I want take multiple values from the database using Ajax, for which I'm using the following code:
public function getParty($party_id){
$party_info = Credits::where('party_id',$party_id)->get();
foreach($party_info as $row)
{
$tariff_type=$row['vehicle_type'];
}
$tariff = Tariff::where('nozzel_type',$tariff_type)->get();
$Party_info=compact($party_info);
$Tariff =compact($tariff);
$data =[$party_info,$tariff];
return response()->json($data);
}
In this code, I'm taking $party_info and $tariff and sending them in response, I found a solution to put both in a new object like I did into $data, to get these values in my view file I use the following code:
if(data){
$.each(data, function(key, value){
var p_amount = value.pending_amount;
var new_tariff = value.price;
document.getElementById('current_amount').value=new_tariff;
document.getElementById('pending_amount').value=p_amount;
});
}
If I send a single parameter through this method, it works, but with multiple parameters, it is notworking
return response()->json(['Party_info'=>$Party_info,'Tariff'=>$Tariff]);
Related
Allow me to preface this by saying that I looked at multiple SO posts on this and I am still lost.
So in my php code I am fetching data from my database and then I am trying to insert it into an array as follows:
$arrayResult = array();
foreach ($result as $item) {
array_push($arrayResult, array("type" => $item['type'],
"count" => $item['count'])
);
}
echo json_encode($arrayResult);
My problem is as follows, the only time my JS shows any data is when I just print out the data on a successful AJAX call, any attempts at manipulating it fail totally. As in, no data shown at all.
var arrayResult = null;
$.get("../php/displayGraph.php",
function (data) {
arrayResult = (data);
var result = JSON.parse(arrayResult);
$("#results").html(arrayResult);
//$("#results").html(JSON.parse(arrayResult));
}
);
The result of this is:
[{"type":"Entertainment","count":"4"},{"type":"Other","count":"31"},{"type":"Politics","count":"50"},{"type":"Sports","count":"3"},{"type":"Technology","count":"9"}]
I am honestly at a loss in terms of what I even need to do to make it work. And here I thought java was bad with json.
Try like this,
$.get("../php/displayGraph.php",
function (data) {
$.each(data, function (i,item){
console.log(item.type + " === " +item.count);
}
/*arrayResult = (data);
var result = JSON.parse(arrayResult);*/
//$("#results").html(arrayResult);
//$("#results").html(JSON.parse(arrayResult));
}
);
Not sure why, but the following works
$.get("../php/displayGraph.php",
function (data) {
var result = JSON.parse(data);
$("#results").html(data);
console.log(result[1][0].count);
}
);
Certainly is a 2D array the way my php makes it, but i did not think this would be how to do as all the other tutorials i saw never had it like this.
I am relatively new to cake and I am struggling with a custom filter that im making in order to display products based on which checkboxes have been ticked. The checkboxes get populated based on which attributes the user creates in the backend, i then collect all the values of the selected boxes into an array with javascript and post it to the controller, but for some reason I cannot access the controller variable named '$find_tags' in my view, it throughs undefined variable.
Here is my javascript and ajax which collects and posts correctly (when i firebug it 'data' in my controller has array values which im posting) so thats fine
$("#clickme").click(function(event){
event.preventDefault();
var searchIDs = $("#checkboxes input:checkbox:checked").map(function(){
return $(this).val();
}).get();
var contentType = "application/x-www-form-urlencoded";
var data = 'data[ID]='+searchIDs;
$.post("",data,function(data){
console.log(data);
});
});
Here is my controller code which im assuming is where the fault lies
if ($this->request->is('post') ) {
$data = $this->request->data['ID'];
$find_tags = array();
$selected_tags = $data;
foreach($selected_tags as $tag)
{
array_push($find_tags,$this->Product->findByTag($tag));
$this->set('find_tags', _($find_tags));
}
}
And here is my view code where i get Undefined variable: find_tags
foreach($find_tags as $all_tag)
{
echo $all_tag['Product']['name'];
echo '</br>';
}
Any help or suggestions would really be appreciated been struggling with this for a while now
If searchIDs is array of ids you just need to make the json of array and then send to your controller
$("#clickme").click(function(event){
event.preventDefault();
var searchIDs = $("#checkboxes input:checkbox:checked").map(function(){
return $(this).val();
}).get();
var contentType = "application/x-www-form-urlencoded";
var data = 'ids='+JSON.stringify(searchIDs);
$.post("controller url",data,function(data){
console.log(data);
});
});
On php side you are getting wrong variable
if ($this->request->is('post') ) {
$data = $this->request->data['ids'];
$find_tags = array();
$selected_tags = $data;
foreach($selected_tags as $tag)
{
array_push($find_tags,$this->Product->findByTag($tag));
}
$this->set('find_tags', _($find_tags));
}
I am using a service to update a DB table.
myApp.factory('createGal', function ($http, $q)
{
return {
createGal: function ()
{
var deferred = $q.defer();
var newGalleryArray = {};
newGalleryArray.galleryName = 'New Image Gallery';
newGalleryArray.client = 245;
$http.post('/beta/images/create', {newGalleryArray: newGalleryArray}).success(function(data)
{
console.log(data);
deferred.resolve(data);
});
return deferred.promise;
}
};
});
PHP
public function create()
{
print_r($_POST);
}
The array is returning empty. Am i passing the array incorrectly?
