strings which you can then use just to acquire the 'some_name'.
http://docs.oracle.com/javase/1.4.2/docs/api/java/lang/String.html
String s = "some_name#somedomain.com";
String name = s.substring(0,s.indexOf("#");