Chrome Dev
Thanks
It's been a while since I've used PHP, but doesn't $_POST just contain request paramaters? $http.post sends data through a JSON payload, not request parameters. So, you'll need to use something like json_decode
I'm trying to build an array of data that will then be ajax using post to php - below is my code:
$('#mainBodySaveSubmitButtonProfilePhotoIMG').click(function() {
var profilePhotoArray = [];
$('.mainUnapprovedProfilePhotoWrapperDIV').each(function() {
var action = '';
alert( this.id );
if($('.mainUnapprovedProfilePhotoAttractiveIMG', this).is(':visible')) {
alert('attractive...');
action = 'attractive';
}
else if($('.mainUnapprovedProfilePhotoDeleteIMG', this).is(':visible')) {
alert('delete...');
action = 'delete';
}else{
alert('normal...');
action = 'normal';
}
profilePhotoArray[this.id+'_'+this.id] = action;
});
alert(profilePhotoArray.length);
for (i=0;i<profilePhotoArray.length;i++) {
console.log("Key is "+i+" and Value is "+array[i]);
}
$.post('scripts/ajax/ajax_approval_functions.php', {
'approvalProfilePhotos': '1',
'approvalProfilePhotosData': profilePhotoArray},
function(data) {
alert(data);
});
});
The if, else if, else section works fine as I can see the alerts.
When I try to alert the array length 'profilePhotoArray' it says 0 so I'm not populating the array correctly. Do I need to use .push()? I thought this format was ok?
Also do I need to do anything to the array before sending to php via ajax?
thankyou
** edit - I'm adding "profilePhotoArray[this.id+'_'+this.id] = action;" this.id twice just to prove this words as I will pass a second variable like this... am I better to use JSON for this?
Javascript arrays use numerical index, therefore your storage is failing. Use a javascript Object to store string based keys.
var lang=new Object();
lang["foo"]="Foo";
lang["bar"]="Bar";
I'm having trouble figuring out how to display some return JSON objects.
My script works like this:
I'm making an ajax call, sending some params to a CodeIgniter Controller where I'm processing it with a model, making some queries towards an database and then returning the json_encoded rows to the ajax callback function. This works great btw.
Here is what I want to do now and here its where I'm stuck. I want the new JSON objects (contains database rows) to "replace" the old rows in a html table. So I want it to update the table depending on the params I'm passing but only in the tbody mind.
I'm new at jquery so I've tried i few things. I've tried iterate trough the json data and use the $.html(string) function but i guess this replace everything and it will eventually just display the last object(Am i right?).
So I wonder how in a general sense I would do this?
$.ajax({
type: 'GET',
url: 'someSite.com/someEndpoint'
data: xyz.
success: function( response ) {
//lets say you have an object like this: object = { data: { ... } }
var html = '';
for(var i = 0; i<response.data.length; i++) {
html += '<tr><td>'+response.data[i].title+'</td></tr>';
}
$('#someTable tbody').html(html);
}
});
You don't have to return JSON objects in an AJAX request. Try setting the data_type config setting for the $.ajax call to "html" (or leave it blank--jQuery is really good about figuring it out from the response data).
I usually factor out the <tbody>...</tbody> portion of a view to its own view partial. Then, the "original" page load can use it, and so can an updating AJAX call.
The only asterisk to this is if you need some sort of object-oriented response along with the HTML. I would usually do something like this:
{
"stat": "ok",
"payload": "<tr><td>row1</td></tr><tr><td>row2</td></tr>"
}
And then in the ajax success function:
$.post('/controller/action', { some: 'data' }, function(response) {
$('#my_table tbody').append(response.payload);
}, 'json');
What are the params your passing in?
for example you might use a select or input field to trigger an ajax call and pass its value as the param.
var tableObj = {
var init : function(){
//check that your selectors id exists, then call it
this.foo();
},
foo : function(){
var requestAjax = function(param){
var data = {param : param}
$.ajax({
data : data,
success : function(callback){
console.log(callback);//debug it
$("tbody").empty();//remove existing data
for(var i =0; i < callback.data.length; i++){}//run a loop on the data an build tbody contents
$("tbody").append(someElements);//append new data
}
});
}
//trigger event for bar
$("#bar").keyup(function(){
requestAjax($(this).val());
});
}
}
$(function(){
tableObj.init();
})
Your php method
public function my_method(){
if($this->input->is_ajax_request())
{
//change the output, no view
$json = array(
'status' => 'ok',
'data' => $object
);
$this->output
->set_content_type('application/json')
->set_output(json_encode($json));
}
else
{
show_404();
}
}